ENGR_400_Module_1_Assignment

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Embry-Riddle Aeronautical University *

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400

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Electrical Engineering

Date

Jan 9, 2024

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docx

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Jason L. Wilson 10/21/2023 ENGR 400 - Module 1 Chapter 8 - Three-Phase Systems 8.1 A Y-connected balanced three-phase source feeds a balanced three-phase load. The voltage and current of the source coil are: v(t) = 340sin(377t+0.5236) V i(t) = 100sin(377t+0.87266) A Calculate the following: a. The rms phase voltage: V rms ( phase ) = 340 2 V rms ( phase ) = 240.42 V b. The rms line-to-line voltage: V rms ( line line ) = 240.42 3 V rms ( phase ) = 416.42 V c. The rms current in the source: I rms ( source ) = I rms ( phase ) = 100 2 I rms ( source ) = 70.71 A d. The rms current in the transmission line: I rms ( transmission ) = 70.71 A e. The frequency of the supply: F = w 2 π F = 377 2 π
Jason L. Wilson 10/21/2023 F = 60 Hz f. The power factor at the source side, state leading or lagging: θ = 0.87266 0.5236 θ = 0.34906 ( 180 π ) θ = 20 ° λ = cos ( 20 ° ) λ = 0.9397 leading g. The three-phase real power delivered to the load: P = 3 V rms ( phase ) I rms ( phase ) cos ( θ ) P = 3 416.42 70.71 0.9397 P = 47.925 kW h. The three-phase reactive power delivered to the load: Q = ¿ 3 V rms ( phase ) I rms ( phase ) sin ( θ ) Q = 3 416.42 70.71 sin ( 20 ) Q =− 17.443 kVAR i. If the load is connected in delta configuration, calculate the load impedance: V rms ( line ) = 3 V rms ( phase ) 30 ° ¿ ( 3 30 ° )( 340 30 ° ) V rms ( line ) = 588.89 60 ° V I phase Δ = I rms ( phase ) 3 30 ° ¿ 100 50 ° 3 30 °
Jason L. Wilson 10/21/2023 I phase Δ = 57.74 80 ° A Z Δ ( phase ) = V rms ( phase ) Δ I rms ( phase ) Δ ¿ 588.89 60 ° 57.74 80 ° A Z Δ ( phase ) = ( 9.58 j 3.49 ) Ω 8.3 A three-phase, 480 V system is connected to a balanced three phase load. The transmission line current I a is 10 A and is in phase with the line-to-line voltage V bc . Calculate the impedance of the load for the following cases: a. If the load is wye-connected: V ab = 480 0 ° i a = 10 120 ° V ab = 3 V an V an = V ab 3 V an = 480 0 ° 3 30 ° V an = 277.13 30 ° Z a = 277.13 30 ° 10 120 ° Z a = 27.71 90 ° Ω b. If the load is delta-connected: i a = 3 i pha i pha = i a 3
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