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1.
The following two pure-breeding corn plants are crossed:
colored and starchy kernels
x
colorless and waxy kernels
All plants in the F1 generation have colored and starchy kernels.
Mating F1 plants to plants with colorless and waxy kernels generates an F2 with the following
phenotype frequencies:
10% colored and waxy kernels
10% are colorless and starchy kernels
40% colored and starchy kernels
40% colorless and waxy kernels
If you mate two F1 individuals to each other, what percent of the offspring will have colorless
and waxy kernels?
2.
A plant with all dominant phenotypes for four genes (
A, B, C, D
) is crossed to a plant with all
recessive phenotypes. The most common phenotypes in the offspring are the parental
phenotypes: dominant for all four genes or recessive for all four genes. All other possible
phenotypes are also observed in the offspring (dominant for some genes and recessive for
others), but they are less frequent.
Which of the following haplotypes is present in the parent with all dominant phenotypes?
Note that we are only considering alleles that are together in a haplotype. You don’t need to
worry about the order of the genes on the chromosome.
A.
abcd
B.
Abcd
C.
ABcd
D.
AbCd
E.
AbcD
F.
none of the above
3.
In a randomly mating population, 4 out 10,000 individuals (0.04%) have a rare recessive
phenotype. If you genotype 100 randomly selected individuals, how many do you expect to be
heterozygous for the recessive allele? Give your answer as an integer.
4.
10% of male flies in a population are sterile due to a recessive allele of an X-linked gene,
which has no effect in females. What is the frequency of this allele in females in the current
population, assuming that it was produced by random mating?
What percent of males in the next generation will be sterile?
5.
A lethal parasite invades an island that contains a population of oak trees and a population of
birch trees. A recessive allele present in the oak tree population causes small leaves and
provides resistance to the parasite. A dominant allele present in the birch tree population
causes silver bark and provides resistance to the parasite.
Before exposure to the parasite, both populations are initially in Hardy-Weinberg equilibrium for
these alleles. Only trees with the resistance phenotype can survive the parasite, and these trees
mate randomly to produce the next generation.
Before the parasite, 16% of the oak trees have small leaves. The parasite is then introduced.
In
the next generation, what percent of the population will have small leaves?
Before the parasite, ¾ of the birch trees have silver bark. The parasite is then introduced. In the
next generation, what fraction of the population will have silver bark? Give your answer as a
reduced fraction.
6.
The frequency of a recessive allele in a population of flies is 0.4, but there are no individuals
with the recessive phenotype. What is the frequency of heterozygotes in this population?
The next generation is created by random mating. What percent of the progeny will have the
recessive phenotype?
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Related Questions
1. Sunflowers with small flowers measuring 10 cm in diameter are crossed with plants that have large flowers with a diameter of 16cm. All offspring in the F1 generation have medium size flowers with 13 cm in diameter. When crossing two F1 generation flowers, the F2 generation shows 4 flowers are 10 cm in diameter and 4 are 16 cm in diameter. Between these are 5 phenotypic classes with diameters intermediate to those at the extremes.
a) Assuming that the alleles that contribute to flower diameter act additively, how many genes control flower size?
b) How much does each additive allele contribute to flower diameter?
c) What size flower makes up the largest phenotypic class?
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1. The height of a wheat plant is determined by several genes. In a variety the minimum size is 12 inches and the maximum is 24 inches. 12-inch plants were crossed with 18-inch plants, and produced an 18-inch F1. The F1 was allowed to cross each other, and an F2 was obtained in which the 12 and 24 inch plants were obtained with a frequency of 2/8195. How many genes are involved in determining plant size in this variety of wheat?
Select one:
a. 5b. 6c. 4d. 3
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1. The petals of the blue-eyed Mary (Collinsia parviflora) are normally blue. There are color variants of white and pink. Two pure breeding lines, one with pink petals and another with white petals were collected and the following crosses were made, with results shown in the table below:
parents
F1
F2
blue x white
blue
101 blue, 33 white
blue x pink
blue
192 blue, 63 pink
pink x white
blue
272 blue, 121 white, 89 pink
A. Define the allele symbols that can be used and show the genotype of parents, F1 and F2.
B. A cross between a certain blue F2 plant and a certain white F2 plant gave progeny of which 3/8 were blue, 1/8 were pink, and ½ were white. What must the genotypes of these two F2 plants have been?
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2. Three different pure-breeding strains of corn that produce ears with white kernels were crossed to eachother. In each case, the F1 plants were all red, whileboth red and white kernels were observed in the F2generation in a 9:7 ratio. These results are summarized in the following table.F1 F2white-1 × white-2 red 9 red : 7 whitewhite-1 × white-3 red 9 red : 7 whitewhite-2 × white-3 red 9 red : 7 whitea. How many genes are involved in determiningkernel color in these three strains?b. Define your symbols and show the genotypes for thepure-breeding strains white-1, white-2, and white-3.c. Diagram the cross between white-1 and white-2,showing the genotypes and phenotypes of the F1and F2 progeny. Explain the observed 9:7 ratio.
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D
D
1
2
d
In a particular plant, leaf color is controlled by gene locus D. Plants with at least one allele D have dark green leaves, and plants with the
homozygous recessive dd genotype have light green leaves. A true-breeding, dark-leaved plant is crossed with a light-leaved one, and
the F1 offspring is allowed to self-pollinate. The predicted outcome of the F2 is diagrammed in the Punnett square shown in the figure,
where 1, 2, 3, and 4 represent the genotypes corresponding to each box within the square.
Which of the boxes marked 1-4 correspond to plants with a heterozygous genotype?
O 1 only
O 1, 2, and 3
2 and 3
2, 3, and 4
4)
3.
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1. P is a dominant allele for purple flowers and p is the recessive allele that causes white flowers. The
following cross is performed: Pp x pp. What percentage of offspring would you expect to have white
flowers?
2. In peas, T (tall) is dominant to t (dwarf). A homozygous dominant plant is crossed to a heterozygous plant.
What is the expected outcome for the genotype ratio of offspring from this cross? What percentage of
offspring would you expect to be tall?
3. In peas, Y (yellow seeds) is dominant to y (green seeds) and R (round seeds) is dominant to r (wrinkled
seeds). The following cross is performed: YYRr x yyrr. What is the expected phenotype ratio of the
offspring?
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1. Use the following information to answer the question: Parental cross is RrYy x RrYy
Seed Shapes are R-round, r-wrinkled
Seed colors are Y-yellow, y-green
Based on the information given, what is the phenotype ratio of the offspring of this cross?
2. A pea plant heterozygous for height and seed color (TtYy) is crossed with a pea plant heterozygous for height but homozygous recessive for seed color (Ttyy). If 80 offspring are produced, how many are expected to be tall and have yellow seeds?
3. What is the chromosome theory of inheritance? How does this theory explain Mendel's results?
4. A cross between two organisms heterozygous for two different genes (AaBb) results in a 9:3:3:1 phenotype ratio among the offspring. Is the offspring's genotype ratio the same? Explain your answer.…
arrow_forward
1. Complete the Punnett square for a cross between a homozygous
red-flowered snapdragon (RR) and a homozygous white-flowered
snapdragon (WW). Give the ratio for the phenotype and the genotype.
Key
F1
Genotypic Ratio:
RR – red
Phenotypic Ratio:
wW- white
RW- pink
2. Complete the Punnett Square for a cross between two Fi plants (WW). Give
the phenotypic ratio for the F2 generation.
F2
Phenotypic ratio:
3. Cite some possible applications of genetics to plant breeding.
arrow_forward
Sunflowers with small flowers measuring 10 cm in diameter are crossed with plants that have large flowers with a diameter of 16cm. All offspring in the F1 generation have medium size flowers with 13 cm in diameter. When crossing two F1 generation flowers, the F2 generation shows 4 flowers are 10 cm in diameter and 4 are 16 cm in diameter. Between these are 5 phenotypic classes with diameters intermediate to those at the extremes.
What size flower makes up the most common phenotypic class?
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3.) A Heterozygous tall heterozygous red flowered plant is crossed with a Homozygous short white
flowered plant.
What is the genotype of the heterozygous tall heterozygous red flowered plant?
What is the genotype of the homozygous short white flowered plant?
Fill in the genotype in the parentheses and FOIL each parent’s genotypes:
heterozygous tall heterozygous red flowered plant (
homozygous short white flowered plant (
How many of the 16 offspring are:
tall & red
tall & white
short & red
short & white
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4. In pea plants, tall (T) plants are dominant to short (t), and green pods (G) are dominant to yellow (g).
Perform a Punnett square analysis for the following crosses, with the parental gametes and all possible
offspring genotypes that could be produced. **Include the phenotypic ratios for the offspring.
(a) TtGG × TTgg
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*Genes A and B are linked. Individual plants homozygous for different combinations of
these genes (AABB, aabb, AAbb, aaBB) were crossed at random to produce Fi plants. The
F₁ plants were self pollinated to produce the F2. The F₂2 progeny from six of the F₁ self
pollinations are listed below.
F₁ Plant
1
2
3
4
S
2.
Number of F₂ plants in each phenotypic class
AB
Ab
aB
98
10
34
3.
64
106
50
99
25
8
104
23
31
a. Determine the genotype of the F₁ that produced each F2 population.
1.
ab
32
18
MacBook Pro
36
2
5.
6.
b. Calculate the recombination frequency between genes A and B.
100
Linkage Problem Set
13. Assume that height and eye color are inherited as follows. T- tall, t- short and B- blue, b-
brown. Genes T and B are linked on chromosome 1, 20 map units apart. A tall brown eyed
woman marries a short blue eyed man. They have a son that is tall and blue eyed. This man
marries a short brown eyed woman.
a. Diagram the arrangement of the alleles on the two chromosome 1's of the tall blue
eyed…
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7. In pea plants, inflated pod is governed by a completely dominant gene and a
constricted pod by a recessive gene. Another independently segregating dominant
gene produces green pod while recessive gene produces yellow pod. Give the
genotypes of the parents in each of the crosses given below.
Phenotypes of Offspring
Inflated
yellow
Constricted
yellow
Parental Phenotypes
Parental genotypes
Inflated
groen
Constricted
Green
7.1. inflated green x
inflated yellow
58
62
18
22
7.2. constricted green x
constricted green
56
18
7.3 inflated yellow x
inflated yellow
64
20
74. inflated gr
green x
36
38
inflated yellow
7.5. inflated green x
inflated green
178
62
58
22
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7. In pea plants, inflated pod is governed by a completely dominant gene and a constricted
pod by a recessive gene. Another independently segregating dominant gene produces
green pod while recessive gene produces yellow pod. Give the genotypes of the parents
in each of the crosses given below.
Phenotypes of Offspring
Parental Phenotypes
Parental genotypes
Inflated
Inflated
Constricted
Constricted
yellow
green
yellow
Green
inflated green x
inflated yellow
7.1.
58
62
18
22
7.2. constricted green x
56
18
constricted green
7.3
inflated yellow x
64
20
inflated yellow
inflated green x
inflated yellow
7.4.
36
38
inflated green x
inflated green
7.5.
178
62
58
22
arrow_forward
2. Figure 8.10 In pea plants, round seed shape (R) is dominant to wrinkled seed shape (r) and yellow peas (Y) are dominant to green peas (y). What are the possible genotypes and phenotypes for a cross between RrYY and rrYy pea plants? How many squares do you need to do a Punnett square analysis of this cross?
arrow_forward
4). In papayas, sour fruit (S) is dominant over sweet fruit
(s), and green skin (G) is dominant over yellow skin (g).
The genes for these characteristics independently assort.
A homozygous plant with sour fruit and green skin is
crossed with a homozygous plant with sweet fruit and
yellow skin. Two individuals from the F1 generation are
then crossed to produce an F2 generation.
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If a heterozygous F1 Tobacco plant was crossed to an albino plant, what is the expected number of green and white plants in the next generation? (show Punnett square)
A woman homozygous dominant for albinism marries a man who is homozygous recessive for albinism. What are the possible genotypes and phenotypes percentages for their offspring?
A man that can roll his tongue is heterozygous for the trait marries a woman that cannot roll her tongue. They have a child. The rolling tongue is dominant to not rolling tongue.
What is the man’s genotype for tongue rolling? The women?
Show the Punnett square for the child’s genotype
Give the probability (percent chance) that the child can or cannot roll their tongue.
Oh no! The F1 and F2 generation seed packet labels were mixed around. How would we know which seeds we planted by observing the color of the leaves? (Hint: What are the genotypes of the two generations? What color leaves do they produce in what ratios?)
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4)
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#19
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x²
R
AA E
Paragraph
255
129
112
1
heavy, green, long
heavy, green, ovate
heavy, yellow, ovate
heavy, yellow, long
light, yellow, oblate
V
light, yellow, long
light, green, long
light, green, ovate
Normal
No Spacing
In an East Indian mango, three genes are linked on the same chromosome. Heavy bloom is
dominant to light bloom, skin that is green is dominant to skin that is yellow, and fruit with a
long shape is dominant to ovate shape. A plant that is true-breeding for the dominant traits
was crossed to a light, yellow and ovate fruit. The F1 plants were then testcrossed to light,
yellow and ovate fruit. The following results were obtained:
251
111
133
21
Styles
Heac
a) Diagram the crosses for the parental generation and F1 test cross.
b) Construct a genetic map that shows the order of these three genes and the distances
between them.
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In corn, a colored aleurone is due to the presence of an R allele; r/r is colorless. Another gene controls the color of the plant, with g/g being yellow and G_being green. A plant of unknown genotype is test-crossed, and the following progeny plants were obtained.
Colored green 89
Colored yellow 13
Colorless green 9
Colorless yellow 92
What was the phenotype and genotype of the plant used for the test cross?
A.
Colorless green - rG/rg
B.
Colorless yellow - rg/rg
C.
Colored yellow - Rg/rg
D.
Colored green - RG/rg
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8. Kernel color in wheat is controlled by 2 pairs of genes (AABB). Determine the color of the offspring with the following genotypes: (Note: 4 contributing alleles – red; 3 contributing alleles – medium red; 2 contributing alleles – intermediate red; 1 contributing allele – red; and 0 – white
AAbb x AaBb
AABb x Aabb
aaBb x Aabb
AABb x aabb
AABb x AaBb
A wheat plant producing medium red seed is crossed with another plant producing intermediate red seed (refer to problem no. 8). How many individuals will be?
Red
Medium red
Intermediate red
Light red
White
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In pineapples, leaves may be spiny, spiny-tipped or piping. Pineapples of different phenotypes
were used in the following crosses:
Pl phenotype
piping
X
spiny
P1 genotype
Fl phenotype
100% piping
F1 genotype
Crossing the Fls produced:
F2 phenotypes
F2 genotypes
ww gm
95 piping
25 spiny tipped
8 spiny
Using the letters A and B, give the COMPLETE genotypes of ALL the individuals.
SOLUTION
Get the total of the F2 generation
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In garden pea, resistance to a certain disease is controlled by a single locus with dominance forresistance (R) and recessive susceptible (r). Another locus governs seed color with yellow being dominant (Y)to green (y). A pea plant which is heterozygous for both gene pairs is crossed with a susceptible and green-seeded plant. The following data was observed in the progeny.
Phenotype NumberResistant yellow 43Susceptible green 49Resistant green 16Susceptible yellow 12Total 120
a. What is the calculated chi-square value based on an independent assortment assumption? Compute forthe df and write the conclusion. (NOTE: The cross will not yield a 9:3:3:1 ratio since not both of theparental genotypes are heterozygous for the 2 pairs of alleles. Thus, perform the cross first, show theparental genotypes, the gamete…
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9. In the F2 Generation, both the male and female pea plants are heterozygous for
round/wrinkles seeds. 1)Draw a Punnett square that shows this cross. 2)What are the
possible genotypes? 3)What are the possible phenotypes?
10. In pea plants, the allele for smooth pods (P) is dominant over the allele for pinched pods
(p). Construct a Punnett Square that shows a cross between an PP plant and an Pp plant.
Predict what percent of the offspring are likely to have smooth pods.
Essay: Is it possible for a son to inherit an allele on an X chromosome from his father? Explain
why or why not.
arrow_forward
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Related Questions
- 1. Sunflowers with small flowers measuring 10 cm in diameter are crossed with plants that have large flowers with a diameter of 16cm. All offspring in the F1 generation have medium size flowers with 13 cm in diameter. When crossing two F1 generation flowers, the F2 generation shows 4 flowers are 10 cm in diameter and 4 are 16 cm in diameter. Between these are 5 phenotypic classes with diameters intermediate to those at the extremes. a) Assuming that the alleles that contribute to flower diameter act additively, how many genes control flower size? b) How much does each additive allele contribute to flower diameter? c) What size flower makes up the largest phenotypic class?arrow_forward1. The height of a wheat plant is determined by several genes. In a variety the minimum size is 12 inches and the maximum is 24 inches. 12-inch plants were crossed with 18-inch plants, and produced an 18-inch F1. The F1 was allowed to cross each other, and an F2 was obtained in which the 12 and 24 inch plants were obtained with a frequency of 2/8195. How many genes are involved in determining plant size in this variety of wheat? Select one: a. 5b. 6c. 4d. 3arrow_forward1. The petals of the blue-eyed Mary (Collinsia parviflora) are normally blue. There are color variants of white and pink. Two pure breeding lines, one with pink petals and another with white petals were collected and the following crosses were made, with results shown in the table below: parents F1 F2 blue x white blue 101 blue, 33 white blue x pink blue 192 blue, 63 pink pink x white blue 272 blue, 121 white, 89 pink A. Define the allele symbols that can be used and show the genotype of parents, F1 and F2. B. A cross between a certain blue F2 plant and a certain white F2 plant gave progeny of which 3/8 were blue, 1/8 were pink, and ½ were white. What must the genotypes of these two F2 plants have been?arrow_forward
- 2. Three different pure-breeding strains of corn that produce ears with white kernels were crossed to eachother. In each case, the F1 plants were all red, whileboth red and white kernels were observed in the F2generation in a 9:7 ratio. These results are summarized in the following table.F1 F2white-1 × white-2 red 9 red : 7 whitewhite-1 × white-3 red 9 red : 7 whitewhite-2 × white-3 red 9 red : 7 whitea. How many genes are involved in determiningkernel color in these three strains?b. Define your symbols and show the genotypes for thepure-breeding strains white-1, white-2, and white-3.c. Diagram the cross between white-1 and white-2,showing the genotypes and phenotypes of the F1and F2 progeny. Explain the observed 9:7 ratio.arrow_forwardD D 1 2 d In a particular plant, leaf color is controlled by gene locus D. Plants with at least one allele D have dark green leaves, and plants with the homozygous recessive dd genotype have light green leaves. A true-breeding, dark-leaved plant is crossed with a light-leaved one, and the F1 offspring is allowed to self-pollinate. The predicted outcome of the F2 is diagrammed in the Punnett square shown in the figure, where 1, 2, 3, and 4 represent the genotypes corresponding to each box within the square. Which of the boxes marked 1-4 correspond to plants with a heterozygous genotype? O 1 only O 1, 2, and 3 2 and 3 2, 3, and 4 4) 3.arrow_forward1. P is a dominant allele for purple flowers and p is the recessive allele that causes white flowers. The following cross is performed: Pp x pp. What percentage of offspring would you expect to have white flowers? 2. In peas, T (tall) is dominant to t (dwarf). A homozygous dominant plant is crossed to a heterozygous plant. What is the expected outcome for the genotype ratio of offspring from this cross? What percentage of offspring would you expect to be tall? 3. In peas, Y (yellow seeds) is dominant to y (green seeds) and R (round seeds) is dominant to r (wrinkled seeds). The following cross is performed: YYRr x yyrr. What is the expected phenotype ratio of the offspring?arrow_forward
- 1. Use the following information to answer the question: Parental cross is RrYy x RrYy Seed Shapes are R-round, r-wrinkled Seed colors are Y-yellow, y-green Based on the information given, what is the phenotype ratio of the offspring of this cross? 2. A pea plant heterozygous for height and seed color (TtYy) is crossed with a pea plant heterozygous for height but homozygous recessive for seed color (Ttyy). If 80 offspring are produced, how many are expected to be tall and have yellow seeds? 3. What is the chromosome theory of inheritance? How does this theory explain Mendel's results? 4. A cross between two organisms heterozygous for two different genes (AaBb) results in a 9:3:3:1 phenotype ratio among the offspring. Is the offspring's genotype ratio the same? Explain your answer.…arrow_forward1. Complete the Punnett square for a cross between a homozygous red-flowered snapdragon (RR) and a homozygous white-flowered snapdragon (WW). Give the ratio for the phenotype and the genotype. Key F1 Genotypic Ratio: RR – red Phenotypic Ratio: wW- white RW- pink 2. Complete the Punnett Square for a cross between two Fi plants (WW). Give the phenotypic ratio for the F2 generation. F2 Phenotypic ratio: 3. Cite some possible applications of genetics to plant breeding.arrow_forwardSunflowers with small flowers measuring 10 cm in diameter are crossed with plants that have large flowers with a diameter of 16cm. All offspring in the F1 generation have medium size flowers with 13 cm in diameter. When crossing two F1 generation flowers, the F2 generation shows 4 flowers are 10 cm in diameter and 4 are 16 cm in diameter. Between these are 5 phenotypic classes with diameters intermediate to those at the extremes. What size flower makes up the most common phenotypic class?arrow_forward
- 3.) A Heterozygous tall heterozygous red flowered plant is crossed with a Homozygous short white flowered plant. What is the genotype of the heterozygous tall heterozygous red flowered plant? What is the genotype of the homozygous short white flowered plant? Fill in the genotype in the parentheses and FOIL each parent’s genotypes: heterozygous tall heterozygous red flowered plant ( homozygous short white flowered plant ( How many of the 16 offspring are: tall & red tall & white short & red short & whitearrow_forward4. In pea plants, tall (T) plants are dominant to short (t), and green pods (G) are dominant to yellow (g). Perform a Punnett square analysis for the following crosses, with the parental gametes and all possible offspring genotypes that could be produced. **Include the phenotypic ratios for the offspring. (a) TtGG × TTggarrow_forward*Genes A and B are linked. Individual plants homozygous for different combinations of these genes (AABB, aabb, AAbb, aaBB) were crossed at random to produce Fi plants. The F₁ plants were self pollinated to produce the F2. The F₂2 progeny from six of the F₁ self pollinations are listed below. F₁ Plant 1 2 3 4 S 2. Number of F₂ plants in each phenotypic class AB Ab aB 98 10 34 3. 64 106 50 99 25 8 104 23 31 a. Determine the genotype of the F₁ that produced each F2 population. 1. ab 32 18 MacBook Pro 36 2 5. 6. b. Calculate the recombination frequency between genes A and B. 100 Linkage Problem Set 13. Assume that height and eye color are inherited as follows. T- tall, t- short and B- blue, b- brown. Genes T and B are linked on chromosome 1, 20 map units apart. A tall brown eyed woman marries a short blue eyed man. They have a son that is tall and blue eyed. This man marries a short brown eyed woman. a. Diagram the arrangement of the alleles on the two chromosome 1's of the tall blue eyed…arrow_forward
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