Solutions and Concentrations Worksheet

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How many milliliters of a 17% w/v concentrate of benzalkonium chloride should be used in preparing 150 mL of a stock solution such that 15 mL. diluted to 1 liter will yield a 1:5000 solution? A. 2 ml. B. 23.5 mL C. 11.75 ml. D. 0.2 mL

The phrase "like dissolves like" refers to the fact that ____________. a. Polar solvents dissolve nonpolar solutes and vice versa b. Sovents can only dissolve solutes of similar molar mass c. Gases can only dissolve other gases d. Polar solvents dissolve polar solutes and nonpolar solvents dissolve nonpolar solutes  e. condensed phases can only dissolve other condensed phases

2. If you perform a dilution ofa 5X solution to 100 ml of a 0.5X solution, how would you determine the volume of the 5X solution and the diluent to use? A. Show the amount that you calculated of the 5X solution. B. How much diluent do you add to the solution to generate the 0.5X solution?

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Materials Needed solid I2 solid CUSO4-5H20 food dye solid (NH4)2SO4 heavy metals waste container halogenated waste container non-halogenated waste container semi-micro test tubes and rack regular test tubes and rack squash pipettes acetone cyclohexane propan-2-ol Method Part A: Solubility of ionic and molecular solids 1. Place a small amount (about the size of 1 grain of rice, see picture) of copper sulfate into each of three DRY semi-micro test tubes. Add 20 drops of water to the first test tube and gently flick the test tube with your finger to ensure mixing. 2. Repeat step 1 using acetone in place of water as the solvent in the second test tube. 3. Repeat step 2 replacing acetone with cyclohexane in the third test tube. Hold the test tubes against a white background to compare the solubility of copper sulfate in the three solvents and record your results. Discard these mixtures into the heavy metals waste container in the fume cupboard. Once these test tubes have been emptied you…

15 g of solute is mixed with 100. g of solvent. The m/m% of this solution must be ___________ 15%.   Question  options:   less than   equal to   greater than

You have a stock solution of 50% (w/v) sodium nitrate and you were asked to prepare 300 mL of a 10% (w/v) solution. How many ml are needed? O a. 15 mL O b.90 mL Oc. 60 mL O d. 20 ml e. 30 mL

part A 1. Concentration of Known NiCl2 Stock Solution ___500________ mM   Tube Number   Blank #1 #2 #3 #4 #5 2. Volume of Known NiCl2 Stock Solution Pipetted Into Tube 0.00 mL 1.50 mL 3.00 mL 4.50 mL 6.00 mL 7.50 mL 3. Volume of Distilled Water Pipetted Into Tube 11.00 mL 9.50 mL 8.00 mL 6.50 mL 5.00 mL 3.50 mL 4. Total Volume of Solution In Tube 11.00 mL 11.00 mL 11.00 mL 11.00 mL 11.00 mL 11.00 mL 5. Diluted Concentration of NiCl2 In Tube ----------- 68.2 mn 136mn 204mn 273mn 341mn 1. Equation for the Best-Fit Straight Line Y=3822x+4.7446 2. Absorbance at λmax for Diluted Unknown 0.87 3. Concentration of NiCl2 in Diluted Unknown 25.693 mM Determine the dilution factor for your diluted unknown U1 based on how you prepared the solutions in Part A. Record this on your report sheet in Part D #4.

1. Solubility Test Table 1. Results for the solubility test. OBSERVATION* INFERENCE SAMPLE Ethyl acetate ** Нехаne Methanol Water Coconut oil Vitamin E Beef fat Miscible (soluble) or immiscible (insoluble) ** polar or nonpolar Sudan IV Test Table 2. Results for Sudan IV test. OBSERVATION* INFERENCE SAMPLE Нехаne Ethyl acetate Methanol Water ** Coconut oil Vitamin E Beef fat Homogeneous or heterogeneous mixture ** polar or nonpolar

KNO3 (aq) added to CaC2O4 (Ksp = 1.3 x 10-8) in solution will lead to __________ in solubility of the solid     no effect then decrease     increase              no effect

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Name: Date: Section: Prelaboratory Assignment: Determination of the Hardness of Water 1. A 0.512 g sample of CaCO, is dissolved in 12 M HCl and the mixture is diluted to 250 mL. a) How many moles of CaCO, are used? moles b) What is the [Ca²*] in the 250 mL solution? b) How many moles of Ca²* are in a 25 mL sample of the 250 mL solution? moles

pter 14 - Solutions - Homework - 2022.pdf - Adobe Acrobat Pro DC (32-bit) Edit View E-Sign Window Help me Tools Chapter 14 - Soluti. x 1 /3 早2 a. D 135% 5) Commercial grade HCl solutions are typically 39.0% (by mass) HCl in water. Determine the molarity of the HCl, if the solution has a density of 1.20 g/mL. 5) 3:18 F 2/8/20 To Im ort e noitufo arb lo viemb D) q ()

Do the dilutions for the given concentration.

For 1-4. A solution is 90% H2SO4 has a density of 1.84 g/ml. Find the 15. mole fraction of the solute, 16. molarity, 17. molality and 18. normality of the solution   1. Mole fraction of the solute  A. 0.62 B. 0.92 C. 0.38 D. 0.56 2. Molarity  A. 6.2M B. 0.62M C. 1.701M D. 17.01M 3. Molality A. 92m B. 0.92m C. 0.092m d. 9.2m 4. Normality  A. 1.24 N B. 12.4 N C. 34.02 N D. 3.4 N

Procedure A: Molarity (M=g/MM/L) Step 1. Place one-eighth of a teaspoon (this weighs approximately 0.5 grams) of NaCl (table salt) in the graduated cylinder provided. Then add distilled water to that graduated cylinder until the level of the water reaches 45.00 mL. Mix thoroughly about 1 minute. Pour solution into a somewhat clear cup. Remember what this looks like for Procedure B. Questions: Is this a saturated solution? Why or why not? Take a picture and insert a picture (compress your image) of your solution here. Save this solution for Step 2. Calculations: Determine the Molarity of this solution using the formula M = g/MM/L. You know the grams (one-eighth of a teaspoon weighs approximately 0.5 grams), look up the Molar Mass of NaCl, and convert your mL to L to solve the problem.) Show your calculations for Molarity here. C % 31 D < hp & * ✔

a. How many mL of methyl alcohol are required to make a 8.79% (v/v) aqueous solution in a 300.mL volumetric flask? ___mL   b. How many mL of methyl alcohol are required to make a 5.92% (v/v) aqueous solution in a 500.mL volumetric flask? ___mL