Blackbody Radiation

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Towson University *

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161

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Chemistry

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Jan 9, 2024

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docx

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ASTR 181 Lab Write Up: Blackbody Radiation Spring 2023 Names: Corey B , Brian H Group # 3 When answering questions, please respond as concisely as you can. When answers must be calculated, show all work and answer all questions. Use scientific notation in E-notation format. Show units when they are not expressed in the step. Objective In this lab exercise, you will use a simulator to investigate some generic properties of blackbodies radiation and Wein's Displacement Law. Background Everything emits Electromagnetic (EM) radiation. The Sun does, operating incandescent lights do, we do, buildings do (stand near a brick building's west wall just after sunset; you can feel the heat radiating!). Anything at a higher temperature than its surroundings gives off some kind of EM radiation. The amount of power liberated in the form of EM radiation depends on the object's temperature (which we can measure in degrees or Kelvins) and its size (surface area, which we can measure in square meters (m 2 )). As you will find out, the wavelength of the EM radiation is related to temperature. The Range of Visible Light Access the PhET Blackbody simulator . You will be presented with the Planck curve of a blackbody at a temperature of 5800 K (approximately the same temperature as the surface of the Sun). The plot is of Spectral Power Density (essentially, the "intensity" of the radiation measured in megawatts per square-meter per micron) vs. wavelength (measured in microns or millionths of a meter). Consider the visible part of the spectrum. What is its approximate wavelength range? To make our measurement easier, check the Graph Values checkbox in the upper right, then drag the slider that appears on the curve toward the violet and red edges of the visible spectrum. As you do so, the intensity and wavelength values of the slider's position will update. 1. Find the approximate range of wavelengths of the visible spectrum, and estimate your numbers to the nearest hundredth of a micron (don't forget to include leading zeros before your decimal point if necessary). Violet starts at 0.397 Red starts at 0.638 Converting Between Units One micron is one-millionth of a meter or 10 -6 meter. To convert microns to meters, multiply the wavelengths from step 1 by 10 -6 meters. For example, we can convert 0.42 µm into meters as: Express your answer in scientific "E" notation. We can express your answer in E-notation format by entering 4.2E-7. 2. Convert your range of visible wavelengths in step 1 into meters. Use E- notation format.
Violet 4E-7 = (0.40um)x(10^-6m) Red 6.4E-7 = (0.64 um)x(10^-6m) In Physics, most wavelength measurements are in nanometers (nm) or 10 -9 meters. 3. Convert your range of visible wavelengths into nanometers. Violet 4E-9 nanometers (0.64 um)x(10^-9m) Red 6.4E-9 nanometers (0.64 um)x(10^-9m) The temperature of this blackbody is 5800 K, but how hot is that in more everyday terms? Fortunately, converting kelvins into degrees Celsius is pretty straightforward, as the difference is precisely 273.15. In other words: While converting into degrees Fahrenheit is 4. Convert 5800K to degrees Celsius and Fahrenheit to within a hundredth of a degree. Celsius: 5526.85 Fahrenheit: 9980.33 Colors of 5800 K Blackbody The starburst symbol at the top of the simulator represents the color of the blackbody as seen by your eyes. 5. What color is this "blackbody" as you see it? White or light gray Of the three primary colors (blue, green, red), notice that the blackbody curve peaks somewhere in the visible part of the spectrum. 6. Which color is this object producing the most? In other words, where does the 5800 K curve peak? Green is produced the most at 5800 K. 7. At what wavelength is visible light intensity the most and the least? Most 0.509 m m Least 0.772 m m Detecting EM Wavelengths Outside of the Visible Range 8. Would a camera that responds only to infrared light be able to detect this EM source? Explain why or why not. No, because if it only responds to infrared light it wouldn’t be able to detect visible light. 2
9. Would a camera that responds only to ultraviolet light be able to detect this EM source? Explain why or why not. No, because if it only responds to ultra violet light it wouldn’t be able to detect visible light. Blackbody of an Incandescent Bulb Using the scrollbar to the right of the spectrum, lower the temperature to approximately that of an incandescent light bulb. NOTE: As the spectrum changes shape, you may need to use the zoom buttons on the vertical and horizontal axes to keep the blackbody curve in view. 10. At approximately what wavelength does the blackbody curve of the light bulb hit its peak? It peaks at about 0.977. 11. Describe the change in the shape of the graph from a 5800 K to a 3090 K blackbody. In particular, describe what happens to the peak. For example, does it go out of the visible range (as marked by the rainbow)? The peak at 3000 K goes out of the range of visible light into the infrared range while as at 5800 K the peak is in the center of visible light. Earth's blackbody radiation Now lower the temperature to about 300 K, the average temperature of Earth's surface. Zoom in as needed to bring the spectrum into view. 12. What wavelength does the Earth's blackbody radiation peak? Earths blackbody radiation peaks at 9.659 13. What part of the electromagnetic spectrum is this? Its in the infrared range of the electromagnetic spectrum 14. Consider the R, G, B, and the starburst colors. Could you see this object in real life with your eyes? Explain why or why not. No, because its not in the visible light range its in the infrared range. 15. Considering our other senses, how else might we detect this object's radiation? We could sense heat with our skin. Earth's temperature isn't thousands of degrees, yet we see light from it. 16. Where does this light come from? The light comes from the sun. 3
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