# Solution: Chapter 1 – Problem 10E – University Physics, 14th Edition

(a)

To determine: the number of foot per second in 60mph60 mph.

Answer: the number of foot per second in 60mph60 mph is 88ft/s88 ft/s.

Explanation:

Given info: one mile is 5280ft5280 ft. One hour is 3600s3600 s. The speed is 60mph60 mph.

Formula to calculate the speed is,

v=60mih×(5280ft1mi)(3600s1h)v=88ft/sv=60 mih×(5280 ft1 mi)(3600 s1 h)v=88 ft/s

• vv is the speed.

Conclusion:

Therefore, the number of foot per second in 60mph60 mph is 88ft/s88 ft/s.

(b)

To determine: the acceleration of freely falling object in m/s2m/s2.

Answer: the acceleration of free falling object is 9.7536m/s29.7536 m/s2.

Explanation:

Given info: The acceleration of free falling object is 32ft/s232 ft/s2. One feet is 30.48cm30.48 cm.

Formula to calculate the acceleration of free falling object is,

g=32fts2×(30.48cm1ft)(1m100cm)g=9.7536m/s2g=32 fts2×(30.48 cm1 ft)(1 m100 cm)g=9.7536 m/s2

• gg is the acceleration of free falling object.

Conclusion:

Therefore, the acceleration of free falling object is 9.7536m/s29.7536 m/s2.

(c)

To determine: The density of water in kilogram per cubic meter.

Answer: The density of water is 1000kg/m31000 kg/m3.

Explanation:

Given info: The density of water is 1.0g/cm31.0 g/cm3.

Formula to calculate the density of the water is,

d=1.0gcm3×(1kg1000g)(1m100cm)3d=1000kg/m3d=1.0 gcm3×(1 kg1000 g)(1 m100 cm)3d=1000 kg/m3

• dd is the density of water.

Conclusion:

Therefore, the density of water is 1000kg/m3