Common aluminum foil for household use is nearly pure aluminum. A box of this product at a local supermarket is advertised as giving 75 A'of material (in a roll 304 mm wide by 22.8 m long). If the foil is 0.5 mil (12.7 µm) thick, calculate the number of atoms of aluminum in the roll. Given: Density of Aluminum: p= 2.7 Mg/m Molar mass of Aluminum: MAI= 26.98 g/mol Avogadro's Number: AN =0.6203 (10)ª

Elements Of Electromagnetics
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Common aluminum foil for household use is nearly pure aluminum. A box of this product at
a local supermarket is advertised as giving 75 ft°of material (in a roll 304 mm wide by 22.8 m
long). If the foil is 0.5 mil (12.7 µm) thick, calculate the number of atoms of aluminum in the
roll.
Given:
Density of Aluminum: p= 2.7 Mg/m³
Molar mass of Aluminum: MAI= 26.98 g/mol
Avogadro's Number: AN = 0.6203 (10)²ª
Transcribed Image Text:Common aluminum foil for household use is nearly pure aluminum. A box of this product at a local supermarket is advertised as giving 75 ft°of material (in a roll 304 mm wide by 22.8 m long). If the foil is 0.5 mil (12.7 µm) thick, calculate the number of atoms of aluminum in the roll. Given: Density of Aluminum: p= 2.7 Mg/m³ Molar mass of Aluminum: MAI= 26.98 g/mol Avogadro's Number: AN = 0.6203 (10)²ª
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