5'GGT ACG TTG GGG CTC CAT3' This sequence is transcribed and translated. If the G that is underlined changes to to a C the result will be A) A nonsenese mutation. B) A frameshift mutation C) A silent substitution. D) A missense mutation
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- Based on the following wild type DNA sequence, indicate if each of the mutations should be classified as : insertion, deletion, missense, nonsense, silent (Use the provided Genetic Code table and remember you have been given DNA sequence). Wild Type: 5’ ATG GCT AGA GTC GAG TTG 3’ Mutant 1: 5’ ATG GCA GAG TCG AGT TG 3’ Mutant 2: 5’ ATG GCT TGA GTC GAG TTG 3’ Mutant 3: 5’ ATG GCT AGA GTT GAG TTG 3’ Mutant 4: 5’ ATG GCT AGA AGT CGA GTT G 3’ Mutant 5: 5’ ATG GCT AGA ATC GAG GTT 3’Met – Asn – Cys – Phe – Glu – Met – Leu – Arg – Ile – Asp – Glu – Gly – Leu – Arg – Leu – Lys – Ile – Tyr – Lys – Asp mRNA sequence (5’-3’)AUG – AAC – UGU – UUU – GAA – AUG – CUU – CGU – AUU – GAU – GAA – GGU – CUU – CGU – CUU – AAA – AUU – UAU – AAA – GAU - Write the dsDNA that encodes for this peptideThe following sequence represents the dsDNA code for a short peptide 5' -CTT TCC CAT CAC CGC ATG CAT CCT CCC TCC TTT CTT TAA TAT TGG-3' 3'-GAA AGG GTA GTG GCG TAC GTA GGA GGG ACC AAA GAA ATT ATA ACC-5' Transcribe the DNA strand given above to write the sequence of the mRNA strand in the 5’ to 3’ direction. (1) Use the table and write the sequence of the resulting peptide. (1) Is it possible for a codon to code for another amino acid? (1) What will be the effect if a mutation changes the codon UAU to UAA? (1) What is a reading frame? (1) If you are given a nucleotide sequence, how would you find Open Reading Frames? (1) DISCUSS the reason why there are leading and lagging strands in replication?
- A gene contains the sequence CGCATACGGTAC that results in the amino acid sequence arg-ile-arg- tyr. A mutation in this gene has a G inserted after the second C in the strand. How will this mutation affect the phenotype? A:This will affect the phenotype because although most of the protein will be identical, the first amino acid will be different. B:This will not affect the phenotype because only the second amino acid is different from the original protein. C:This will not affect the phenotype because the protein will be identical to the original protein. D:This will affect the phenotvpe because all of the amino acids after the first one will be different from he original protein.DNA Sequence: TAC TCC GGC TCT CCC AGT TGA ACT Mutated Sequence: TAC TCG GCT CTC CCA GTT GAA CT Original Amino acid: Mutated Amino Acid: What mutation have occurred in the sequence? How does it affect the expression of amino acids? 2. DNA Sequence: TAC TCC GGC TCT CCC AGT TGA ACT Mutated Sequence: TAC TCT GGC TCT CCA AGT TGA ACT Original Amino acid: Mutated Amino Acid: What mutation has occurred in the sequence? How does it affect the expression of amino acids? 3. DNA Sequence: TAC TCC GGC TCT CCC AGT TGA ACT Mutated Sequence: TAC TCC GGC TCT CCC ACT TGA ACT Original Amino acid: Mutated Amino Acid: What type of mutation has occurred in the sequence? How does it affect the expression of amino acids? 4. DNA Sequence: TAC TCC GGC TCT CCC AGT TGA ACT Mutated Sequence: TAC TCC GGC TCG CCC ACT TGA ACT Original Amino acid: Mutated Amino Acid: What of mutation mutation has occurred in the sequence? How…The genetic code consists of a series of three-base wordsthat each code for a given amino acid.(a) Using the selections from the genetic code shown below, de-termine the amino acid sequence coded by the following seg-ment of RNA: UCCACAGCCUAUAUGGCAAACUUGAAG AUG= methionine ;CCU= proline; CAU= histidine ;UGG= tryptophan AAG= lysine ; UAU= tyrosine ;GCC= alanine ;UUG= leucine ;CGG= arginine ;UGU= cysteine ;AAC =asparagine ;ACA=threonine ;UCC= serine ;GCA=alanine ;UCA=serine(b) What is the complementary DNA sequence from which this RNA sequence was made? (c) If you were sequencing the DNA fragment in part (b), how many complementary chain pieces would you obtain in the tube containing ddATP?
- The following are DNA fragments containing a small gene. The top strand is the coding strand. Transcribe all groups and translate. FIND THE POSSIBLE MUTATIONS Group D 5’-GGCAATGGGTTTGTGCAATTCTAACAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACGTTAAGATTGTCAAAAATTAAG-5’ Group E 5’-GGCAATGGGTTTTGCAATTCTAAAAGTTTTTAATTC-3’ 3’-CCGTTACCCAAAACGTTAAGATTTTCAAAAATTAAGCTA GCC CTC CGT TAC TAG TTA CCT ACT TAT TCA ATT TTG TAA ACG CTC ATC CGA ACC CGC TTT TAA TTG CCC ACT TAG TCG ATT ACC CGT TTA TGT TAA TTA CCT ATC 1. Build the mRNA molecule matching the RNA nucleotides to the DNA nucleotides properly letter by letter. (assume that the mRNA is bacterial there are not intros to cut out)Normal DNA: TGC GTG CTT AAG CGG TGT ACA CGT TGC mRNA: Animo Acid: 1st Mutation TGC GTG CTT AAG CGA TGT ACA CGT TGC mRNA: Animo Acid: Do you think it will affect the protein’s function? Why? 2nd Mutation TGC GTG CTT AAG CGG TGT GCA CGT TGC mRNA: Animo Acid: What kind of mutation is this? Do you think it will affect the protein’s function? Why?
- A gene contains the sequence CGCATACGGTAC that results in the amino acid sequence arg-ile-arg-tyr. A mutation in this gene removes the first G in the strand.What is true of this mutation's effect on the phenotype?1.It will affect the phenotype because although most of the protein will be identical, the first amino acid will be different.2.It will not affect the phenotype because the protein will be identical to the original protein.3.It will affect the phenotype because all the amino acids past this point will be different from the original protein.4.It will not affect the phenotype because only the first amino acid is different from the original protein.Identify the dinucleotide CA repeat region and the score in the following sequence:TGGCACACTCACACCACACAGACAGTTAFor the following sequence design the forward and reverse primer... explain and justify your answer. Gene of Interest: a tgaaacaaca aaaacggctt tacgcccgat tgctgacgct gttatttgcg 61 ctcatcttct tgctgcctca ttctgcagca gcggcggcaa atcttaatgg gacgctgatg 121 cagtattttg aatggtacat gcccaatgac ggccaacatt ggaagcgttt gcaaaacgac 181 tcggcatatt tggctgaaca cggtattact gccgtctgga ttcccccggc atataaggga 241 acgagccaag cggatgtggg ctacggtgct tacgaccttt atgatttagg ggagtttcat 301 caaaaaggga cggttcggac aaagtacggc acaaaaggag agctgcaatc tgcgatcaaa 361 agtcttcatt cccgcgacat taacgtttac ggggatgtgg tcatcaacca caaaggcggc 421 gctgatgcga ccgaagatgt aaccgcggtt gaagtcgatc ccgctgaccg caaccgcgta 481 atttcaggag aacacctaat taaagcctgg acacattttc attttccggg gcgcggcagc 541 acatacagcg attttaaatg gcattggtac cattttgacg gaaccgattg ggacgagtcc 601 cgaaagctga accgcatcta taagtttcaa ggaaaggctt gggattggga agtttccaat 661 gaaaacggca actatgatta tttgatgtat gccgacatcg attatgacca tcctgatgtc 721 gcagcagaaa ttaagagatg gggcacttgg tatgccaatg…