Sample Solution from
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Chapter 1
Problem 1.1P
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(a)

To determine

The value of current I by using Ohm’s Law.

Expert Solution

Answer

  I=5mA

Explanation of Solution

Given information:

  V=5VR=1kΩ

Calculation:

The expression of Ohm’s law can be written as

  V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

  V=IR5=I(1× 103)I=51× 103I=5×10−3AI=5mA

(b)

To determine

The value of resistanceR by using Ohm’s Law.

Expert Solution

Answer

  R=5kA

Explanation of Solution

Given information:

  I=1mAV=5V

Calculation:

The expression of Ohm’s law can be written as

  V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

  V=IR5=R(1× 10 −3)R=51× 10 −3R=5×103AR=5kA

(c)

To determine

The value of voltage V by using Ohm’s Law.

Expert Solution

Answer

  V=1V

Explanation of Solution

Given information:

  I=0.1mAR=10kΩ

Calculation:

The expression of Ohm’s law can be written as

  V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

  V=IRV=(10× 103)(0.1× 10 −3)V=1V

(d)

To determine

The value of current I by using Ohm’s Law.

Expert Solution

Answer

  I=10mA

Explanation of Solution

Given information:

  V=1VR=100Ω

Calculation:

The expression of Ohm’s law can be written as

  V=IR

Here, V = voltage

I = current

R = resistance.

Putting the given values in the equation of Ohm’s Law,

  V=IR1=I(100)I=1100AI=10mA

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