Given:

Drag Coefficient of sports car, CD = 0.30

Front area of the car, A=21ft2

Speed of the car, V = 110mi/h

Density, ρ = 0.002378slugs/ft2

Formula Used:

The power required to overcome the aerodynamic drag is

  P = F × V

Where,

Force = F 

Velocity = V

Calculation:

The required power is calculated by power equation

  P = F × V ..................... (1)

We know that

Force applied on caris given by

  F = 12ρACDV2 ...................... (2)

Where,

Density = ρ

Front Area of the Car = A

Drag coefficient = CD

Rearranging the equation (1) as

  P = F × V

  P = (12 ρACD×V2) ×(V) 

  P = (12 ρACD)×V3   .................. (3)

To calculate power in (lb-ft/r), we have to convert the velocity from mi/h to ft / sec

  V = 110 mi/h = 110×52803600ft/s

As -

  1mi/h = 5280 ft3600 sec

Put the given values in equation (3)

  P = (12  ρACD)×V3P = (12×0.002378×21×0.3)×( 110×5280 3600)3

  P = 31455.364 lb-ft/s .......................... (4)

But we want the power in hp -

We know that - 1 lb-ft/s  = 1550hp 

So, the calculated power of equation (4) is converted into hp as

  P = 31455.364550hpP = 57.19 hp

Conclusion:

Thus, the power required to overcome the aerodynamics drag is 57.19hp