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Need answer to the following question.

We first find the slope of the tangent for which we need **derivative** of **f(x)**. Differentiating **f(x)** w.r.t. **x** we get:

Now, slope is the value of **f’(x)** at the given point **x = 1**.

Now, to find any one point on the tangent line, we consider the fact that tangent line is drawn at **x=1**. This point also lies on the curve and hence its y-coordinate is the value of **f(x)** at **x=1**. We get:

Equation of a line in slope-point form is given as, **(y **–** y _{1}) = slope * (x **–

**Answer:** The equation of tangent line to the given curve at **x = 1** is: