Please help me with this question on matrices.
We first find A2, for which we multiply A with itself. We perform matrix multiplication in which we multiply rows of first matrix with columns of second matrix element by element and add.
Let us now find 3A, for which multiply each element of A by 3.
Now, to find 2I we consider the identity matrix of order 3x3 and multiply its each element by 2. We take order 3x3 to match with the order of A2 and 3A.
To find A2–3A+2I, consider all three matrices obtained in previous steps and add/subtract them.
Answer: The value of A2–3A+2I is: