QUESTION 1 Figure Q1 shows a frame structure that is connected to a cable with a tension force of 150 N. Determine the resultant internal loadings acting on the cross section at points E and F of the frame. 3 m 1 m I m F 100 N/m B E -2 m- -2 m- 1 m 1 m 30° Figure Q1 150 N
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- The assembly is subjected to a tension force P = 2500 N. If these cables are arranged in a parallel assembly as shown, determine the stress of each cable. Cable Length (m) Area (sq. mm.) E (GPa) A 1.4 30 50 B 1.0 10 80 C 1.2 8 603. At temperature T₁, the two rigidly connected rods just fit the rigid supports. If both sections are identical except for the diameter, prove that the following equations are true when temperature rises to T₂. a. F= b. OAB C. OBC A x(T₂-T₁)лd²E 20 x(T₂-T₁)E 5 9x(T₂-T₁)E 5 -1/2- d B 1/12- d CQ2/ Use the unit load method to find the slope and the horizontal displacement of point C on the frame shown below. E=200 GPa, I=200 x 10 mm 5 m B C 4 KN El 2 kN/m 6 m 1.5 EI A-
- 1-1 Determine the resultant internal normal force acting on the cross section through point A in each column. In (a), segment BC weighs 180 lb/ft and segment CD weighs 250 lb/ft. In (b), the column has a mass of 200 kg/m. 5 kip |8 kN B 200 mm 200 mm 6 kN| 6 kN 10 ft 8 in. 3 m 8 in. 200 mm 200 mm 3 kip 3 kip 4.5 kN 14.5 kN C 4 ft A A 4 ft I m D (а) (h)F2 F1 Figure (4) 200 For figure (4): The ring is subjected to two forces (F1 and F2). Suppose that the resultant force has the value of 225 N and it is located downward in the third quart at angle 40° measured from the y-axis. Set 0 = 30° , ß = 80°. em 11- What is the value of the force F1? 1312 - A00 A= 50° B=70%Determine the internal resisting forces and mo- ment transmitted by section aa in the bracket shown in Fig. 125 mm -375 mm 60° B 250 mm 300 N 30°
- A weight W = 905 lb is held up by two cables each with a diameter of 1.5 in. Determine the tension in each cable and the normal stress in each cable. 0 = 21° O = 37° B Image is not drawn to scale.The beam supports the triangular distributed load shown below with max = 510 lb/ft. The reactions at A and B are vertical. Part A Determine the resultant internal loadings on the cross section at point C. Express your answers, separated by commas, to three significant figures. Nc, Vc , Mc = Submit SHADE Request Answer 6 ft .. - D 6 ft . x C -6 ft W TR 130 E 4.5 ft 4.5 ft for Part A for Part A for Part A for Part A ndo for Part redo for Part A reset for Part A keyboard shortcuts for Part A help for Part A kip, kip, kip-ftIf the tension in cable DE is 455 N, determine the moments of this tensile force (as it acts at point D) about point O and about line OF. EQ 2.3 m Answers: BC=CD = 2.2 m MOF= 3.0 m Moi -1203.39 i 2.3 m 3.1 m 1.3 m i+ i N.m 1.7 m 39° j+ i k) N-m
- The bell crank is in equilibrium for the forces acting in rods (1) and (2). The bell crank is supported by a pin with a diameter of 14 mm at B that acts in single shear. The thickness of the bell crank is 7 mm. Assume a = 60 mm, b = 100 mm, F₁ = 1000 N, and 9 = 75°. Determine the average shear stress in pin B. Answer in MPa rounded-off to 2 decimal places. Bell crank (2) mDetermine the force in each member of the loaded truss. The forces are positive if in tension, negative if in compression. Part 1 B AD 50° CD AD = Correct Answers: CD= 3.1 m The Free-Body diagram for joint Dis drawn assuming that all internal forces are in tension. Solve for the forces in AD and CD. The forces are positive if in tension, negative if in compression. 50% 50 6.2 m -3020.7586 3600 N 4699.4662 D 50° D N 3600 N NA cable with supports at the same elevation has a span of 400 m. The cable supports a uniformly distributed load of 6 kN/m along the horizontal. The maximum ten- sion in the cable is 5000 kN. Determine The angle between the cable and the horizontal at a support.