Unit 8_Nazarli_Heydar_62115076

.pdf

School

University of British Columbia *

*We aren’t endorsed by this school

Course

154

Subject

Chemistry

Date

Dec 6, 2023

Type

pdf

Pages

6

Uploaded by MinisterKookabura3556

Report
CHEM 154: Chemistry for Engineering Unit 8: Entropy and the Second Law Name:_______________________________________________________ Student ID: _________________________________________________ 2023W 1 1. Find/borrow a coin and flip it four times. a) Record how many times the coin lands “heads up”. b) Is the outcome you obtained what you would have initially predicted? Briefly explain. 2. Good question. If all students in the class flip a coin four times, calcualte the entropy associated with the MOST and LEAST likely outcomes. (k = 1.38 x 10 -23 J K -1 ).
CHEM 154: Chemistry for Engineering Unit 8: Entropy and the Second Law Name:_______________________________________________________ Student ID: _________________________________________________ 2023W 2 3. HFC-134a ( CH 2 FCF 3 ; molar mass = 102.0 g mol -1 , boiling point = - 27 °C, ΔH vap = 22.0 kJ mol -1 ) is a common liquid refrigerant. It vaporizes using heat from the refrigerator, thereby cooling its contents, and is later condensed into a liquid with the help of a pump. a) Determine the entropy change (ΔS) in J K -1 for the reversible vapourization of 102.0 g of HFC-134a at its boiling point (at a constant pressure of 1 atm). b) If the heat in part a) comes from a refrigerator whose contents (the surroundings) are at a temperature of 4 °C , d etermine ΔS surr in J K -1 for the vapourization process. c) Determine ΔS universe for this process. 4. Good question. While performing an experiment, a CHEM 154 student cools the refrigerator from Question 3) to -35 °C. Use the second law of thermodynamics to prove the refrigerator cannot operate by having HFC-134a absorb heat from the contents of the refrigerator under these conditions.
CHEM 154: Chemistry for Engineering Unit 8: Entropy and the Second Law Name:_______________________________________________________ Student ID: _________________________________________________ 2023W 3 5. Calculate ΔS for the formation of 1 mol of solid Fe 2 O 3 (rust!) from its elements given the following information: 6. Consider the reaction: N 2 O 4 (g) 2 NO 2 (g) Δ H ° = 58.03 kJ Δ S ° = 176.7 J K -1 a) Calculate the temperature at which the reaction is at equilibrium under standard conditions (assume Δ H ° and ΔS° do NOT vary with temperature). b) Explain what happens to the spontaneity of the reaction when the temperature is above or below that calculated in part a). Species S m (J mol -1 K -1 ) Fe(s) 27.28 O 2 (g) 205.10 Fe 2 O 3 (s) 87.40
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help