DGD4+solution

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University of Ottawa *

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Course

2138

Subject

Electrical Engineering

Date

Dec 6, 2023

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pdf

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5

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DGD 4 ELG2138 A Question 1) (P 4.5-1) Determine the mesh currents i 1 , i 2 , and i 3 for the circuit shown in Figure P 4.5-1.
Question 2) (P 4.6-8) Determine values of the mesh currents, i 1 , i 2 , and i 3 , in the circuit shown in Figure P 4.6-8. Solution : The meshes 1 and 2 share a current source Supermesh=mesh 1 + mesh 3 Use units of V, mA and k Ω . Express the currents to the supermesh to get : i 1 i 3 = 2 Apply KVL to the supermesh to get : 4 ( i 3 i 2 ) + ( 1 ) i 3 3 + ( 1 ) ( i 1 i 2 ) = 0 i 1 5 i 2 + 5 i 3 = 3 Apply KVL to mesh 2 to get
Question 3) (P 4.7-10) The circuit shown in Figure P 4.7-10 is the small signal model of an amplifier. The input to the amplifier is the voltage source voltage, v s. The output of the amplifier is the voltage v o. (a) The ratio of the output to the input, v o / v s , is called the gain of the amplifier. Determine the gain of the amplifier. (b) The ratio of the input voltage source v s to the input current i b , v s / i b , is called the input resistance of the amplifier. Determine the input resistance.
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Question 4) (P 4.7-16) Determine the values of the mesh currents i 1 and i 2 for the circuit shown in Figure P4.7-16 . Solution : First, express the controlling current in terms of mesh current: KCL at node i a =i 2 + 1
Question 5) (P 5.2-2) Consider the circuit of Figure P 5.2-2. Find i a by simplifying the circuit (using source transformations) to a single-loop circuit so that you need to write only one KVL equation to find i a . Solution :