Lab 1 CYSE 230

Using the photo provided, what are the following answers MAC Destination Address:MAC Source Address:MAC Type (Length):IP Version #:IP Header Length:IP Type of Service:IP Total Length:IP Identification:IP Fragment Flag|Offset:IP Time-to-live:IP Next Protocol:IP Header Checksum:IP Source address:IP Destination address:TCP source port:TCP destination port:TCP Sequence number:TCP Acknowledgement number:TCP Window size:TCP Checksum:

10. Don't explain ... just tell me which is right... solve only if you are 100% sure

Thanks

Please provide explaination. Thank you!

Tunneling procedure? Which three tunneling protocols exist?

Assume a computer is sending the following 3 bytes of data: 89 241 72 over UDP. The data is being sent from port 59700 to port 443 What is the checksum that should be included with the packet? Your answer should be 16 bits long. Make sure you include both the packet header and the payload in the checksum calculation. Show your work.

Suppose an Ethernet packet represents a TCP acknowledgment; that is, the packet contains an IPv4 header with no options and a 20-byte TCP header but nothing else. Is the IPv4 packet here smaller than the Ethernet minimum packet size, and, if so, by how much? What if the packet is IPv6 with no extension headers?

Show the original (unabbreviated) form of the following IPv6 addresses. FDEC: 74 : : BOFF : 0 : FFFO 0 : 15 :: 1 : 12 :1213

The IPV4 Header Header And Its Fields Are Given For Your Reference. Read the questions that follow the Header diagram. IPV4 Header Byte Offset IHL (Header Length) Version Type of Service (TOS) Total Length IP Flags x D M 4 Identification Fragment Offset 20 Time To Live (TTL) Protocol Header Checksum Bytes II I I I IHL (Internet Header Length) 12 Source Address 16 Destination Address 20 IP Option (variable length, optional, not common) Bit To 1 2 3 4 5 6 78 9 0 1 2 3 4 56 7 89 Nibble FByte Word 2 314 5 6 7 8 9 0 Version IP Flags Protocol Fragment Offset Version of IP Protocol. 4 and 6 are valid. This diagram represents version 4 structure only. IP Protocol ID. Including (but not limited to): 1 ICMP 17 UDP 2 IGMP 47 GRE 88 EIGRP 6 TCP 9 IGRP 51 AH Fragment offset from start of IP datagram. Measured in 8 byte (2 words, 64 bits) increments. If IP datagram is fragmented, fragment size (Total Length) must be a multiple of 8 bytes. x DM 57 SKIP x Ox80 reserved (evil bit) D Ox40 Do Not…

Write down of shorter form the following IPv6 addresses: 0000:0000:0000:0000:0000:0000:0000:0001, 2001:0DB8:0000:A300:ABCD:0000:0000:0123 Can the following IPv6 addresses exist? (Justify your answer!): 2001:DB9:0000:AA:1::1111; FF02:1001::A1:0000::F; FE80:AAAA:0001:FFFF::0; 8080:0011:AD:5000:99:10.

A received UDP packet is broken into 16-bit chunks and the chunks are added together with any carry-out on the left wrapped around to the right. The resulting value is 0011001100110010 For the packet to be accepted by the UDP receiver, what must the checksum be?

Change the following IPv4 addresses from binary notation to dotted-decimal notation.       I. 10000001    00001011    00001011     11101111       ii.11000001   10000011     00011011     11111111 Show the original (unabbreviated) form of the following IPv6 addresses. FDEC: 74 :  :  BOFF : 0 : FFFO 0 : 15 :  : 1 : 12 :1213 Explain the term Network Address Translation (NAT). What is the need for the network layer?  State four advantages that IPv6 has over IPv4

is DORA protocol initiated by the Server? Which of the following packets are broadcasts during renewal? DISCOVER OFFER REQUEST ACK or None of the above  and justify the above answer   Why does DISCOVER and REQUEST need to be broadcasted?

Can you tell me which protocol does not have the ability to buffer out-of-order packets?

Answers should all be in lowercase with no spaces between hex characters when hexadecimal is the answer expected.  All hex values must start with 0x, which stands for hexadecimal and therefore include 0x in your answers. Q1: What Transport protocol is encapsulated in the packet trace? Answer: The Transport protocol is encapsulated in the packet trace is:   Q2. What is the value in hexadecimal of the  Destination port address? Answer: The  value in hexadecimal of the  Destination Port Address is:   Q3: What is the value in hexadecimal of the Transport header Checksum? Answer: The value in hexadecimal of the Transport header Checksum is:   Q4: What is the value in hexadecimal of the Sequence Number? Answer: The value in hexadecimal of the Sequence Number is:   Q5: What is the value in hexadecimal of the Source Transport Port Address? Answer: The value in hexadecimal of the Source Port Address is:

In protocol rdt3.0, the ACK packets flowing from the receiver to the sender do not have sequence numbers, although they do have an ACK field that contains the sequence number of the packet they are acknowledging. Why is it that ACK packets do not themselves require sequence numbers?

Given IPV6 address 7000:0db8: cafe: 0000:0835:0000: 0000:0100. Write the most compressed form after applying Omit leading and Omit all 0 segments

The first of these packets is from your computer to the DHCP server telling it to release the lease on your IP address.  The next 4 packets renew that lease.  Note that the source address on the “DHCP Discover” and “DHCP Request” packets is 0.0.0.0.  This indicates that your computer does not actually use its new IP address until the interchange has completed.  Also note that the destination address in each of the 4 packets is a broadcast address[1].  It should be obvious to you why the first two packets are broadcasted, but what about the last two?  Can you explain this? Answer the questions in your Word document right after you post a snapshot of the DHCP packet screen. (#4)

In term of encapsulation, please explain how a message from Source can be transmitted toDestination. Please explain what happen in each layer

Note: answer already available in bartleby is wrong and not detailed ...don't copy the wrong answer and paste here ..I will downvote    IP address: 200.172.138.62 11001000.10101100.10001010.111110   Subnet mask: 255.255.255.240 (/28) 11111111.11111111.11111111. Subnet address: 200.172.138. 11001000.10101100.10001010.   Please show the complete work out and explanations. That includes the slash notation and most importantly how to the do subnet mask.

What are the facts regarding the UDP protocol?Answer choices group The UDP header includes information for the source and destination ports. UDP is a connection-oriented protocol. Congestion Control is supported by UDP. Incorrect packets are retransmitted via UDP.

Determine whether or not the following IPv6 address notations are correct:•::0F53:6382:AB00:67DB:BB27:7332•7803:42F2:::88EC:D4BA:B75D:11CD•::4BA8:95CC::DB97:4EAB•74DC::02BA•::00FF:128.112.92.116