Unused catch (InputMismatch Exception excpt) { System.out.println("Fatal error"); askFor Input= false; } catch (Exception excpt) { System.out.println(excpt.getMessage()); askForInput = true; } System.out.println(excpt.toString()); System.out.println(excpt);
Unused catch (InputMismatch Exception excpt) { System.out.println("Fatal error"); askFor Input= false; } catch (Exception excpt) { System.out.println(excpt.getMessage()); askForInput = true; } System.out.println(excpt.toString()); System.out.println(excpt);
Chapter11: Exception Handling
Section: Chapter Questions
Problem 1CP
Related questions
Question
Put unused code in the right order
Transcribed Image Text:Unused
catch (InputMismatch Exception excpt) {
System.out.println("Fatal error");
askForInput = false;
}
catch (Exception excpt) {
System.out.println(excpt.getMessage());
askForInput
}
=
true;
System.out.println (excpt.toString());
System.out.println (excpt);
![The following program simulates a vending machine panel. The program gets an integer that represents the user's selected item,
and then outputs a dispensing message. Only 8 items are for purchase. Ex: The input 2 results in the message "Dispensing item
2".
Arrange the following lines to handle two exceptions. If the user enters an item number that is not for purchase, the program
throws an Exception with the message "Try again", outputs the exception message, and then tries again. If the user enters a non-
integer input, the program throws an Input Mismatch Exception, outputs "Fatal error", and then exits.
Not all lines are used in the solution.
How to use this tool
Unused
catch (InputMismatch Exception excpt) {
System.out.println("Fatal error");
askForInput
=
false;
}
catch (Exception excpt) {
System.out.println(excpt.getMessage());
}
askForInput = true;
System.out.println(excpt.toString());
System.out.println(excpt);
Vending Machine.java
public static void main (String[] args) {
Scanner scnr = new Scanner(System.in);
int itemNumber = 0;
boolean askFor Input = true;
}
while (askForInput) {
try {
}
}
Load default template...
itemNumber = scnr.nextInt ();
if ((itemNumber <= 0) || (itemNumber > 8)) {
throw new Exception ("Try again");
}
System.out.println("Dispensing item " + itemNumbe
askFor Input = false;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0cc153ae-b205-4fb2-9991-7cf6a21d5016%2F4ce82dbe-afae-474d-8a7d-08abaebf1ccc%2Fk9lxr4a_processed.png&w=3840&q=75)
Transcribed Image Text:The following program simulates a vending machine panel. The program gets an integer that represents the user's selected item,
and then outputs a dispensing message. Only 8 items are for purchase. Ex: The input 2 results in the message "Dispensing item
2".
Arrange the following lines to handle two exceptions. If the user enters an item number that is not for purchase, the program
throws an Exception with the message "Try again", outputs the exception message, and then tries again. If the user enters a non-
integer input, the program throws an Input Mismatch Exception, outputs "Fatal error", and then exits.
Not all lines are used in the solution.
How to use this tool
Unused
catch (InputMismatch Exception excpt) {
System.out.println("Fatal error");
askForInput
=
false;
}
catch (Exception excpt) {
System.out.println(excpt.getMessage());
}
askForInput = true;
System.out.println(excpt.toString());
System.out.println(excpt);
Vending Machine.java
public static void main (String[] args) {
Scanner scnr = new Scanner(System.in);
int itemNumber = 0;
boolean askFor Input = true;
}
while (askForInput) {
try {
}
}
Load default template...
itemNumber = scnr.nextInt ();
if ((itemNumber <= 0) || (itemNumber > 8)) {
throw new Exception ("Try again");
}
System.out.println("Dispensing item " + itemNumbe
askFor Input = false;
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