maze

A "generic" data structure cannot use a primitive type as its generic type. O True False

using namespace std; class SinglyLinkedListNode { // INSERT YOUR CODE HERE }; class SinglyLinkedList { public: SinglyLinkedListNode *head; SinglyLinkedListNode *tail; SinglyLinkedList() { this->head = nullptr; this->tail = nullptr; } voidinsert_node(intnode_data) { // INSERT YOUR CODE HERE } }; void free_singly_linked_list(SinglyLinkedListNode* node) { // INSERT YOUR CODE HERE } // Complete the has_cycle function below. /* * For your reference: * * SinglyLinkedListNode { * int data; * SinglyLinkedListNode* next; * }; * */ bool has_cycle(SinglyLinkedListNode* head) { SinglyLinkedListNode* temp = head; bool isCycle = false; while (temp != nullptr) { // INSERT YOUR CODE HERE } } int main() { // INSERT YOUR CODE HERE TO TEST YOUR CODE return0; }

using namespace std; class SinglyLinkedListNode { // INSERT YOUR CODE HERE }; class SinglyLinkedList { public: SinglyLinkedListNode *head; SinglyLinkedListNode *tail; SinglyLinkedList() { this->head = nullptr; this->tail = nullptr; } voidinsert_node(intnode_data) { // INSERT YOUR CODE HERE } }; void free_singly_linked_list(SinglyLinkedListNode* node) { // INSERT YOUR CODE HERE } // Complete the has_cycle function below. /* * For your reference: * * SinglyLinkedListNode { * int data; * SinglyLinkedListNode* next; * }; * */ bool has_cycle(SinglyLinkedListNode* head) { SinglyLinkedListNode* temp = head; bool isCycle = false; while (temp != nullptr) { // INSERT YOUR CODE HERE } } int main() { // INSERT YOUR CODE HERE TO TEST YOUR CODE return0; }

def drop_uninformative_objects(X, y):# your code herereturn X_subset, y_subset     # TEST drop_uninformative_objects functionA = pd.DataFrame(np.array([[0, 3, np.nan],[4, np.nan, np.nan],[np.nan, 6, 7],[np.nan, np.nan, np.nan],[5, 5, 5],[np.nan, 8, np.nan],]))b = pd.Series(np.arange(6))A_subset, b_subset = drop_uninformative_objects(A, b) assert A_subset.shape == (3, 3)assert b_subset.shape == (3,)

In C, define: List addAt(List head, int item,int pos);

void listEmployees (void) { for (int i=0; i 10000. Make a guess about why the comparison function takes 2 struct Employee parameters (as opposed to struct Employee *) **

Please code in C language. Please use the starter code to help you solve the deleted node and the reverse list. Here is the starter code: #include <stdio.h> #include <ctype.h> #include <stdlib.h> #include <string.h>   #include "linkedlist.h"   // print an error message by an error number, and return // the function does not exit from the program // the function does not return a value void error_message(enum ErrorNumber errno) {   char *messages[] = {       "OK",       "Memory allocaton failed.",       "Deleting a node is not supported.",       "The number is not on the list.",       "Sorting is not supported.",       "Reversing is not supported.",       "Token is too long.",       "A number should be specified after character d, a, or p.",       "Token is not recognized.",       "Invalid error number."};     if (errno < 0 || errno > ERR_END)     errno = ERR_END;   printf("linkedlist: %s\n", messages[errno]); }   node *new_node(int v) {   node *p =…

Using the code source screenshot (C++) explain in depth what each line of code does.

define fl(i,a,b) for(i=a;i<b;i++)   #define fast ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);   using namespace std;   typedef long long int ll;       string int_to_roman(ll n)   {   string str="";   // store all base values in vector in descending order   vector <int > v ={1000,900,500,400,100,90,50,40,10,9,5,4,1};       // store roman numeral equivalent of each base value using map   map <int, string> m ={{1000,"M"}, {900,"CM"},{500,"D"},{400,"CD"},{100,"C"},{90,"XC"},{50,"L"},{40,"XL"},{10,"X"},{9,"IX"},{5,"V"},{4,"IV"},{1,"I"}};       //now find the largest base value   //dividing the number and repeat the symbol accordingly       for(auto x: v)   {   if(n>0)   {   int i= n/x;   n= n%x;   while(i--)   str+= m[x]; //repeating the correspoding roman symbol   }   else   return str;   }   return str;   }       int main()   {   fast;       ll n; cin>>n;…

In C, using malloc to allocate memory for a linked list uses which memory allocation scheme? Heap allocation Static allocation

int machineCompare1(struct machine* mac1, struct machine* mac2){    struct mac1;    struct mac2;    char make1[21], make2[21];    char model1[51], model2[21];     if((lap1 -> make1 == lap2 -> make2) && (lap1 -> model1 == lap2 -> model2))        return 0;    else        return 1;} have to create function to compare make and model of 2 machines - it's using structures - not sure if this is correct/ on the right track?

given code lab4   #include <stdio.h>#include <stdlib.h> /* typical C boolean set-up */#define TRUE 1#define FALSE 0 typedef struct StackStruct{int* darr; /* pointer to dynamic array */int size; /* amount of space allocated */int inUse; /* top of stack indicator - counts how many values are on the stack */} Stack; void init (Stack* s){s->size = 2;s->darr = (int*) malloc ( sizeof (int) * s->size );s->inUse = 0;} void push (Stack* s, int val){/* QUESTION 7 *//* check if enough space currently on stack and grow if needed */ /* add val onto stack */s->darr[s->inUse] = val;s->inUse = s->inUse + 1;} int isEmpty (Stack* s){if ( s->inUse == 0)return TRUE;elsereturn FALSE;} int top (Stack* s){return ( s->darr[s->inUse-1] );} /* QUESTION 9.1 */void pop (Stack* s){if (isEmpty(s) == FALSE)s->inUse = s->inUse - 1;} void reset (Stack* s){/* Question 10: how to make the stack empty? */ } int main (int argc, char** argv){Stack st1; init (&st1);…

#include <bits/stdc++.h> using namespace std;  // Structure of a Node struct Node {  int data;s struct Node *next; struct Node *prev; };   // Function to insert at the end void insertEnd(struct Node** start, int value) { // If the list is empty, create a single node // circular and doubly list   if (*start == NULL)   { struct Node* new_node = new Node;  new_node->data = value; new_node->next = new_node->prev = new_node; *start = new_node; return;   }  // If list is not empty  /* Find last node */ Node *last = (*start)->prev; // Create Node dynamically   struct Node* new_node = new Node; new_node->data = value;  // Start is going to be next of new_node   new_node->next = *start;  // Make new node previous of start  (*start)->prev = new_node;    // Make last preivous of new node   new_node->prev = last;    // Make new node next of old last     last->next = new_node; }  // Function to insert Node at the beginning // of the List, void insertBegin(struct…

Answer the given question with a proper explanation and step-by-step solution. #include<stdio.h>#include<stdlib.h>#include"NoteSynth.c" typedef struct BST_Node_Struct{ double key;double freq;int bar;double index;/*** TO DO:* Complete the definition of the BST_Node_Struct***/  } BST_Node; BST_Node *newBST_Node(double freq, int bar, double index){ /*** TO DO:* Complete this function to allocate and initialize a* new BST_Node. You should make sure the function sets* initial values for the data in the BST_Node that can* never occur in an actual musical note from a score!****/  return NULL;} BST_Node *BST_insert(BST_Node *root, BST_Node *new_node){/** This function inserts a new node into the BST. The* node must already have been initialized with valid* note data, and must have its unique key.** The insert function must check that no other node* exists in the BST with the same key. If a node with* the same key exists, it must print out a message* using the following format…

Assign currentSize with the size of the sensorReadings vector. 434056.2330114.qx3zqy7 #include #include using namespace std; int main () { vector> input; sensorReadings.resize (input); /* Your solution goes here cout << "Number of elements: << current Size << endl; return 0; "1 li

struct node{ int a; struct node * nextptr; };   Write two functions. One for inserting new values to a link list that uses the given node structure. void insert(struct node **head, int value); Second function is called to count the number of even numbers in the link list. It returns an integer that represents the number of even numbers. int countEvenNumbers(struct node *head); Write a C program that reads a number of integers from the user and insert those integers into a link list (use insert function). Later pass the head pointer of this link list to a function called countEvenNumbers. This function counts and returns the number of even numbers in the list. The returned value will be printed on the screen. Note 1: Do not modify the function prototypes.   Sample Input1:          Sample Output1: 45 23 44 12 37 98 33 35 -1 3   Sample Input2:          Sample Output2: 11 33 44 21 22 99 123 122 124 77 -1 4