Quiz #3 Session #1_ Chem 1LE W24
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Chemistry
Date
Feb 20, 2024
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7
Uploaded by AdmiralFog8928
2024/2/6 14:40
Quiz #3 Session #1: Chem 1LE W24
https://canvas.eee.uci.edu/courses/59678/quizzes/300102
1/7
Quiz #3 Session #1
Due
Feb 6 at 11:59pm
Points
10
Questions
8
Time Limit
None
Allowed Attempts
3
Instructions
Attempt History
Attempt
Time
Score
LATEST
Attempt 1
9 minutes
10 out of 10
Correct answers are hidden.
Score for this attempt: 10
out of 10
Submitted Feb 6 at 2:40pm
This attempt took 9 minutes.
The information needed to answer these questions can be found in your general chemistry lecture
textbook, the Lab Safety for Chemists online text
(https://drive.google.com/file/d/1zGrN2CkyKk-
UejhEa277V-VPzfgf-TLr/view?usp=sharing) (Section 2.1.2) and in documents hyperlinked within this
document. Take the Quiz Again
2 / 2 pts
Question 1
A NaOH (aq) stock solution was created by dissolving 3.88 g NaOH in
water to create a 100.00 mL solution. What is the concentration of this
solution? [ Select ]
M
Perform a ten fold dilution to create three more solutions. What are the
concentrations of these solutions?
Dilution #1: [ Select ]
M
Dilution #2: 0.0097 M
2024/2/6 14:40
Quiz #3 Session #1: Chem 1LE W24
https://canvas.eee.uci.edu/courses/59678/quizzes/300102
2/7
Answer 1:
Answer 2:
Answer 3:
Answer 4:
Dilution #3: 0.00097 M
0.970 0.0970 0.0097 0.00097 1 / 1 pts
Question 2
Why is significant?
max
The value indicates the amount of light absorbed. The value can indicate the observed color of solution. The value increases as the energy of light increases. The instrument response is highest at that wavelength. The value is can be used to identify a particular chemical. 2 / 2 pts
Question 3
Fill in the table with the correct responses.
Reaction
Order
Integrated
Rate Law
Linear
Plot
Rate
constant
Half
life
2024/2/6 14:40
Quiz #3 Session #1: Chem 1LE W24
https://canvas.eee.uci.edu/courses/59678/quizzes/300102
3/7
(k) from
the linear
plot
(t
)
zero
[a]
[b]
[c]
[d]
first
[e]
[f]
[g]
[h]
second
[i]
[j]
[k]
[l]
Answer bank:
1. 1/A = kt + 1/A
2. ln A vs time
3. negative of the slope (-m)
4. log A vs time
5. A = -kt + A
6. A
/k
7. A
/2k
8. y-intercept
9. A vs time
10. slope (m)
11. A = kt + A
12. 1/A vs t
13. lnA = -kt + lnA
14. ln2/k
15. 1/kA
1/2
t
o
t
o
t
o
t
o
t
o
o
a
5
b
9
c
3
Your preview ends here
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- ESF X empt/quiz_start_frame_auto.d21?ou=9739790&isprv=&qi=11007766&cfql=0&dnb=0&fromQB=0&inProgress=1 ystems Question 5 (1 point) Ben starts walking along a path at 3 mi hr¹. Amanda starts jogging along the same path 1 hour later at 5 mi hr. After how much time jogging does Amanda catch up to Ben? 3.5 hr 2.5 hr 2 hr 16arrow_forwardRapidly cool to 625°C (1155°F), hold at this temperature for 10 s, rapidly cool to 400°C (750°F), hold at this temperature for 5 s, then quench to room temperature. martensite % proeutectoid ferrite bainite fine pearlite austenite i eTextbook and Mediaarrow_forwardTrial [I0:] [HSO: ] Time Rate [HSO3 ]/time 1 49 25 3 16.9 Table-2 Find the concentrations of [IO3] and [HSO3] and enter into the table. Divide the concentration of HSO3 with the time in seconds to get the rate. Volume is assumed to be additive in this experiment. Thus, the total volume of all the solutins is assumed to be 20.0 mL. This introduces a small error that can be considered insignicant. The concentrations of IO; and HSO, (after mixing but before the reaction begins) can be calculated using the relationship: Mailute Vdilute= Mcone Vcone. A sample calculation is shown below for the concentration of IO, in Trial 1: Mailute to be calculated Vdilue 20.0 mL 0.020 M x 2.0 mL Mcone 0.020M V conc 2.0 mL %3D diluted [IO, ] = = 0.0020 M IO, %3D 20.0 mL Similarly, the concentration of HSO; in Trial 1 is calculated thus: 0.010 M x 2.0 mL diluted [HSO, ] =0.0010 M HSO, 20.0 mLarrow_forward
- 26) The floor tiles in SE 27 are about 1 square foot and the lab is about 25 tiles wide and about 36 tiles from front to back. When the emergency shower was demonstrated, in 10. seconds the water in the trash can was about 1 foot deep. One student estimated this was 2.5 gallons. Estimate how deep the room will get in inches after a 15 minute shower. List 3 simplifving assumptions you make in this calculation rea L-36 Tile fiDw ill it cost2 The density of gold is 27l An artist plans to apply gold leaf to a painting with an area of 2.32 f? and a thickness of 1.50arrow_forwardWith the image attached please do the calculations/calculate what is highlighted in yellow please Please also calculate - percent % error in molar mass - percent % error in pKa Please please please answer as fast as possiblearrow_forwardPlz answer correctly in 20 minutes plz it's very urgentarrow_forward
- Please answer fast it’s very important and urgent I say very urgent so please answer super super fast please For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466arrow_forwardHey, I need help with question one. These problems are for us to study, not for a grade. It's only practice.arrow_forwardTable 2- AA contents of lemon juice stored at 10°C Time (mo) AA content (mg/100 mL) 1 69 1.25 58 49 10 30 Clue: First, write this equation in the form of "y = ax + b" form. And, then determine the x and y values. Give units wherever the units are applicable!!!!!arrow_forward
- You are interested to know the Q10 value for mean heart rate (# of beats/10 sec) for a species of crab for the temperature interval of 25°C - 35°C. To find this value, you collect data for these six temperatures and calculate mean heart rate (# of beats/10 sec) for each temperature. Here is the data: 10°C 15°C 20°C 25°C 30°C 35°C Mean Heart Rate (# 23.67 23.89 24.33 27 35.89 37.78 beats/10 sec) What is the Q1o value for heart rate (# of beats/10 seconds) for the temperature interval of 25°C - 35°C? Round your answer to two decimal places.arrow_forwardBa(NO,l(aq) + K,SOlaq) Baso(s) + 2 KNOlaq) Volume Volume Trial 0.10 M Ba(NO)2 (ml) 0.10 M K,SO, (ml) Mass Baso4 (s) Limiting Reagent 50. 20. 0.46 50. 40. 0.92 3 50. 50. 1.15 4 50. 60. 1.15 50. 80. 1.15 • Question 8 Use the data to identify the limiting reagent for each reaction performed. V Trail 1 a. Neither/Both EV Trial 2 b. Baso4 EV Trial 3 C. KSO4 EV Trial 4 d. Ba(NO3)2 EV Trial 5 e. KNO3 Question Help: Message instructor I Calculator Submit Question • Question 9 Why is the amount of precipitate in the Data Table above the same in Trials 3 through 5? Edit Insert Formats B IVX x' Aarrow_forwardE MasteringChemistry: HW 01b C Get Homework Help With Che b My Questions | bartleby > MyLab and Mastering Home - Students x X A session.masteringchemistry.com/myct/itemView?offset=next&attemptNo=1&assignmentProblemlD=139293464 E Apps W California Fool's Go... CLA Purdue OWL: APA F.. O Christmas Window... C Bianca 4-piece Fabr.. O ANGELINO o How do I format m. O Choosing Resource. New Tab Dashboard >>arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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