An electric field is given as E=x(y+1)+y(z−1)+22 Verify that the field is indeed an electrostatic field by examining its curl VxE. It is found that VxE=0

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
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Hello, I am doing some practice and I am getting hung up on my cross product derivation. I know it is supposed to be zero, but I want to prove it with the math. Could you help me out with this?

Thank you for your time and effort, I appreciate the help. 

Please see attached for probelm. 

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An electric field is given as
E = x(y+1) +ŷ(x − 1) +22
Verify that the field is indeed an electrostatic field by examining its curl
VxE. It is found that VxE=0
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Transcribed Image Text:✓ ↑ → + docs.google.com/document/d/1FS5FFcLvPKLjsnbDz0de817GtLJs1spWAX0p08DjhuQ/edit Untitled document - Google Do IT ☑ ☑ 0 ☐ An electric field is given as E = x(y+1) +ŷ(x − 1) +22 Verify that the field is indeed an electrostatic field by examining its curl VxE. It is found that VxE=0 Cloudy Search 29°F Σ | 0 ☑ Finish update: 10:19 AM 3/16/2024 PRE
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