The mean, median and mode for the set of 40 chemistry final scores.
The mean of the chemistry final scores is
The given data set of 40 scores that consists of chemistry final marks is given below:
93 | 85 | 99 | 77 |
94 | 99 | 86 | 76 |
95 | 99 | 97 | 84 |
91 | 89 | 77 | 87 |
97 | 83 | 80 | 98 |
75 | 94 | 81 | 85 |
78 | 92 | 89 | 94 |
76 | 94 | 96 | 94 |
90 | 79 | 80 | 94 |
77 | 86 | 83 | 81 |
Calculation:
The formula to calculate the mean is,
Where,
The sum of the 40 final scores is given below.
Substitute 3502 for
Thus, the mean is 87.55.
Median:
For calculation of median, arrange the data in ascending or descending order. Now data is arranged in descending order as shown below:
99 | 99 | 99 | 98 | 97 | 97 | 96 | 95 | 94 | 94 |
94 | 94 | 94 | 93 | 92 | 92 | 91 | 90 | 89 | 89 |
87 | 86 | 86 | 85 | 85 | 84 | 83 | 83 | 81 | 81 |
80 | 80 | 79 | 78 | 77 | 77 | 77 | 76 | 76 | 75 |
The formula to calculate the median for even data is shown below.
The total number of terms in the data is 40 so, substitute 40 for n in the above formula.
Substitute 89 for
Thus, the median is 88.
Mode:
For calculation of mode, check the number that occurs most frequent. Since, 94 occur for 5 times in the table, thus 94 is the mode.