Lab5-Ohm's Law

.docx

School

Tarrant County College, Fort Worth *

*We aren’t endorsed by this school

Course

2425

Subject

Electrical Engineering

Date

Dec 6, 2023

Type

docx

Pages

6

Uploaded by SuperHumanGoldfinchMaster215

Report
Ohm’s Law NAME: ____Sehajpartap Gill__________________ Date: ____7/20/2021___________ Lab Partner’s: ________ (No Contact, Worked Solo) ___________________ Access the University of Colorado’s PhET simulation Ohm’s Law BACKGROUND: In the early 19th Century, technology was developed by Alessandro Volta to produce electricity on demand. Soon, thereafter experiments were being conducted on electrical circuits. The source of the electricity, the Voltaic Pile, as it came to be known, was an early forerunner to the battery. The bigger the pile was constructed, the more electricity it could provide. However, it soon became apparent that the same pile did not provide the same amount of electricity across different materials. Some materials conducted electricity very readily, others less so, and some hardly at all. Like materials conducted equivalently. For example, one copper wire conducted electricity just as well as another of the same size. But an iron wire conducted less well than a copper wire of the same size. An aluminum wire of the same size connected across a voltaic pile conducted more electricity than an iron wire, but less than a copper wire. Out of this grew the concept that different materials have a particular electrical resistance. Since the bigger the voltaic pile, the more powerful it was, a unit was created that related to how well the voltaic pile could produce electricity across a given electrical resistance. The voltaic pile’s electrical potential to do this is its voltage. Voltage is measured in Volts (symbol V). Physically, the voltage is the electrical potential energy per unit charge. The amount of electricity flowing (current) through a conductor is measured in Amperes (symbol A), named for André Ampère. Often, for simplicity, we shorten this name to “Amps” though formally it should be Amperes. The electrical resistance is measured in units of Ohms (symbol Ω), named after Georg Ohm. THEORY: In 1827, the German physicist Georg Ohm published his research showing that the amount of current ( I ) passing through a material, for most materials, is directly proportional to the voltage ( V ) applied across the material, and inversely proportional to the electrical resistance ( R ) of the material. This relationship is referred to as Ohm’s Law and is commonly written today as: V = IR Note: In some engineering fields, the letter E is used for the electromotive force (voltage source) in an electrical circuit, and Ohm's law is written as E = IR
INSTRUCTIONS: Use Excel to plot the graphs and insert or attach all graphs, plots, and tables to this lab assignment. Convert values to SI units and show all your calculations. PROCEDURE: 1) Select a value of resistance (R). Now, increase the potential (V) across the resistor. How does current (I) change? The current will increase proportionally as the potential (V) increases. 2) Select a value of potential. Now, increase resistance. How does the current change? After increasing the resistance and setting the voltage, the current decreases since current and resistance are inversely proportional. 3) If a battery of 9 V is connected across a resistor of 1000 Ω, what will be the value of current flowing through it? I = V/R Here, V = 9 V R = 1000 Ohms So, I = 9/1000 = 9 mA (milli ampere) 4) For a resistor of 100 Ω, apply five different potentials and measure the current through the resistor. NOTE : The current in the simulation is given in milliamps (mA), divide the current values by 1000 to convert them to Amperes. Voltage (V) 1.5 3 4.5 6 7.5 Current (A) 1.5e-3 3.0e-3 4.5e-3 6.0e-3 7.5e-3 2
5) How does the slope of the graph relate to resistance? If the value of resistance were 500 Ω instead of 100 Ω, how will this slope change? Explain. The line on the graph will be lower (less steeper) and the slope would decrease from the current value of the slope. 6) Complete the table below. Voltage (V) Current (A) Resistance (Ω) 0.1 1.25e-4 800 2.0 2.5e-3 3.0 3.8e-3 4.0 5.0e-3 5.0 6.3e-3 6.0 7.5e-3 7.0 8.8e-3 8.0 10e-3 9.0 11.3e-3 0.1 2.47e-4 405 2.0 4.94e-3 3.0 7.41e-3 4.0 9.88e-3 5.0 12.35e-3 6.0 14.81e-3 7.0 17.28e-3 8.0 19.75e-3 9.0 22.22e-3 0.1 2.5e-3 40 2.0 50e-3 3.0 75e-3 4.0 100e-3 5.0 125e-3 3
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help