Oxidative Resp finished

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Dec 6, 2023

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Ozidatire Rhosphoy1ation K/8 a1e 4#e e(ec41/.3 $. NADK a.d FADK S 63ed 4/ ,a'e ATF d61%." ce**6(a1 1e30$1a4%/.? WL y ! T#e !&.a) 0#a3e / ce(*6*a1 2e30%1a4$/. $3 ozidative qhosqhor7lation, B/4# 4#e e(ec41/. 42a.30/14 c#a%. a.d c#e-%/3,/3$3 -a'e 60 /9%da4$7e 0#/30#/1:*a4%/.. D61$." 4#$3 0#a3e / ce*(6(a1 2e30%2a4$/., a** / 4#e NADK a.d FADK 2 4#a4 8e1e 01/d6ced %. /4#e1 0#a3e3 / ce(*6(a1 1e30%1a4$/. ("*:c/*:3$3, 0:167a4e / 9 $da4$/. , a.d c$41$c ac$d c:c+e) a1e 63ed 4/ -a'e ATE T #e 0 1/ce33 /cc613 %. 4#e 01/4e%. c/- 0 ( e9e3 e, b e d ded %. 4#e %..e2 -$5/c#/.d1$a( ,e , b 1a.e. Wodeł 1 — ßłeztron Wransport CLan H+ H+ H+ H’ H+ H€ H’ H+ H+ H+ H+ H’ O JTER H CROCHOKDRCA L H EMBRAKE H’ H+ H+ H€ H’ H+ H+ H’ H€ H’ H€ H+ H’ H’ H+ H+ H+ H’ H+ H+ I KTERMEMBRAKE Sqace H€ H’ Ni½k porenri»ł³€ enei½¡ ełecrion H+ H’ H+ r H+ H+ H+ H+ H+ H+ H+ . I KKER H CTOCHOKDRCAL H EMBRAKE ”.tffif® ”4D T + K + ”HiO O » + 4H + H CTOCHOKDRCD Hatrix l. C/.3%de2 4#e ,e-b2a.e3 $*(6342a4ed $. F/de( l. C$1c(e a 3ec4$/. / 4#e -$4/c#/.d1$a be(/8 8#e1e 4#$3 3$4e ,%"#4 be (/ca4ed. located in the inner mitochondrial membrane.

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2, R%&%: >7 W7$%3 1, a‚ D%=#:0"% >.% :%-076 06 W7$%3 1 B.%:% >.% .0-.%=> #76#%6>;!>076 7& .D$:7-%6 076 (H x ) 0= 37#!>%$, b, A##7;$06- >7 W7$%3 1¸ .7B $7 >.% .D$:7-%6 076= :%!#. >.0= !:%!? 3, EC83!06 B.D %6%:-D 0= :%9@0:%$ >7 57A% >.% .D$:7-%6 076= !#:7== >.% 5%5":!6% 06 >.% $0;%#>076 06$0#!>%$ 06 W7$%3 1. h. H0-. 87>%6>0!3 %6%:-D %3%#>:76= 8:7A0$% >.% %6%:-D 6%#%==!;D >7 8@58 .D$:7-%6 076= ! #:7== >.% 066%: 50>7#.76$:0!3 5%5":!6%, a , V.!? 573%#@3%= #!:;D > .%=% .0 - . 8 7 >%6>0!3 %6%:-D %4%#>;76=? b, V .%:% $0$ > . %=% %3% # >:76 #!::0%:= #75% (<75? c, V.%6 >.% %3%#>:76= ! :% ;% 3% !=%$ (<75 >. % %3%#>:76 #!::0%: , B. !> %3=% 0= 8;7$@#%$? A, (= >.% :%3%!=% 7& !6 %3%#>:76 +75 76% 7& >.%=% %3%#>:76 #!::0%:= 7C0$!>076 7: :% $@#>076? ), R%&%: >7 W7$%3 1. a , V . ! > 5 74% # @3% 0= >.% '16!3 %3%#>:76 ! ##%8>7; !,% ; >.% %3%#>:76 .!= 57A%$ > .; 7 @ -. >.% %3%#>:76 >:!6=87;> #.!06? b, /! > # 7587@6$ 0 = ):5%$ != ! '26!3 8 ;7$@#> 7 & > .% % 3%#>;76 > :!6=87; > # . !06? G, (= !6D AFG 8:7$@#%$¸ =8%#0(0#!33D 06 >.% %3%#>:76 >;!6=87:> #.!06? ✓ , ( = !6 D AFG @ =%$¸ =8%#0(0#!33D 06 > .% %4%#>;76 >:!6=87:> # . !06? 88 Intermembrane space which is between inner and outer membranes They diffuse through embedded protein channels via facilitated diffusion. The ions are moving against their concentration gradient, from low to high concentration. FADH2 and NADH The electron carriers are produced in glycosis, the link reaction, and the krebs cycle H+ Oxidation Oxygen H2O No No

Model 2 - Chemiosmosis H+ H+ H+ H+ H+ H+ Outer Mitochondrial Membrane H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ lntermembrane Space H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ H+ Inner Mitochondrial Membrane Mitochondrial Matrix 8. Describe the movement of hydrogen ions through the membrane illustrated in Model 2. 9. Would free energy be required for the hydrogen ions to move in the direction shown in Model 2? Explain your reasoning. 10. What is the name of the embedded protein that provides a channel for the hydrogen ions to pass through the membrane? 11. The flow of hydrogen ions through the protein channel provides free energy to do work. What process in Model 2 requires energy? H + H+ moves from high concentration in the intermembrane space to a lower concentration in the mitochondrial matrix through ATP synthase via facilitated transport No because they're moving from high to low concentrations ATP synthase phosphorylation (ADP-ATP)

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