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Experiment 10: VOLUMETRIC ANALYSIS OF ANTACID TABLETS
Chemistry - 1131
By: Mohammad Shaikh
Lab Partner: Sahil Khan
Submitted to: Dave Duncan
Date –November 27, 2023
Introduction:
In this sedentary modern life and by overconsumption of meat products,
humans are facing issues digesting all the food and several times it results in acidity.
There are many types of antacid tablets available in the market. Here, one of the
antacid tablets (Tums) is analyzed in the laboratory by doing titration by which one can
understand how much 0.2M HCl (stomach acid) can be neutralized by 1 tablet of Tums.
Objective: To determine the amount of HCl (in mEq) neutralized by 1 antacid tablet by
titration with methyl orange indicator.
Procedure: In this experiment, Tums tablet was crushed and placed into the
Erlenmeyer flask which was then topped up to 50 ml of deionized water and stirred well.
Full titration was done by filling 0.2M HCl in buret and using methyl orange as an
indicator in the Erlenmeyer flask. Full procedure of the experiment is referred from
Stathopoulos;
Chemistry 1 Laboratory Manual; Durham College: Oshawa, 2023
;
p 36-
38. Note: 15 drops of methyl orange were used in the titration, because it was old, besides
10ml as mentioned in previously referred lab manual.
Chemical Reactions: (1)
2HCl + CaCO
3 → CaCl
2
+H
2
O + CO
2
Observations: Table 1: Titration of Tums tablet (orange): First Trial
Trial
Initial Reading
(mL)
Final Reading
(mL)
Total amount
Dispensed(mL)
1 (Orange
Tablet)
0.02
50.00
49.98
0.95
49.90
48.95
0.90
12.65
11.75
7.40
22.50
15.10
So Total amount of HCl got neutralized was 49.98 +48.95 + 11.75+ 15.10 = 125.78 mL
At the end of the titration, Solution was pink with some ppt. at the bottom.
Table 2: Titration of Tums tablet (white): (second trial)
Trial
Initial Reading
(mL)
Final Reading
(mL)
Total amount
Dispensed(mL)
2 (white Tablet)
1.97
49.40
47.43
1.32
49.68
48.36
1.60
49.65
48.05
0.55
7.40
6.85
So, Total amount of HCl got neutralized was 47.43 + 48.36+ 48.05+ 6.85= 150.69 mL At the end of the titration, Solution turned pink with some ppt. at the bottom.
Table 3: Titration of Tums tablet (white): (third trial)
Trial
Initial Reading
(mL)
Final Reading
(mL)
Total amount
Dispensed(mL)
3 (white Tablet)
0.43
49.85
49.42
0.15
49.95
49.80
0.60
12.20
11.60
So Total amount of HCl got neutralized was 49.42 + 49.80 + 48.05+ 11.60= 110.82 mL At the end of the titration, Solution turned faint pink with some ppt. at the bottom.
Calculation: 1.
Average amount of HCl got neutralized.
= addition of total amount of dispensed HCl / 3
=125.78+150.69+110.82 mL / 3
=
129.10 mL
2.
To convert it in to mEq 129.10 mL × 0.2mol × 1000m / 1000mL
= 25.81 mmol HCl
For HCl, 1mmol of HCl = 1 mEq
So, mEq =
25.81mEq
Discussion: Titration is a basic technique to do neutralization of acid and base. One can use this for
practical use to find efficiency of antacid tablets which is generally getting used in large
amount in the modern era. Student can do this by getting HCl of similar concentration
as gastric acid and neutralize it by dissolving one antacid tablet with having methyl
orange as indicator.
By this experiment, 129.10 mL gastric acid did get neutralized which is 25.81mEq.
Lab-Question:
1.
Methyl orange shows clear and distinct color variance at various pH values which
is essential in Titration.
2.
Milk of Magnesia:
Mg(OH)
2
+ 2HCl → MgCl
2 + H
2
O
Tums:
2HCl + CaCO
3 → CaCl
2
+ H
2
O + CO
2
Eno:
NaHCO
3
+ HCl → NaCl + H
2
O + CO
2
Rolaids:
NaAl(CO
3
)(OH)
2
+ 4HCl → NaCl + AlCl
3
+ CO
2
+ 3H
2
O
3.
275mL 0.98M H
+
= 0.98mol/L × 275mL
=269.50 mmol
=269.50 mEq
only 25.81mEq will be neutralized So, percentage of gastric acid which would get neutralized =25.81 mEq × 100 % / 269.50 mEq
=9.577%
Conclusion: In conclusion, one can see 25.81mEq of HCl got neutralized by the
titration with methyl orange which fulfill the objective of the experiment.
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References:
1.
Stathopoulos D; Chemistry 1131 Laboratory Manual; Durham College: Oshawa;
2023; p 36 - 38.
2.
What is the role of methyl orange in acid base titration
; toppr.com )
; (accessed date : 2023-12-04)
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