1) Treatment groupn₁ = 50x1 = 7.00Placebo groupS₁ = 1.00n2 = 100x2 = 6.00S2 = 2.00Test the claim that the two samples come from populations with the same mean.Use a = .05.Draw it:Conclusion (full sentence):Ho=HA=Calculated valep-valueDecisionFind the 95% confidence interval for the difference between the two population meansto the nearest hundredth.

The objective of this question is to test the claim that the two samples come from populations with…

Answered: 1) Treatment group n₁ = 50 x1 = 7.00…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Consider the following results for two independent random samples taken from two populations. Sample 1 Sample 2 n1=50 n1=30 xbar1=13.6 xbar=11.1 pop mean 2.1 pop mean=3 What is the point estimate of the difference between the two population means? (to 1 decimal) Provide a 90 confidence interval for the difference between the two population means (to 2 decimals).( , ) Provide a 95 confidence interval for the difference between the two population means (to 2 decimals).( , )
A random sample of male and female employees selected from a large industrial plant yielded the followinghourly wage results (in Rands):Male Femalen1 = 45 n2 = 32x1 = 6.00 x2 = 5.75s1 = 0.95 s2 = 0.75Question 1Calculate the difference in the sample means (rounded off to two decimals)? Question 2Construct and explain a 99% confidence interval for the difference between the population mean hourlywages for all male and female employees (rounded off to four decimals). Question 3Is there a significant difference in the two population means, considering the confidence interval found inQuestion 2?
Consider the following results for two independent random samples taken from two populations. Sample 1 Sample 2 n 1 = 50 n 2 = 30 x 1 = 13.5 x 2 = 11.6 σ 1 = 2.5 σ 2 = 3 What is the point estimate of the difference between the two population means? (to 1 decimal) Provide a 90% confidence interval for the difference between the two population means (to 2 decimals). Use z-table.( , ) Provide a 95% confidence interval for the difference between the two population means (to 2 decimals). Use z-table. If your answer is negative, enter minus (-) sign.( , )
According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this proportion is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. Calculate a 95% confidence interval for the difference between the proportions of Californians and Oregonians who are sleep deprived and interpret it in context of the data.
A sample of size 12 drawn from a normally distributed population has a sample mean 38.7 and a sample standard deviation 14.9. Construct a 99.9% confidence interval for the population mean.
A 30 month study is conducted to determine the difference in rates of accidents per month between two departments in an assembly plant. If a sample of 12 from the first department averaged 12.3 accidents per month with a standard deviation of 3.5, and a sample of 9 from the second department averaged 7.6 accidents per month with standard deviation of 3.4, find: The 95% confidence interval between the difference in rates between the two departments (round off to four decimal places) is: A. [2.9782; 6.4218] B. [1.5083; 7.8917] C. [2.9782; 7.8917] D. [1.5083; 6.4218] E. None of the preceding
According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this percent is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. Suppose we want to calculate a 99% confidence interval for the difference between the proportions of Californians and Oregonians who are sleepdeprived. 1. State the critical value for the interval (3 decimal places): 2. State the difference between the sample proportions, POregon-PCalifornia (3 decimal places): 3. State the standard error of the difference between the proportions (3 decimal places): 4. State the confidence interval being sure to use proper notation (3 decimal places each):
A 90 percent confidence interval is to be created to estimate the proportion of television viewers in a certain areawho favor moving the broadcast of the late weeknight news to an hour earlier than it is currently. Initially, theconfidence interval will be created using a simple random sample of 9,000 viewers in the area. Assuming that thesample proportion does not change, what would be the relationship between the width of the original confidenceinterval and the width of a second 90 percent confidence interval that is created based on a sample of only 1,000viewers in the area?(A) The second confidence interval would be 9 times as wide as the original confidence interval.(B) The second confidence interval would be 3 times as wide as the original confidence interval.(C) The width of the second confidence interval would be equal to the width of the original confidence interval.(D) The second confidence interval would be 1/3 as wide as the original confidence interval.(E) The second…
According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this proportion is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. Calculate a 95% confidence interval for the difference between the proportions of Californians and Oregonians who are sleep deprived and interpret it in context of the data. Also, conduct a hypothesis, with alpha = 0.05, test to determine if these data provide strong evidence the rate of sleep deprivation is different for the two states. Construct a 95% confidence interval Which of the following correctly displays the standard error? 0.0046 0.009 0.001 0.00002 0.008
A 30 month study is conducted to determine the difference in rates of accidents per month between two departments in an assembly plant. If a sample of 12 from the first department averaged 12.3 accidents per month with a standard deviation of 3.5, and a sample of 9 from the second department averaged 7.6 accidents per month with standard deviation of 3.4. The 95% confidence interval between the difference in rates between the two departments (round off to three decimals) is:
According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this proportion is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. Using Rguroo, and the Large Sample Z method, calculate a 95% confidence interval for the difference between the proportions of Californians and Oregonians who are sleep deprived. Round your answers to 4 decimal places.
Independent studies show that the everage salary of 38 r/s woman with a PhD degree is 90.2 K$ with standart deviation 10.8 K, while the average and the standart deviation of 33 r/s men with a PhD degree are 92.6 K$ and 8.37 K$. Construct a 90% confidence interval for the difference between the overall average sallaries of women and men, respectively, with a PhD degree.

SEE MORE QUESTIONS

Recommended textbooks for you

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

Elementary Statistics: Picturing the World (7th E…

Statistics

ISBN:

9780134683416

Author:

Ron Larson, Betsy Farber

Publisher:

PEARSON

The Basic Practice of Statistics

Statistics

ISBN:

9781319042578

Author:

David S. Moore, William I. Notz, Michael A. Fligner

Publisher:

W. H. Freeman

Introduction to the Practice of Statistics

Statistics

ISBN:

9781319013387

Author:

David S. Moore, George P. McCabe, Bruce A. Craig

Publisher:

W. H. Freeman

SEE MORE TEXTBOOKS