Lab_report 4

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Arizona State University *

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113

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Chemistry

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Feb 20, 2024

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5

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Chemistry Lab Report Experiment 4: Determination of the Chemical Giuseppe Preziosi Purpose and learning object: To observe the reactivity of metals with water and acid. To introduce acid-base titration as a method to determine the molecular formula of a compound. Part 1. The reaction of Zinc and Calcium with dilute HCl and Water. Results Analysis Reactants Observation ?𝐧 + 𝟔𝐌 𝐇𝐂𝐥 During the reaction, there was vigorous bubbling, indicating the production of gas. We collected the gas that was generated and subjected it to a flame, resulting in a small explosion. Once the reaction was complete, we observed that the zinc had completely dissolved 𝐂? + 𝟎. 𝟎?𝐌 𝐇𝐂𝐥 We observed vigorous bubbling and a color change from transparent to white during the reaction. We collected the gas that was produced and ignited it, resulting in a small explosion. Once the reaction was complete, we were left with a white powder. ?𝐧 + 𝐇 ? 𝐎 When no reaction occurred initially, we added 6M HCl, and the mixture started bubbling vigorously. Additionally, the color changed from transparent to white. After the reaction was completed, we observed that the zinc was completely dissolved. 𝐂? + 𝐇 ? 𝐎 We observed vigorous bubbling and a color change from transparent to white during the reaction. Once the reaction was complete, we were left with white powder. In a separate test tube containing calcium metal, we added 2 drops of 0.1% phenolphthalein solution. The solution changed color from clear to a light purple hue.
Part 2. Titration of the product of the reaction of calcium in water. Calculation table Volume of HCl used Final value of burette initial value of burette 31.3 ?? − 25.0 ?? = 6. .3 ?? Moles of H + used to titrate sample Mole H + = concertation * volume 0.30 ? ∗ 0.0063 ? = 0.00189 ?𝑜? H + Moles of OH neutralized Mole OH = concertation * volume 0.30 ? ∗ 0.0063 ? = 0.00189 ?𝑜? OH Moles of calcium Moles of calcium = mass of Ca / molecular weight of Ca 0.050 ? ?𝑎 ∗ 1 ?𝑜? ?𝑎 40 ? ?𝑎 = 0.00125 ?𝑜? ?𝑎 Mole ratio of OH to Ca Moles of OH / moles of Ca 0.00189 ?𝑜? OH 0.00125 ?𝑜? ?𝑎 = 1.512 Results Analysis Data Trial 1 Trial 2 Mass of calcium 0.050 g 0.051 g Initial volume in the burette 25.0 mL 31.3 mL Final volume in the burette 31.3 mL 38.0 mL Volume of HCl used 6.3 mL 6.7 ml Molarity of HCl 0.30 M 0.30 M Molarity of H + 0.30 M 0.30 M Moles of H + used to titrate sample 0.00189 mol 0.00201 mol Moles of OH neutralized 0.00189 mol 0.00201 mol Moles of calcium 0.001 0.001 Mole ratio of OH to Ca 1.512:1 1.608:1 Round the ration to the nearest integer 2:1 2:1 Experimental chemical formula ?𝑎(?𝐻) 2
Prelab questions: In forming compounds does a calcium atom gain or lose electrons? In the formation of the compound ( ?𝑎 + 𝐻 2 ? 𝑦𝑖?𝑙?𝑠 → ?𝑎(?𝐻) 2 + 𝐻 2 ) the calcium goes from charge 0 (element does not have any charge) to charge + 2 so its loosed electrons. How many electrons? It lost 2 electrons. What is the charge of the hydroxide ion? The charge of hydroxide ion is -1 What would you predict for the chemical formula of calcium hydroxide? ?𝑎(?𝐻) 2 Does the calcium hydroxide compound have charge? No, the calcium hydroxide compound has no charge. 2. Balanced the equations 2?𝑎(𝑠) + 2𝐻 2 ? (?) 𝑦𝑖?𝑙?𝑠 → 2?𝑎?𝐻(𝑎𝑞) + 𝐻 2 (?) 2?𝑎(𝑠) + 2𝐻?? (𝑎𝑞) 𝑦𝑖?𝑙?𝑠 → 2?𝑎??(𝑎𝑞) + 𝐻 2 (?) 3. How many moles of 𝐇 ? will be produced if 15.0g of Na reacts completely with excess HCl? Moles of Hydrogen: 15.0 g Na ∗ 22.99 mol Na 15g Na 1 mol H 2 2 mol Na = 0.326 mol H 2 4. In this experiment a sample of calcium reacts with water to produce calcium hydroxide and hydrogen gas. 1. The solution is titrated with HCl. Write the net ionic reaction that occur. Chemical formula: ?𝑎(?𝐻) 2 + 2𝐻?? 𝑦𝑖?𝑙?𝑠 → ?𝑎?? 2 + 2𝐻 2 ? Ionic equation: ?𝑎 2+ + 2?𝐻 + 2𝐻 + + 2?? 𝑦𝑖?𝑙?𝑠 → ?𝑎 2+ + 2?? + 2𝐻 2 ? Net ionic equation : ?𝐻 + 𝐻 + 𝑦𝑖???𝑠 𝐻 2 ?
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