How do I write this in C programming? I need help with the code. int isOpen(char move[THREE], char board[ROW][COL]) { int open = FALSE; int rowInt = getMoveRow(move); int colInt = getMoveCol(move); open = TRUE return open;
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How do I write this in C
I need help with the code.
int isOpen(char move[THREE], char board[ROW][COL])
{
int open = FALSE;
int rowInt = getMoveRow(move);
int colInt = getMoveCol(move);
open = TRUE
return open;
}
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- 3. Implement a function called findLargestIndex which returns the index of the rowwith the largest sum.ex. int array[3][6] = {{3, 6, 8, 2, 4, 1}, // sum = 24{2, 4, 5, 1, 3, 4}, // sum = 19{1, 0, 9, 0, 1, 0}}; // sum = 11If the findLargestIndex function was called using this array, it would return 0, asit is returning the index of the row, not the sum.Note that the number of columns is required when passing a 2d array to a function.Assume that 2D arrays passed to this function will have 6 columns.Title line: int findLargestIndex(int array[][6], int rows, int columns);create an array of 30 random numbers that range between 1and 100. And yet again, write a function that will receive a number from the userand determine if that number exists in the array or not. But this time, start bySORTING your input list. After a sort, the list in problem 1 is as follows:[2, 2, 3, 5, 12, 14, 14, 15, 23, 36, 39, 41, 44, 44, 45, 48,49, 50, 52, 52, 59, 71, 81, 82, 88, 89, 89, 93, 96, 97] Approach: Implement a method called findC(x, A, i, j), where x is the number we arelooking for in array A, the first index of the array is i and the last index is j. We wantto determine whether x exists in A anywhere between index i and index j. Your firstcall to this method will therefore look like this: findC(x, A, 0, A.length-1). In the body of your function, compare x with the item that is in the middle of thearray, as you did before. As before, call the middle of index of the array mid. But thistime, if x<=a[mid], recursively call your function to search ONLY the first half of…Implement the following function without using any additional data structure, and without sorting the input vectors. /* Given two vectors of integers, check if the two vectors contain same set of values: e.g., V1=[3,4,10,4,10,11] and V2=[3,3,4, 11, 10] stores same set int: {3, 4, 10, 11}. Note that duplicates are removed when considering set */ @param list1, list2: two vectors of integers@pre: list1, list2 have been initialized@post: return true if list1 and list2 stores same values (in same or different order); return false, if not. */ bool SameSet (const vector<int> & list1, const vector<int> & list2) {//for each value in list1, check if it appears in list2, if not, return false //for each value in list2, check if the value appears in list1, if not return false //return true}
- Please help me with this: using js create an array of 30 random numbers that range between 1and 100. And yet again, write a function that will receive a number from the userand determine if that number exists in the array or not. But this time, start bySORTING your input list. After a sort, the list in problem 1 is as follows:[2, 2, 3, 5, 12, 14, 14, 15, 23, 36, 39, 41, 44, 44, 45, 48,49, 50, 52, 52, 59, 71, 81, 82, 88, 89, 89, 93, 96, 97] Approach: Implement a method called findC(x, A, i, j), where x is the number we arelooking for in array A, the first index of the array is i and the last index is j. We wantto determine whether x exists in A anywhere between index i and index j. Your firstcall to this method will therefore look like this: findC(x, A, 0, A.length-1). In the body of your function, compare x with the item that is in the middle of thearray, as you did before. As before, call the middle of index of the array mid. But thistime, if x<=a[mid], recursively call your…6. Read in two integers n and m (n, m < 50). Read n integers in an array A. Read m integers in anarray B. Then do the following (write separate programs for each, only the reading part iscommon).a) Find if there are any two elements x, y in A and an element z in B, such that x + y = z.b) Copy in another array C all elements that are in both A and B (intersection).c) Copy in another array C all elements that are in either A and B (union).d) Copy in another array C all elements that are in A but not in B (difference).Do In c Program3) A function is implemented with a feature to print a line when x is found in the array A. def better_linear_search(A, x): for i in range(len(A)): if A[i] == x: print(x,"found at",i) return i return -1 What is the output after running code below? better_linear_search([17, 2, 10, 3], 10) better_linear_search([0, 9, 9, 9], 18) better_linear_search([12, 8, 7, 8], 8).
- Create two Arrays A with 10 unsorted integer elements and B with 10 unsorted floatelements. Find the largest element in A and B and then sum both of them calling afunction SumAB() by reference. Sort A and B and then call another function StichAB()to merge B with A. Be careful about memory leakage.TROUBLESHOOT my PYTHON code, please :) The code of a sequential search function is shown on textbook page 60. In fact, if the list is already sorted, the search can halt when the target is less than a given element in the list. For example, given my_list = [2, 5, 7, 9, 14, 27], if the search target is 6, the search can halt when it reaches 7 because it is impossible for 6 to exist after 7. Define a function linearSearchSorted, which is used to search a sorted list. This function displays the position of the target item if found, or 'Target not found' otherwise. It also displays the elements it has visited. To test your function, search for these targets in the list [2, 5, 7, 9, 14, 27]: 2, 6, 14, 27 and 28. Expected output: List: [2, 5, 7, 9, 14, 27] Search target: 2 Elements visited: 2 Target found at position 0 Search target: 6 Elements visited: 2 5 7 Target not found Search target: 14 Elements visited: 2 5 7 9 14 Target found at position 4 Search target: 27 Elements visited: 2…Write a function is ordered that takes an integer array and its size as parameters and returns true if the array elements are ordered in nondecreasing order and returns false if not. For example, integers in {10,0,1,1,5,1009} are ordered in nondecreasing order. On the other hand, integers in {1, 2, 3, 8, 4, 19} are not since 8 > 4
- Write C++ program, you will work on inserting, searching and how many comparisons are needed for that searching on a 5X5 board. Complete the countingNumOfComparison() function that counts the number of comparisons that are done in binary search. We don't use a board array in this problem. The function countingNumOfComparison() gets candidateWord and string vector dictionary as parameters and doing binary search. You have to fill up the code in which how many comparisons are needed for searching candidateWord in dictionary. Sample: Enter the word :world The item is found and the number of comparisons : 32. Implement a function called findMinGap that will return the smallest gap betweenadjacent entries of an integer array. A gap between two numbers is the absolutevalue of their difference. For example, if an array contains the elements {10, 14,-5, -3, 0, 5, 7}, the minimum gap is 2 (between -5 and -3).Title line: int findMinGap(int array[], int length)Create a function append(v, a, n) that adds to the end of vector v a copy of all the elements of array a. For example, if v contains 1,2, 3, and a contains 4, 5, 6, then v will end up containing 1, 2, 3, 4, 5,6. The argument n is the size of the array. The argument v is a vector ofintegers and a is an array of integers. Write a test driver.