9. Let Zs is a ring of integers mod 5 and f(x)eZ,(x) such that f(x) = x²+x+1, then: Zs a) f(x) is a field. b) f(x) has only two roots. c) f(x) has more than two roots. d) No one of the above. 55 4
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- Let ab in a field F. Show that x+a and x+b are relatively prime in F[x].Since this section presents a method for constructing a field of quotients for an arbitrary integral domain D, we might ask what happens if D is already a field. As an example, consider the situation when D=5. a. With D=5, write out all the elements of S, sort these elements according to the relation , and then list all the distinct elements of Q. b. Exhibit an isomorphism from D to Q.. a. Let, and . Show that and are only ideals of and hence is a maximal ideal. b. Show that is not a field. Hence Theorem is not true if the condition that is commutative is removed. Theorem 6.22 Quotient Rings That are Fields. Let be a commutative ring with unity, and let be an ideal of . Then is a field if and only if is a maximal ideal of .
- Prove that if F is an ordered field with F+ as its set of positive elements, then F+nen+, where e denotes the multiplicative identity in F. (Hint: See Theorem 5.34 and its proof.) Theorem 5.34: Well-Ordered D+ If D is an ordered integral domain in which the set D+ of positive elements is well-ordered, then e is the least element of D+ and D+=nen+.Prove that if R and S are fields, then the direct sum RS is not a field. [Type here][Type here]22. Let be a ring with finite number of elements. Show that the characteristic of divides .