LAB4Takehome_Cellbio

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St. Mary's University *

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Biology

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Feb 20, 2024

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Dataset: Use the dataset provided on the last page. The data supplied is what was expected to occur in your lab, but if you did something wrong or if the enzyme for some reason didn’t work, you may not have appropriate data to work with. INSTRUCTIONS: Use the standard curve formula to convert each absorbance value into an amount of starch ( g). Create a single graph with two lines, one line for the control (the reaction without inhibitor added), and the second line for the inhibitor (the reaction with inhibitor added). The curved trendline options don’t work very well, so I recommend connecting the markers with smooth lines. In Excel, the graph type is called a “ scatterplot with smooth lines and markers ”. Avoid the “2D line” charts. Paste or import your graph into this document then move to the next page BIOL2321 | 2022 4- 1
QUESTIONS: 1. Use the graph to decide whether or not the inhibitor slows the reaction rate. Breifly explain why or why not. The inhibitor did in fact slow down the reaction rate of the breakdown of starch. The control data shows the steady decreasing of starch over time, but the inhibitor data shows a slower rate of reaction. At the end of the reaction (at 30 minutes), the control data has a lower concentration of starch (3.87 µg) than that of the inhibitor, which has a higher concentration of starch (20.13 µg). This tells me that the inhibitor had a slower rate of reaction (took more time to breakdown the starch). 2. Look up the definitions of both a competitive inhibitor and non-competitive inhibitor . Read over the definitions, then use the definitions to explain what would happen to the diagram below given the situation in the description. The rectangle in blue is the enzyme itself. The active site is the upside-down triangle at the top, and the allosteric site is the circular space at the bottom. A) A competitive inhibitor is present in a cell along with the substrate for the enzyme. What SHAPE is the substrate? What SHAPE is the inhibitor? What happens when the inhibitor binds to the enzyme? The shape of the substrate would be an upside-down triangle (a similar shape to the active site). The shape of the inhibitor would also be an upside-down triangle (similar shape to the substrate so that it can fit into the active site). When the inhibitor binds to the enzyme, it blocks the substrate from binding and the reaction can no longer happen, or the reaction would slow down. B) A non-competitive inhibitor is present in a cell along with the substrate for the enzyme. What SHAPE is the substrate? What SHAPE is the inhibitor? What happens when the inhibitor binds to the enzyme? BIOL2321 | 2022 4- 2
Enzyme Inhibitor Lab 5 The shape of the substrate would be an upside-down triangle (a similar shape to the active site). The shape of the inhibitor would be a circle (a similar shape that fits into the allosteric site). When the non- competitive inhibitor binds to the enzyme, it will bind to the allosteric site. Once it binds, this causes the enzyme to lose its shape which means that the substrate can no longer bind to its active site. Or even if the substrate binds, once the inhibitor binds to the allosteric site, the reaction can no longer occur effectively or slows down. 3. Refer to the structural diagrams below and state in one sentence whether you think acarbose is more likely to be a competitive or non-competitive inhibitor and why . (You are free to look up acarbose, but make sure your conclusion is based upon and agrees with your graph!) I think that acarbose is most likely to be a competitive inhibitor because it ‘competes’ with the substrate, alpha-amylase, by binding to the active site, and this is shown on my graph as there is a decrease in the reaction rate due to the inhibitor binding to the active site. I think that acrobose is the most likely to be competitive inhibitor. This is an image of acarbose; it lowers your blood sugar by preventing the breakdown of starch into sugar (medication used to treat type 2 diabetes) Source: https://pubchem.ncbi.nlm.nih.gov/compound/Acarbosa 4. Calculate the amount of starch remaining at each timepoint for both the control and the inhibitor data. Use the standard curve equation provided under both tables on the last page. Control Data BIOL2321 | 2021 5- 3
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Lab 4 Take-home assignment Time (in minutes) Absorbance (A 580nm ) Calculations of the amount of starch remaining (µg) Amount of starch remaining (µg) 0 1.793 1.793/0.015 119.53 5 1.026 1.026/0.015 68.40 10 0.476 0.476/0.015 31.73 15 0.263 0.263/0.015 17.53 20 0.160 0.160/0.015 10.67 25 0.091 0.091/0.015 6.07 30 0.055 0.055/0.015 3.67 Inhibitor Data Time (in minutes) Absorbance (A 580nm ) Calculations of the amount of starch remaining (µg) Amount of starch remaining (µg) 0 1.931 1.931/0.015 128.73 5 1.555 1.555/0.015 103.67 10 0.953 0.953/0.015 63.58 15 0.641 0.641/0.015 42.73 20 0.457 0.457/0.015 30.47 25 0.372 0.372/0.015 24.80 30 0.302 0.302/0.015 20.13 Once you’re finished, please upload this file to the Lab 4 take-home assignment Dropbox on Brightspace. This assignment is due by 7 days after your lab assignment was due (in other words, by 5:30pm on either Saturday March 18 th or Saturday March 25 th ). 5- 4 2021 | BIOL2321
Enzyme Inhibitor Lab 5 This is glucose: Starch is made of many glucose molecules linked together in a chain: The natural substrate of alpha-amylase is starch. Alpha-amylase cuts the bond between adjacent glucose molecules to make shorter starch molecules or to release glucose. We are testing a potential inhibitor of alpha-amylase named acarbose (a similar structure to starch 78) Dataset: CONTROL: Time (min) A 580 Amount of starch remaining ( g) Blank - BIOL2321 | 2021 5- 5
Lab 4 Take-home assignment 0 1.793 5 1.026 10 0.476 15 0.263 20 0.160 25 0.091 30 0.055 INHIBITOR: Time (min) A 580 Amount of starch remaining ( g) Blank - 0 1.931 5 1.555 10 0.953 15 0.641 20 0.457 25 0.372 30 0.302 Use the following standard curve formula: y = 0.015x 5- 6 2021 | BIOL2321
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