Sample Solution from
Fluid Mechanics (2nd Edition)
2nd Edition
ISBN: 9780134649290
Chapter 1
Problem 1P
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a)

To determine

Correct SI form of mmMN.

Expert Solution

Explanation of Solution

Given:

mmMN

Calculation:

Convert the quantities.

  mmMN=(1 mm×1 m103mm)(1MN×(103)kN1 MN)mmMN=1(103)m(103)kN=kNm

Thus, the correct SI form for mmMN is kNm_.

b)

To determine

Correct SI form of Mg/mm.

Expert Solution

Explanation of Solution

Given:

Mg/mm

Calculation:

Convert the quantities.

  Mg/mm=(Mg×1 Gg103 Mg)/((1 mm×1 m103mm))=103Gg103m=Gg/m

Thus, the correct SI form for Mg/mm is Gg/m_.

c)

To determine

Correct SI form of km/ms.

Expert Solution

Explanation of Solution

Given:

km/ms

Calculation:

Convert the quantities.

  km/ms=(1 km×1 Mm103 km)/((1 ms×1 s103ms))=103Mm103s=Mm/s

Thus, the correct SI form for km/ms is Mm/s_.

d)

To determine

Correct SI form of kN/mm2.

Expert Solution

Explanation of Solution

Given:

kN/mm2

Calculation:

Convert the quantities.

  kN/mm2=(1 kN×1 GN106 kN)/(((1 mm)2×1 m2106mm2))=106GN106m2=GN/m2

Thus, the correct SI form for kN/mm2 is GN/m2_.

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