EET-216_Lab_7_FINAL
docx
keyboard_arrow_up
School
Centennial College *
*We aren’t endorsed by this school
Course
216
Subject
Electrical Engineering
Date
Dec 6, 2023
Type
docx
Pages
13
Uploaded by PrivateValorFlamingo23
Electrical Engineering
Electrical Engineering Technician AMAT/ SETAS
Course: EET-216
DRAWINGS & INSTALLATION 3
Names: 1. _________________________________________
2.________________________________________________
3. _________________________________________________________
Lab # 7
Title:
Wind Turbine
Make sure that you are wearing appropriate protective equipment when performing the tasks. You should
never perform a task if you have any reason to think that a manipulation could be dangerous for you or your
teammates.
Introduction
The production of energy using renewable natural resources such as wind, sunlight, rain, tides,
geothermal heat, etc., has gained much importance in recent years as it is an effective means of reducing
greenhouse gas (GHG) emissions. The need for innovative technologies to make the grid smarter has
recently emerged as a major trend, as the increase in electrical power demand observed worldwide
makes it harder for the actual grid in many countries to keep up with demand. Furthermore, electric
vehicles (from bicycles to cars) are developed and marketed with more and more success in many
countries all over the world.
This Introduction to Wind Power lab, covers how a permanent magnet wind turbine produces electricity
from wind power, and how Maximum Power Point Tracking controllers are able to adjust the blade
velocity of variable-speed fixed pitch wind turbines.
The Discussion of this exercise covers the following points:
●
Air density
●
Kinetic energy in the wind
●
Calculating wind power
●
Relationship between wind power and wind speed
●
Relationship between torque, rotation speed, and rotational mechanical power
●
Conversion of wind power into rotational mechanical power and electrical power
●
Typical torque-versus-speed curve at the wind turbine rotor
●
Variable-speed, fixed-pitch Wind turbines.
●
Wind turbine generator efficiency
The air density, symbolized by the Greek letter
𝜌
(rho), is an important parameter to know in wind power
applications. Air density is the mass of air per unit volume:
𝜌
=
𝑚/?
Where: ρ is the air density, in kilograms per cubic meter (kg/m3)
𝑚
is the mass of air, in kilograms (kg)
?
is the volume, in cubic meters (m3)
The air density varies with atmospheric pressure, temperature, humidity, and altitude. In SI units,
ρ = 1.225 kg/m3 under standard sea level conditions, which are: a temperature of 15.5°C, an
atmospheric pressure of 101.325 kPa, and a relative humidity of 36%
Kinetic energy in the wind
Any object or fluid in motion has kinetic energy. For example, wind, which is a mass of air in motion, has
kinetic energy. The faster the speed of the wind, the higher the kinetic energy of the wind. The kinetic
energy in a mass of air in motion can be calculated by using the following equation:
?
?
=
𝑚V
2
/ 2
Where:
?
?
is the kinetic energy, in joules (J) or [feet-pound force (f
lbf)].
∙
𝑚
is the mass of air, in kilograms (kg)
V
is the velocity of the mass of air, in meters per second (m/s)
2 is a constant.
?
?
=
𝑚V
2
/
2
?
?
imperial unit version of the above SI unit equation.
Where
?
?
is equal to 32.174 lbm/lbf
s
∙
2
.
Calculating wind power
The Figure 1 below shows wind of constant speed passing through a cross-sectional area
?
. This area
could be, for example, the area swept by the blades of a wind turbine.
In SI units, the power of the wind passing through the cross-sectional area is:
?
?
=
𝜌A
V
3
/ 2
Where:
?
?
is the power in the wind, in watts (W, or kg
m
∙
2
/s
3
).
𝜌
is the air density, in kilograms per cubic meter (kg/m
3
).
?
is the cross-sectional area, in square meters (m
2
).
V
is the wind speed (m/s).
Cross-sectional area A
Wind
Velocity V
Figure 1, Wind flowing through a cross-sectional area A
The observations below can be made from the equation used to calculate the power in the wind.
●
Any change in the temperature of the air, atmospheric pressure, or relative humidity causes the
air density ρ to change, causing the wind power to change in the exact same way (for given wind
speed and cross-sectional area). For instance, when the air density ρ increases by 5%, the wind
power
?
?
also increases by 5%.
●
When the cross-sectional area
?
swept by the blades of a wind turbine rotor is increased, the
wind power intercepted by the blades increases in direct proportion.
●
When the wind speed
V
increases, the wind power also increases.
Relationship between wind power and wind speed
As already mentioned, the wind power increases when the wind speed increases. More precisely, the
wind power
?
?
varies with the cube (the third power) of the wind speed
V
, as Figure 2 shows.
• When the wind speed doubles, the wind power increases eight times (2
3
= 8).
• When the wind speed triples, the wind power increases 27 times (3
3
= 27).
• When the wind speed quadruples, the wind power increases 64 times (4
3
= 64).
Relationship between torque, rotation speed, and rotational mechanical power
When a force is applied to an object mounted on a rotation axis (such as the bladed rotor of a wind
turbine), the object starts to rotate at a certain speed, as shown in Figure 3. The rotation speed
?
is
expressed in revolutions per minute (r/min). One revolution is equal to 360°, or 2π radians (rad).
The rotational mechanical power
?
m
produced at the rotating axis of the object is the product of the
torque T developed at the rotating axis and the rotation speed
?
, divided by a constant. The equation
below allows the rotational mechanical power to be calculated in SI units.
?
m
=
T
∙
? /
9.55
Where
?
m
is the rotational mechanical power, in watts (W).
T
is the torque, in newton meters (N
m).
∙
?
is the rotation speed, in revolutions per minute (r/min).
9.55 is a constant
When wind hits the blades of a wind turbine rotor, the pressure of the air acting on the surface of the
blades creates a force, which applies a torque onto the rotor of the turbine, as Figure 4 shows.
When the wind is strong enough to produce a torque higher than the force (torque) opposing rotation,
the wind turbine rotor starts to rotate at a certain speed. In this condition,
F
?
Pm =
T
∙
?
/ constant
T
Figure 3. Torque, rotation speed, and rotational mechanical power.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
●
The blades of the wind turbine convert a portion of the power contained in the wind they
intercept (linear mechanical power) into rotational mechanical power that makes the wind
turbine rotor turn.
●
The rotational mechanical power produced at the wind turbine rotor drives an electric generator.
The electric generator converts the rotational mechanical power into electrical power.
Wind, rotor, and rotor efficiency coefficient
?
?
As already mentioned, the power contained in the wind passing through the area swept by the blades of
a wind turbine rotor is:
?
?
=
𝜌A
V
3
/ 2
Where:
?
?
is the power in the wind, in watts (W, or kg
m
∙
2
/s
3
).
𝜌
is the air density, in kilograms per cubic meter (kg/m
3
).
?
is the cross-sectional area, in square meters (m
2
).
V
is the wind speed (m/s).
Not all the power in the wind passing through the swept area is transferred to the wind turbine rotor.
Only a fraction of the available wind power is extracted by the blades and transferred to the rotor. This
fraction indicates the efficiency of the wind turbine rotor in converting linear mechanical power into
rotational mechanical power.
The fraction of wind power extracted by the blades and transferred to the rotor is called the rotor
coefficient efficiency
?
?
. The rotor efficiency coefficient depends on the design (shape) of the rotor
blades. The rotor efficiency coefficient is sometimes expressed as a percentage (rotor efficiency
coefficient multiplied by 100%).
The rotor efficiency coefficient
?
?
is generally between 0.4 and 0.5 for most blade designs. The rotor
efficiency coefficient
?
?
must be taken into account to determine the fraction of wind power
?
?
that is
transferred to the wind turbine rotor. The formula used to calculate the mechanical power
?
𝑚
at the
wind turbine rotor is therefore:
?
𝑚
=
?
?
∙
?
?
= (
𝜌A?
3
/ 2)
∙
?
?
Three-blade wind turbine rotor
F
Wind turbine generator
F
T
F
Figure 4:
A fraction of the power in the wind intercepted by the blades of the turbine is
converted into rotational mechanical power to drive the electric generator of the turbine.
The rotor efficiency coefficient
?
?
of a wind turbine is virtually constant over the normal wind speed
range of the turbine. Therefore, the mechanical power at the wind turbine rotor varies in the same way
as wind power, i.e., with the cube (the third power) of the wind speed.
Typical torque-versus-speed curve at the wind turbine rotor
Figure 5 shows a typical torque-versus-speed curve at the rotor of a wind turbine obtained for a given
wind speed.
As the rotor speed increases, the torque produced at the rotor increases until a point is reached, beyond
which the torque gradually decreases to zero. Consequently, the mechanical power produced at the
rotor also increases up to a certain maximum value, and then gradually decreases to zero, as Figure 5
shows. The point at which the mechanical power is maximum is referred to as the
maximum power
point (MPP)
.
A wind turbine must be operated as close as possible to the optimum speed to maximize the mechanical
power developed at the rotor and thus obtain the maximum amount of electrical power. This is
performed by setting the rotor torque to the optimum value, through adjustment of the current drawn
by the electrical load at the wind turbine generator output.
Note that the rotor speed at which the maximum amount of power is produced varies with the wind
speed. Therefore, to operate the wind turbine at the maximum power point (MPP) and maximize the
energy produced at any wind speed, the rotor speed must be continuously monitored and changed, by
adjustment of the rotor torque. This is generally performed automatically by an MPPT controller in the
wind turbine.
Variable-speed, fixed-pitch Wind turbines
.
Variable-speed wind turbines are generally characterized as having higher efficiency than fixed-speed
wind turbines and hence are becoming more popular, particularly for small wind turbines. Typically,
variable-speed wind turbines are controlled, usually by using power electronics, to regulate the torque
and speed of the turbine in order to maximize the output power. Variable-pitch controlled wind turbines
Figure 5.
Typical torque-versus-speed curve and mechanical power-
versus-speed curve at the rotor of a wind turbine, for a given wind speed.
Mechanical power at rotor
??
Rotor torque
?
Optimum torque
Maximum
power
Maximum power
point (MPP)
Optimum
Velocity
Rotor speed
?
Rotor speed
?
are more costly and complex. Therefore, variable-speed fixed-pitch approach is becoming more popular
for low cost construction and is the most common scheme for small wind turbines.
In
fixed-pitch variable-speed wind turbines, Wind-rotor performance is fixed, the rotor speed and torque
are adjusted in order to keep the generator operating at the maximum power point (MPP). The MPPT
controller varies the velocity of the blades by varying the current from the generator.
With a wind turbine generator (as well as any other generator), not all the mechanical power applied to
the rotor shaf is converted into electrical power, due to power losses in the stator windings.
Figure 8 shows that the actual electrical power produced by the generator is lower than the ideal power
value over most of the rotor speed range. On the ideal curve, the maximum electrical power is 224 W,
and it is reached when the rotor speed is 987 r/min. On the actual curve, the maximum electrical power
is 177 W, and it is reached when the rotor speed is 1013 r/min. Therefore, the actual electrical power
produced by the generator is lower than the ideal value by 47 W, which corresponds to a power
conversion efficiency of about 79% (177 W ÷ 224 W).
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
1.
OBJECTIVE
Students will set up a circuit containing a solid magnet wind turbine, a prime mover (hand crank or
coupled motor) three phase rectifier
and variable resistive load.
Then, with the measuring equipment, study the behavior of the wind turbine (frequency, output current,
and generator torque) as the prime mover speed and load are varied.
2.
MATERIALS REQUIRED
Data Acquisition and Control Interface
Prime mover
Variable resistive load
Three phase power rectifier Diodes and Bread Board
Multi-function tester
Clamp-on ammeter
Miscellaneous wire and tools
NOTE:
Do not install any improper or damaged components. Have instructor review finished connections
PRIOR to applying power.
High voltages are present in this laboratory exercise. Do not make or modify any banana
jack connections with the power on unless otherwise specified.
3a. Effect of Velocity and Load on Wind turbine.
1.
Set up the six diodes to form a three phase full wave bridge rectifier.
/3
2.
Make sure that the AC and DC power switches on the power supply are set to the
O
(off)
position, then connect the
Power Supply
to the three-phase AC power outlet.
Connect the Power Input of the
Data Acquisition and Control Interface
to a 24V AC power
supply. Turn the 24V ac power supply on.
3.
Connect the USB port of the
Data Acquisition and Control interface
to a USB port of the host
computer.
4.
Turn the host computer on, then start the
LVDAC-EMS
sofware.
In the
LVDAC-EMS Start-Up
window, make sure the
Data Acquisition
and
Control Interface
is
detected. Select the network voltage and frequency (60Hz,
120V
) then click the OK button to
close the
LVDAC-EMS Start-Up
window.
5.
Connect the equipmnet as shown in the figure Below. Using you’re the rectifier that you
constructed and the three phase resistor bank (all resistors in parallel)
6.
Have your instructor verify your connections.
/3
7.
In the
LVDAC-EMS
, open the
Metering
window. Make the required setting in order to measure
the output voltage and frequency from the generator, and rectified Voltage, Current supplied to
the resistor bank.
8.
In the
LVDAC-EMS
, open the
Oscilloscope
, then make the appropriate settings in order to
observe the waveforms of the Generator. Before and afer rectification (
E1
and
E2
). Select the AC
generator voltage (Input
E1
) as the trigger source of the
Oscilloscope
.
9.
With all the resistors in the resistor bank disconnected, turn the turbine at a consistent low-
medium speed. Record frequency and amplitude of the AC turbine output in
Table 1
.
10.
Observe the waveforms on the
Oscilloscope
, how are they behaving?
(voltage, frequency)
●
The amplitude of the voltage and the frequency values gradually grew as the turbine was turned
at a constant low-medium speed, until they remained constant at a narrow range of values.
/2
11.
Change the settings on the Resistor bank so that the resistance is 1Ω. Observe the waveforms on
the
Oscilloscope
, record frequency and amplitude of the AC turbine output in
Table 1
.
12.
How does this change effect the counter torque produced by the turbine. (i.e. are the blades
more difficult to move?)
●
The blades were more difficult to move at a 5 ohm resistor load than they were at the
detached resistor bank. It is simpler to move the handle in an open load when there is
no counter torque generated in an open resistance bank.
/2
13.
Change the resistor bank settings to 0.5Ω. Record frequency and amplitude of the AC turbine
output in
Table 1
.
14.
How does this change effect the counter torque produced by the turbine. (Are the blades more
difficult to move?)
●
In comparison to the resistor load of 5 ohms, moving the handle at 2.5 ohms proved to
be significantly more challenging. Considering that the resistance value was lowered. As
a result, an increase in current was noticed, which raised the counter torque.
/2
15.
Change the resistor bank settings to 0.33Ω. Record frequency and amplitude of the AC turbine
output in
Table 1
.
16.
How does this change effect the counter torque produced by the turbine. (Are the blades more
difficult to move?)
/2
●
The handle was significantly harder to move at 1.667 ohms as opposed to a resistor load
of 2.5 ohms. Since the resistance value was decreased, an increase in current has been
noticed, which has led to a larger counter torque.
17.
Disconnect the resistors. Turn the turbine at a consistent medium-high speed. Record frequency
and amplitude of the AC turbine output in
Table 2.
18.
Change the settings on the Resistor bank so that the resistance is 1Ω. Observe the waveforms on
the
Oscilloscope
, record frequency and amplitude of the AC turbine output in
Table 2
.
19.
How does this change effect the counter torque produced by the turbine. (i.e. are the blades
more difficult to move?)
Compared to an open resistor bank, moving the handle at a 5 ohm
resistor was harder.
/1
20.
Change the resistor bank settings to 0.5Ω. Record frequency and amplitude of the AC turbine
output in
Table 2
.
21.
How does this change effect the counter torque produced by the turbine. (Are the blades more
difficult to move?)
/1
●
At 2.5 ohms, the handle was more difficult to move compared to the 5 ohms resistors
load
22.
Change the resistor bank settings to 0.33Ω. Record frequency and amplitude of the AC turbine
output in
Table 2
.
23.
How does this change effect the counter torque produced by the turbine. (Are the blades more
difficult to move?)
/1
●
At 1.67 ohms, the handle was more difficult to move compared to the 2.5 ohms resistors
load.
24.
Lab Equipment powered off and cleaned up. Instructor to verify _______ (initial)
/
10
4.
QUESTIONS
1.
From your observations of the waveforms on the
Oscilloscope
, how does the turbine behave as
the rotational speed and load are varied (output Voltage, Frequency, and counter torque
produced by the generator)?
/4
●
According to the data tallied below: The output voltage, frequency, and current all increase as
the rotational speed rises from 100 to 121 bpm. Consequently, the output voltage, frequency,
and current all decrease as the load resistance rises from 1.67 ohms to 5 ohms. Furthermore,
the counter torque increases along with an increase in current.
2.
What can you conclude about the number of poles in the turbine stator?
/4
●
The number of poles within it significantly influences the turbine stator's rotational speed. The
rotational speed (in Rpm) falls as the number of poles rises. Because these relatively high-speed
generators are more affordable and smaller in size, the majority of wind turbines only use
generators with four or six poles.
3.
Can the synchronous generator (Fixed-pitch, Variable-speed Wind turbine) be synchronized
directly to the to the AC power network using a synchronizer as we did in the previous lab?
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
□ Yes
□ No
/1
If one was to try, what could the complications be?
/4
●
The frequency of the voltage varies along with the wind's speed and the rotor's speed. The AC
power network cannot be connected to this directly. Alternatively, the frequency needs to be
adjusted so that it remains constant. If this isn't done, there's no guarantee that the wind
turbine frequency will match the network frequency. As a result, it might cause harm to the
generator and the power system.
4.
How would a Maximum Power Point Tracking controler manage a fixed pitch variable-speed
wind turbine such that the blade speed could be controlled with respect to wind velocity?
●
Knowing the wind-rotors fixed-pitch variable-speed wind turbine's performance. The generator's
rotor speed and torque are modulated to maintain it operating at its maximum power point
(MPP). The MPPT controller modifies the generator's current to alter the blades' velocity.
/4
5.
What kind of feedbacks could the MPPT controler use to ensure the blade speed is appropreat to
the wind speed?
/5
●
The rotor speed needs to be continuously varied and monitored by adjusting the rotor torque in
order for the wind turbine to maintain its maximum power point (MPP) and maximize the
energy produced at any wind speed. Usually, the wind turbine's MPPT controller does this
automatically.
/8
Table 1
Prime mover speed: 100 bpm refer
2 nf email
Load (Ω)
AC Voltage (peak)
Frequency (Hz)
DC Current
DC Voltage
OPEN (∞Ω)
6.90
10.16
0.00
6.02
5
Ω
4.80
10.69
0.60
3.13
2
.5 Ω
3.76
9.91
0.75
2.07
1
.
67
Ω
3.37
9.87
0.82
1.06
/8
Table 2
Prime mover speed: 120 bpm
Load (Ω)
AC Voltage (peak)
Frequency (Hz)
DC Current
DC Voltage
OPEN (∞Ω)
8.04
11.92
0.00
7.51
5
Ω
5.45
12.39
0.72
3.73
2
.5 Ω
4.67
12.95
1.05
2.93
1
.
67
Ω
4.33
13.72
1.27
2.45
Conclusion:
/5
●
By the time the lab was over, I knew how the wind turbine worked. First, the mechanical power
reaches its maximum value at a point known as the maximum power point (MPP). In order to
maximise mechanical power and obtain the maximum amount of electrical power, a wind
turbine must run at a speed very close to the optimal speed. Second, there is an inverse
relationship between the load and the current. Due to the fact that there is no current passing
through the turbine, it is therefore more difficult to move it at low resistances. In contrast, since
there would be a sharp rise in current, it would be much more difficult with shorted leads.
Finally, the result tabulated above indicates a direct relationship between the rotational speed
and voltage, frequency, and current.
Student Names
LAB MARK
QUESTIONS
Conclusion
SAFETY
Total Mark
33
22
5
10
70
1
2
3
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
For that reason, it is harder to move the turbine at low resistances because there is no current flowing
through it. Whereas to shorted leads, it would be alot harder as there will be a rapid current increase.
Lastly, the rotational speed has a direct relationship with voltage, frequency, and current as shown in the
result tabulated above
Recommended textbooks for you

EBK ELECTRICAL WIRING RESIDENTIAL
Electrical Engineering
ISBN:9781337516549
Author:Simmons
Publisher:CENGAGE LEARNING - CONSIGNMENT

Electricity for Refrigeration, Heating, and Air C...
Mechanical Engineering
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Cengage Learning


Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning
Recommended textbooks for you
- EBK ELECTRICAL WIRING RESIDENTIALElectrical EngineeringISBN:9781337516549Author:SimmonsPublisher:CENGAGE LEARNING - CONSIGNMENTElectricity for Refrigeration, Heating, and Air C...Mechanical EngineeringISBN:9781337399128Author:Russell E. SmithPublisher:Cengage Learning
- Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning

EBK ELECTRICAL WIRING RESIDENTIAL
Electrical Engineering
ISBN:9781337516549
Author:Simmons
Publisher:CENGAGE LEARNING - CONSIGNMENT

Electricity for Refrigeration, Heating, and Air C...
Mechanical Engineering
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Cengage Learning


Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning