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Here is a typical statement made by the media: "Based on a recent study, pennies weigh an average of 2.5 grams with a margin of error of 0.006 gram." What important and relevant piece of information is omitted from that statement? Is it OK to use the word "average"? Choose the correct answer below. (O A. The media often omit reference to the confidence level, which is typically 95%. It is OK to use the word "average" in this context. (O B. The media often omit reference to the confidence interval. It is OK to use the word "average" in this context. () €. The media often omit reference to the confidence interval. The word "mean" should be used instead of the word "average." ® D. The media often omit reference to the confidence level, which is typically 95%. The word "mean" should be used instead of the word "average."
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Related Questions
Use the body temperatures, in degrees Fahrenheit, listed in the accompanying table. The range of the data is 3.3°F. Use the range rule of thumb to estimate the value of the standard deviation. Compare the result to
the actual standard deviation of the data rounded to two decimal places, 0.69°F, assuming the goal is to approximate the standard deviation within 0.2°F.
The estimated standard deviation is °F.
(Round to two decimal places as needed.)
Compare the result to the actual standard deviation.
The estimated standard deviation is
C
the actual standard deviation. Thus, the estimated standard deviation
Data table
the goal.
99 98.2 97.5 98.4 99.2 98 98.7 98.5 98.1 98.1 98.5 99.3
98.7 96.7 96.5 98.7 98 97.3 98.4 98 97.7 98.3 98.9 97.1
99 97.1 98.7 98.6 99.4 97.6 97.6 97.7 97.9 99.4 98.7 99.6
97.8 97.9 99 98.3 97.7 98.7 98.2 98.7 97.6 98 97.7 98.6
98.5 98.3 97.7 99 96.3 98 98.2 96.8 97.3 97.3 97.5 98.5
97.6 97.7 97.2 97.7 98 98.8 99 98.5 98 97.8 97 97.3
99.1 98.7 98.6 98.3 98.4 99 98…
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Question 16
The probability of an 60 year-old male living to 70 years old is equal to
in 2019. (Art_13_07_B)
78.2%
85.3%
70.2%
087.2%
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f (x, y) = 3x² + y³ + 4xy² +8
Of(x,y)
dr
Of(x,y)
dy
What is the value of
when x = 4 and
y = 5?
(Note: the answer may not be a whole
number, so please round to the nearest
hundredth)
(Note: the numbers may change between
questions, so read carefully)
arrow_forward
To solve:
A manufacturer of high-tech computing equipment must decide whether or not to
continue development of a new promising technology. continuing the development would
cost $2 Million. If the development is continued, then a patent is either awarded or not.
70% chance that the patent will be awarded and
The best estimate is that there is a
a 30% chance that it will not.
if the patent is awarded, the company needs to decide whether or not to license the
technology. it does, it would receive a total of $25 million in licensing royalties.
However, the
company
could also produce and sell the technology in-house (at. a cost of
$10 million), in which case there is an additional uncertainty about the demand for the
technology. if the demand is high (p = 0.25), the company would make $55 Million in
revenues, if the demand is medium (p = 0.55) the company would make $33 Million and if
the demand is Low (p = 0.20) the company would still make $15 Million.
a) Draw and solve a decision tree…
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MEAN ABSOLUTE DEVIATION
Q.1) Find the mean absolute deviation for the set below. S = {85, 90, 68, 75, 79}
A.
В.
C.
D.
79.4
6.48
32.4
79
Sherrie just registered for her wedding. So far 6 items have been fulfilled on her registry. Find the
Q.2)
mean price of the fulfilled items. $29, $58, $15, $129, $75, $22
43.5
129
54.7
114
А.
В.
С.
D.
Find the mean absolute deviation of the fulfilled items on Sherrie's registry. $29 , $58, $15, $129,
Q.3)
$75, $22
196
54.7
114
32.67
C.
D.
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2. A city had an unemployment rate of 7%. The mayor pledged to lower this figure and supported programs to decrease unemployment. A group of citizens wanted to test with 0.032 label of significance if the unemployment rate had actually decreased, so they obtained a random sample of 500 citizens to see what proportion of the sample was unemployed. Only 32 citizens in the above sample is still unemployed. What is the probability of Type II error if the actual unemployment rate is 6.5% please don't use software everything needs to be done by hand. Explain because I don't understand my professor.
Note:-
Do not provide handwritten solution. Maintain accuracy and quality in your answer. Take care of plagiarism.
Answer completely.
You will get up vote for sure.
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A property owner is faced with a choice of:
A large-scale investment to improve her flats. This could produce a substantial pay-off in terms of increased revenue net of costs but will require an investment of 1.4 million pesos. After extensive market research it is considered that there is a 40% chance that a pay-off of 2.5million will be obtained, but there is a 60% chance that it will be only 800,000 pesos.
A smaller scale project to re-decorate her premises. At 500,000 pesos this is less costly but will produce a lower pay-off. Research data suggests a 30% chance of a gain of one million pesos but a 70% chance of being only 500,000 pesos.
Continuing the present operation without change. It will cost nothing but neither will it produce any pay-off. Clients will be unhappy and it will become harder to rent the flats out when they become free.
What is the best alternative? Use decision tree analysis.
arrow_forward
Q.3 What is the difference between ordinary least square and maximum likelihood ( ML ) estimators ? Also discuss their properties ?
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Answer asap
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FIVE. Which of the following is true about standard deviation?
The first step in calculating the standard deviation is calculating the square root.
The second step in calculating the standard deviation is to subtract each measurement from the intermediate value and then square that difference.
The last step in calculating the standard deviation is to sum the squared values and divide by the number of values minus one.
Standard deviation is a type of average where the positive and negative numbers sum to zero.
The amount of difference of the measurements from the central value is called the sample standard deviation.
arrow_forward
The average expenditure on Valentine's Day was expected to be $100.89 (USA Today, February 13, 2006). Do male and female consumers differ in the amounts they spend? The average expenditure in a sample survey of 44 male consumers was $137.38, and the average expenditure in a sample survey of 35 female consumers was $65.11. Based on past surveys, the standard deviation for male consumers is assumed to be $35, and the standard deviation for female consumers is assumed to be $12. The z value is 2.576.
Round your answers to decimal places.
b. At 99% confidence, what is the margin of error?
c. Develop a 99% confidence interval for the difference between the two population means.
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A buyer for an electrical component is searching for a supplier who has the best combination of low price, low order cycle time and low order cycle variability.Current uage for the component is 100 units per day. the buyer received data on four potineital suppliers
(table)
Based on the order cycle time, variability and unit price data provided in the table, which supplier should be awarded the component business?
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Although 23 states barred the self-service sale of gasoline in 1968, most
removed the bans by the mid-1970s. By 1992, self-service outlets sold nearly
80% of all US gas, and only New Jersey and Oregon continued to ban self-
service sales. Using predictive value for self-service sales for New Jersey and
Oregon Johnson and Romeo (2000) estimate that the ban in those two
states raised the price by approximately $.03-$.05 per gallon. Why did the
ban effect the price? Illustrate using a figure and explain. Show the welfare
effects in your figure. Use a table to show who gains or loses.
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I neeed help with all parts of this question
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The value of the ideal standard deviation is (two decimal places, no zeroes anywhere)
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How do you solve a problem similar to this? I’m confused on how to solve to find the quantity when you have the other variables.
(Q1-15)-Q1/ ((Q1-15)+Q1)/2 = -30.30
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pls help asap on both
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Answer this question. Part (b).
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43% of small businesses are either not tracking inventory or using manual processes, such as spreadsheets or pen-and-paper. This creates a higher probability of creating double entries, difficulties in placing and receiving orders, and time-consuming processes of locating stock, among other errors. Suppose you are appointed as a purchasing officer of a small business. You are asked to manage the purchases of NIDO (powder milk). The annual demand = 1500 units of NIDO, Delivered purchase cost = R25/units, Annual carrying cost percentage= 15percent, Order cost = R35/order. The lead time is 10 working days. Assuming 20 working days per month.
a) Determine the Economic Order Quantityb) Determine the reorder pointc) Determine the average inventoryd) Suppose orders are placed only at review time. Find the optimal period and the optimal orderquantity.
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R(p) = pN(p).|
Bob is currently selling tires for 60 dollars each. His weekly sales are running at 130 tires per week, so
N(60) = 130.
His marketing department estimates that he will lose 2 sales per week for each 10 dollar increase in unit price, so
N'(60) = -0.2.
Estimate Bob's increase in weekly revenue for each one dollar increase in tire price.
Revenue increase =1
dollars
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A film processing service monitors the quality of the developing process with light-sensitive equipment. The accuracy measure is a number with a target value of zero. Suppose that an X- chart with subgroups of size five is used to monitor the process and the control limits are UCL = 1.5 and LCL = -1.5. Assume that the estimate for the process mean is zero and for the process standard deviation is 1.30.a. What is the value of α for this control chart?b. Find the UCL and LCL based on three-sigma limits.c. Suppose that the process mean shifts to 1. What is the probability that the shift is detected on the first subgroup after the shift occurs?
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Consider the data set below. Use Table 2 of Appendix B.
question 9
attahed in ss below
tahnaks
aorihro
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Economic topic. Show your work
A weighing machine without any display was
used by an average of 320 persons a day with
a standard deviation of 50 persons. When an
attractive display was used on the machine, the
average for 100 days increased by 15 persons.
Can we say that the display did not help much?
Use a level of significance of 0.05?
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The cost C(Q) of producing a quantity Q of widgets to satisfy demand isC(Q) = 4000+20Q, but the quantity demanded is random. If the mean and standarddeviation of demand are 500 and 200, respectively, then what are the mean andstandard deviation of costs?
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Question of the day:
A machine is designed to produce insulating
washers for electrical devices of average
thickness of 0.025 cm. A random sample of 10
washers was found to have an average
thickness of 0.024 cm with a standard deviation
of 0.002 cm. Test the significance of the
deviation. Value of t for 9 degrees of freedom at
5% level is 2.262?
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GIL internet services record customer usage patterns. Historically they have found the duration of an internet session is normally distributed with an average duration of 77.5 minutes and a standard deviation of 20.6 minutes. What is the probability a randomly selected session would last longer than two hours or less than thirty-five minutes? (4 decimal places)
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The mean was found to be u = 70 so now we need to find the standard deviation o. The standard deviation is calculated as follows where n is the sample size, 350,
and p is the probability of a success, 0.2. Find the standard deviation.
V np(1 – p)
O =
V 350(
)(1 – 0.2)
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Consider a very large number of students taking a college entrance exam such as the SAT. And suppose the mean score on the mathematics section of the SAT is 570 with a standard deviation of 40.a. Find the z-score for a student who scored 600.b. A student is told that his z-score on this test is -1.5. What was his actual SAT math score?
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Scenario 38-5. Researchers are interested in the height of the average person in San Francisco, California. Using a random sample of 1,000 people, they find that the average height in the sample is 68 inches.
(Hint: Be sure to calculate the
Refer to Scenario 38-5. If the standard deviation of heights is 3 inches, we can be 95% confident that the true mean height of the population is between
standard error of the estimate.)
O O O O
between 67.997 inches and 68.003 inches.
between 67.905 inches and 68.095 inches.
between 67.905 inches and 68 inches.
between 68 inches and 68.095 inches.
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The average amount of debt families have is 2.5 times their annual income with a standard deviation 0.75 times their annual income. How much debt does a family have to have (relative to their annual income) to be in the top 5% with the LOWEST debt load?
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A polling company reported that 33% of 2286 surveyed adults said that they play football. Complete parts (a) through (d) below.
C
a. What is the exact value that is 33% of 2286?
The exact value is
(Type an integer or a decimal.)
b. Could the result from part (a) be the actual number of adults who said that they play football? Why or why not?
O A.
No, the result from part (a) could not be the actual number of adults who said that they play football because that is a very rare activity.
O B.
Yes, the result from part (a) could be the actual number of adults who said that they play football because the results are statistically significant.
O C.
Yes, the result from part (a) could be the actual number of adults who said that they play football because the polling numbers are accurate.
O D. No, the result from part (a) could not be the actual number of adults who said that they play football because a count of people must result in a whole number.
c. What could be the actual number of…
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Related Questions
- Use the body temperatures, in degrees Fahrenheit, listed in the accompanying table. The range of the data is 3.3°F. Use the range rule of thumb to estimate the value of the standard deviation. Compare the result to the actual standard deviation of the data rounded to two decimal places, 0.69°F, assuming the goal is to approximate the standard deviation within 0.2°F. The estimated standard deviation is °F. (Round to two decimal places as needed.) Compare the result to the actual standard deviation. The estimated standard deviation is C the actual standard deviation. Thus, the estimated standard deviation Data table the goal. 99 98.2 97.5 98.4 99.2 98 98.7 98.5 98.1 98.1 98.5 99.3 98.7 96.7 96.5 98.7 98 97.3 98.4 98 97.7 98.3 98.9 97.1 99 97.1 98.7 98.6 99.4 97.6 97.6 97.7 97.9 99.4 98.7 99.6 97.8 97.9 99 98.3 97.7 98.7 98.2 98.7 97.6 98 97.7 98.6 98.5 98.3 97.7 99 96.3 98 98.2 96.8 97.3 97.3 97.5 98.5 97.6 97.7 97.2 97.7 98 98.8 99 98.5 98 97.8 97 97.3 99.1 98.7 98.6 98.3 98.4 99 98…arrow_forwardQuestion 16 The probability of an 60 year-old male living to 70 years old is equal to in 2019. (Art_13_07_B) 78.2% 85.3% 70.2% 087.2%arrow_forwardf (x, y) = 3x² + y³ + 4xy² +8 Of(x,y) dr Of(x,y) dy What is the value of when x = 4 and y = 5? (Note: the answer may not be a whole number, so please round to the nearest hundredth) (Note: the numbers may change between questions, so read carefully)arrow_forward
- To solve: A manufacturer of high-tech computing equipment must decide whether or not to continue development of a new promising technology. continuing the development would cost $2 Million. If the development is continued, then a patent is either awarded or not. 70% chance that the patent will be awarded and The best estimate is that there is a a 30% chance that it will not. if the patent is awarded, the company needs to decide whether or not to license the technology. it does, it would receive a total of $25 million in licensing royalties. However, the company could also produce and sell the technology in-house (at. a cost of $10 million), in which case there is an additional uncertainty about the demand for the technology. if the demand is high (p = 0.25), the company would make $55 Million in revenues, if the demand is medium (p = 0.55) the company would make $33 Million and if the demand is Low (p = 0.20) the company would still make $15 Million. a) Draw and solve a decision tree…arrow_forwardMEAN ABSOLUTE DEVIATION Q.1) Find the mean absolute deviation for the set below. S = {85, 90, 68, 75, 79} A. В. C. D. 79.4 6.48 32.4 79 Sherrie just registered for her wedding. So far 6 items have been fulfilled on her registry. Find the Q.2) mean price of the fulfilled items. $29, $58, $15, $129, $75, $22 43.5 129 54.7 114 А. В. С. D. Find the mean absolute deviation of the fulfilled items on Sherrie's registry. $29 , $58, $15, $129, Q.3) $75, $22 196 54.7 114 32.67 C. D.arrow_forward2. A city had an unemployment rate of 7%. The mayor pledged to lower this figure and supported programs to decrease unemployment. A group of citizens wanted to test with 0.032 label of significance if the unemployment rate had actually decreased, so they obtained a random sample of 500 citizens to see what proportion of the sample was unemployed. Only 32 citizens in the above sample is still unemployed. What is the probability of Type II error if the actual unemployment rate is 6.5% please don't use software everything needs to be done by hand. Explain because I don't understand my professor. Note:- Do not provide handwritten solution. Maintain accuracy and quality in your answer. Take care of plagiarism. Answer completely. You will get up vote for sure.arrow_forward
- A property owner is faced with a choice of: A large-scale investment to improve her flats. This could produce a substantial pay-off in terms of increased revenue net of costs but will require an investment of 1.4 million pesos. After extensive market research it is considered that there is a 40% chance that a pay-off of 2.5million will be obtained, but there is a 60% chance that it will be only 800,000 pesos. A smaller scale project to re-decorate her premises. At 500,000 pesos this is less costly but will produce a lower pay-off. Research data suggests a 30% chance of a gain of one million pesos but a 70% chance of being only 500,000 pesos. Continuing the present operation without change. It will cost nothing but neither will it produce any pay-off. Clients will be unhappy and it will become harder to rent the flats out when they become free. What is the best alternative? Use decision tree analysis.arrow_forwardQ.3 What is the difference between ordinary least square and maximum likelihood ( ML ) estimators ? Also discuss their properties ?arrow_forwardAnswer asaparrow_forward
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