2016 SYST465 HW 7 Solutions

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Apr 3, 2024

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1 SYST 465 001 ECON 496 002 Math 493 002 Homework 7 Solutions - Spring 2016 Problem 1 (20 points) Use the Brown-Robinson algorithm to find the optimal strategies for the row and the column player of the following zero-sum matrix game: (If there is a tie, use a pure strategy.) Complete 3 full iterations for each player. 9 6 4 3 5 10 The x player starts with strategy: x 0 =( 1/2, 1/2) The y player starts with strategy: y 0 = ( 1/3, 1/3, 1/3) Iteration : 1 x –player assumes that y-player uses y 0 . y –player assumes that x player uses x 0 . Choose Find the averages: Iteration :2 x-player assumes that y–player uses y –player assumes that x player uses . Find the averages: Iteration : 3 x-player assumes that y–player uses
2 y –player assumes that x player uses . Find the averages: XXXXXXXXXXXXXXXXXXXXXX Iteration : 4 x-player assumes that y–player uses y –player assumes that x player uses . Choose Find the averages: Iteration : 5 x-player assumes that y–player uses y –player assumes that x player uses . Find the averages: Check with LINDO: MAX y1 + y2 + y3 SUBJECT TO S1) 9 y1 + 6 y2 + 4 y3 <= 1 S2) 3 y1 + 5 y2 + 10 y3 <= 1 C1) y1 >= 0 C2) y2 >= 0
3 C3) y3 >= 0 END LP OPTIMUM FOUND AT STEP 3 OBJECTIVE FUNCTION VALUE 1 ) 0.1750000 = 35/200 VARIABLE VALUE REDUCED COST Y1 0.000000 0.275000 y1 = 0 Y2 0.150000 0.000000 y2 = 30/200 Y3 0.025000 0.000000 y3 = 5/200 ROW SLACK OR SURPLUS DUAL PRICES S1) 0.000000 0.125000 = 1/8 = 25/200 S2) 0.000000 0.050000 = 5/100 = 10/200 C1) 0.000000 0.000000 C2) 0.150000 0.000000 C3) 0.025000 0.000000 (Normalize!) Optimal values x* = (0.714, 0.286); y* = (0, 0.857, 0.143); v = 5.714 Problem 2(20 points) (Kornai-Liptak) Consider the following LP with block structure: [FYI: Optimal solution: x1 = 2.778; x2 = 2.889; x3 = 7.139; x4 = 2.153; z = 79.04 This solution assigns 14.22 units of the common resource eggs to the first subsystem and 45.78 units of the common resource eggs to the second system.] a) Allocate half of the common resource in each subsystem and formulate the primal and dual LP for each of the subsystems. Subsystem 1 Subsystem 2
4 b) Graph the feasible region of each dual LP and find the corresponding feasible extreme points. Subsystem 1 v 4 5/4 (0,11/18,17/18) = (0,0.611,0.944) 4/5 v (11/10,0,7/10) =(1.1,0,0.7) 5/2 4/3 y 5/2 Vertices: { (0,0,0), (5/2, 0, 0), (0, 5/2,0), (0, 0,5/4), (4/3,0,0), (0,4/5,0), (0,0,4), (11/10,0.7/10), (0, 11/18,17/18) } Feasible vertices: ={ (5/2,0,0), (11/10,0,7/10), (0,11/18,17/18), (0,5/2,0), (0, 0, 4) } Subsystem 2 w 5/2 6/5 (0,13/28,31/28) (13/32,0,7/8) 6 w
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