Yianni Tripas - EMNG1001_Lab6_CombinationCircuits_InClass(2)

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Dec 6, 2023

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Student First Name: Yianni Student Last Name: Tripas Student Number: 101490541 Submission Date: 2023-10-26 General Notes: 1. Type your name, student ID, and the submission date of the lab in the above fields. 2. Practice safety at all times. Carefully follow the directions of the lab. Do not use broken power cords or broken devices powered directly from the mains such as the DC supply. 3. Use only the electronic kit and devices provided by George brown college. Also, ensure that all equipment in the kit stays in good working condition. 4. Carefully read and follow ALL lab instructions provided in the lab write-up. 5. Complete all measurements, calculations, tables, drawings, and images required for all labs. 6. Answer all questions neatly and concisely in the spaces provided (preferably in bold red). 7. All Labs must be submitted by their due dates in Blackboard and cannot be made up. A grade of “Zero” will be assigned for missed labs. 8. The mark and possible feedback will be posted in Blackboard after the due date of each lab. Submission: This original word document with answers included in full is required to be submitted in Blackboard by the due date. It is not allowed to submit another separate document that includes only answers to the questions. Lab 6 Combination Circuits Objectives Upon completion of this lab, students will be able to: 1. Learn to recognize and construct combination series-parallel circuits. 2. Compute voltages and currents of combination series-parallel circuits. 3. Apply the concept of equivalent circuits to simplify combination circuits. 4. Verify computations through measurements. Introduction Real-life systems and applications involve series-parallel circuits which are commonly referred to as combination circuits. The key to solving combination type circuits is to form equivalent circuits of the Ali A. Hussein, Ph.D., P. Eng. EMNG 1001, Circuit Analysis Lab Page 1 EMNG1001 Circuit Analysis Lab 6 Combination Circuits
series and parallel elements. The goal is to reduce a complex combination circuit into a simple series or parallel circuit. To do so, the student must recognize circuit elements which are connected in series and parallel to form the equivalent circuit. To identify whether components are in series or parallel remember that: For components to be considered in series, they must be connected end-to-end and the identical amount of current must flow through them. For components to be considered in parallel, both ends of one component must be directly attached to both ends of other components. Take as an example the combination circuit of Figure 1. Figure 1 Combination circuit example. In Figure 1, R 2 is in series with R 3 and they can be replaced with an equivalent resistance equals to R a = R 2 + R 3 = 11.5 k Ω . The circuit can then be simplified as shown in Figure 2. Figure 2 Simplification of the circuit of Figure 1. In Figure 2, R 1 is in parallel with R a and they can be replaced by the equivalent total resistance as follows and as shown in Figure 3: Figure 3 Total equivalent resistance of the circuit of Figure 1. Ali A. Hussein, Ph.D., P. Eng. EMNG 1001, Circuit Analysis Lab Page 2
R T = [ 1 R 1 + 1 R a ] 1 2.564 k Ω Part 1 Procedure 1. From your tool kit obtain the following resistors: 2.2KΩ, 4.7KΩ, 5.6 KΩ, and 10KΩ. 2. Use the DMM to measure the resistance of each resistor and record the measured values below in Table 1. Table 1 Measuring resistances. Resistor Nominal Resistance (KΩ) Measured Resistance (KΩ) R 1 2.2 2.17 KΩ R 2 4.7 4.61 KΩ R 3 5.6 5.56 KΩ R 4 10 9.81 KΩ 3. Using the resistors from Table 1, construct the combination circuit shown in Figure 4 below. Adjust the DC power source to 12 V. Figure 4 Experimental combination circuit of Part 1. 4. Identify the topology of the combination circuit of Figure 4: a. Indicate which resistors will have identical current flowing through them (i.e. which resistors are connected in series?). Ali A. Hussein, Ph.D., P. Eng. EMNG 1001, Circuit Analysis Lab Page 3
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Answer: ……R1 + R4…………………….. b. Indicate which resistors have both ends connected (i.e. which resistors are connected in parallel so that they receive the same voltage?). Answer: ………R2+R3………………….. 5. Measure the DC source voltage as it is applied to the circuit: V s = ¿ ………12.0 V………………….. 6. Utilizing the measured values of the resistances as in Table 1 and the measures supply voltage as in step 5, theoretically analyze the combination circuit of Figure 4 as follows and fill in the computed values in Table 2: a. Replace R 2 and R 3 with an equivalent resistance called R 2,3 . Determine the value of R 2,3 : R 2,3 = R 2 R 3 R 2 + R 3 …1.56 KΩ b. Determine the total resistance of the resulted simplified series circuit: R T = R 1 + R 2,3 + R 4 = ¿ ………13.54 KΩ ………………….. c. Apply Ohm’s law to find the total current of the circuit: I T = V s R T = ¿ ………0.8 mA………………….. d. Proceed using Ohm’s law to find the voltage drops of the different resistors and the currents of the resistors R 2 and R 3 : V R 1 = I T R 1 = ¿ …………19.2 V……………….. R 3 = ¿ I T R 2,3 = ¿ V R 2,3 = V R 2 = V ¿ …………13.82 V……………….. V R 4 = I T R 4 = ¿ ……………7.84 V…………….. I R 2 = V R 2,3 R 2 = ¿ …………2.99 mA……………….. I R 3 = V R 2,3 R 3 = ¿ ………………2.48 mA………….. 7. Disconnect the constructed combination circuit of Figure 4 from the DC power supply and use the DMM as an ohmmeter to verify the total resistance and record the value in Table 2. 8. Connect the circuit to the DC power supply and using the DMM measure all required voltage drops and currents as per Table 2. Ali A. Hussein, Ph.D., P. Eng. EMNG 1001, Circuit Analysis Lab Page 4
9. In Table 2, do the theoretically calculated values agree with the measured values? Comment on the differences.: The theoretical values I calculated for my circuit differ slightly from my measured values by a .1 difference. Table 2 Analysis and measurement results of the circuit of Figure 4. Parameter Calculated Values Measured Values R T ( k Ω ) 13.54 KΩ 13.49 KΩ I T ( mA ) 8.86 mA 8.83 mA V R 1 ( V ) 19.2 V 19.0 V V R 2,3 ( V ) 13.82 V 13.80 V V R 4 ( V ) 7.84 V 7.82 V I R 2 ( mA ) 2.99 mA 2.97 mA I R 3 ( mA ) 2.48 mA 2.46 mA Part 2 Procedure 1. Using the resistors from Table 1, construct the combination circuit shown in Figure 5. Adjust the DC power source to 12 V. Ali A. Hussein, Ph.D., P. Eng. EMNG 1001, Circuit Analysis Lab Page 5
Figure 5 Experimental combination circuit of Part 2. 2. Measure the DC source voltage as it is applied to the circuit: V s = ¿ ……………12.4…………….. 3. Utilizing the measured values of the resistances as in Table 1 and the measures supply voltage as in step 2 of this part, theoretically analyze the combination circuit of Figure 5 as follows and fill in the computed values in Table 3: a. Replace R 1 and R 2 which are connected in series with an equivalent resistance called R 1,2 . Determine the value of R 1,2 : R 1,2 = R 1 + R 2 = ¿ ………6.78 KΩ ………………….. b. Replace R 3 and R 4 which are connected in series with an equivalent resistance called R 3,4 . Determine the value of R 3,4 : R 3,4 = R 3 + R 4 = ¿ …………15.37 KΩ ……………….. c. Determine the total resistance of the resulted simplified parallel circuit: R T = R 1,2 R 3,4 R 1,2 + R 3,4 = ¿ ……………4.70 KΩ …………….. d. Apply Ohm’s law to find the different currents and voltage drops of the circuit elements: I R 1,2 = V s R 1,2 = ¿ ………1.76 mA………………….. I R 3,4 = V s R 3,4 = ¿ ……………………0.78 mA…….. I T = V s R T = ¿ …………2.55 mA……………….. Ali A. Hussein, Ph.D., P. Eng. EMNG 1001, Circuit Analysis Lab Page 6
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V R 1 = I R 1,2 R 1 = ¿ ……………3.81 V…………….. V R 2 = I R 1,2 R 2 = ¿ …………8.11 V……………….. V R 3 = I R 3,4 R 3 = ¿ ……………………4.37 V…….. V R 4 = I R 3,4 R 4 = ¿ ………7.65 V………………….. 4. Disconnect the constructed combination circuit of Figure 5 from the DC power supply and use the DMM as an ohmmeter to verify the total resistance and the resistance of each parallel branch of the circuit and record the values in Table 3. 5. Connect the circuit to the DC power supply and using the DMM measure all required voltage drops and currents as per Table 3. 6. In Table 3, do the theoretically calculated values agree with the measured values? Comment on the differences.: The theoretical values differ slightly with my results by a .4 difference which most likely was caused by the difference of source voltage. Ali A. Hussein, Ph.D., P. Eng. EMNG 1001, Circuit Analysis Lab Page 7
Table 3 Analysis and measurement results of the circuit of Figure 5. Parameter Calculated Values Measured Values R 1,2 ( k Ω ) 6.78 KΩ 6.72 KΩ R 3,4 ( k Ω ) 15.37 KΩ 15.26 KΩ R T ( k Ω ) 4.70 mA 4.74 mA I R 1,2 ( mA ) 1.76 mA 1.74 mA I R 3,4 ( mA ) 0.78 mA 0.77 mA I T ( mA ) 2.55 mA 2.54 mA V R 1 ( V ) 3.81 V 3.32 V V R 2 ( V ) 8.11 V 8.19 V V R 3 ( V ) 4.37 V 4.35 V V R 4 ( V ) 7.65 V 7.64 V Part 3 Questions & Answers 1. In your own words, describe what is a combination circuit.: A combination circuit is a circuit that combines both parallel and series circuits. These types of circuits are used in many practical ways. One of them being used in the wiring of a household. 2. What is the definition of an equivalent circuit: A equivalent circuit is the theoretical version of a practical circuit, An equivalent circuit has values which are possible approximations of measurements the actual circuit would have. 3. What is the purpose of an equivalent circuit?: The purpose of an equivalent circuit is to give the creator of the circuit an idea of how the practical circuit should operate with the theoretical values the person calculated for resistance, voltage and current. 4. Apply KCL to the measurement results of Table 2 for the circuit of Figure 4. Current I(R1) (calculated) = V(R1) / R1 = 19.0 V / 13.54 kΩ = 1.404 mA Now, applying KCL to Node A: IT + I(R2) = I(R1) -8.83 mA - 2.97 mA = -1.404 mA -11.80 mA = -1.404 mA Node B (B): At Node B, the currents entering the node are: Current I(R2) (measured) = 2.97 mA (negative sign because it enters the node). Current I(R3) (measured) = 2.46 mA (negative sign because it enters the node). The currents leaving the node are: No other components are connected between nodes B and C. Ali A. Hussein, Ph.D., P. Eng. EMNG 1001, Circuit Analysis Lab Page 8
Applying KCL to Node B: I(R2) + I(R3) = 0 -2.97 mA - 2.46 mA = 0 -5.43 mA = 0 At Node C, the current entering the node is: Current I_(R_3) (measured) = 2.46 mA (negative sign because it enters the node). The currents leaving the node are: Current I(R4) (calculated) = V(R4) / R4 = 7.82 V / R4 I(R4) = 7.82 V / 13.54 kΩ = 0.579 mA Applying KCL to Node C: I(R3) = I(R4) -2.46 mA = 0.579 mA 5. Apply KVL to the measurement results of Table 2 for the circuit of Figure 4. KVL equation for Loop 1: V(R1) - V(R2,3) - V(R_2) = 0 Substituting the measured and calculated values: 19.0 V - 13.80 V - V(R_2) = 0 Now, solve for V(R_2): V(R2) = 19.0 V - 13.80 V = 5.20 V KVL equation for Loop 2: V(R2) - V(R2,3) - V(R3) - V(R4) = 0 Substituting the measured and calculated values: 5.20 V - 13.80 V - V(R3) - 7.82 V = 0 Now, solve for V(R3): V(R3) = 5.20 V - 13.80 V - 7.82 V = -16.42 V Ali A. Hussein, Ph.D., P. Eng. EMNG 1001, Circuit Analysis Lab Page 9
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6. Apply KCL to the measurement results of Table 3 for the circuit of Figure 5. Node 1 (junction between R1 and R2): I(R1,2) = 1.74 mA (measured) I(R3,4) = 0.77 mA (measured) IT = 2.54 mA (measured) KCL at Node 1: 1.74 mA + 0.77 mA - 2.54 mA = 0.97 mA I(R2) = 8.19 V / 6.72 kΩ = 1.22 mA (approximated using the measured V(R2) and R1,2) I(R3) = 4.35 V / 15.26 kΩ = 0.28 mA (approximated using the measured V(R3) and R3,4) Now, let's apply KCL at Node 2: KCL at Node 2: I(R2) - I(R3) = 1.22 mA - 0.28 mA = 0.94 mA IT = 2.54 mA (measured) Now, let's apply KCL at Node 3: KCL at Node 3: IT - I(R4) = 2.54 mA - 0.77 mA = 1.77 mA 7. Apply KVL to the measurement results of Table 3 for the circuit of Figure 5. Loop 1 (R1, R2, and voltage sources): V(R1) = 3.32 V (measured) V(R2) = 8.19 V (measured) KVL around Loop 1: V(R1) + V(R2) - V(R1,2) = 3.32 V + 8.19 V - 4.70 V = 6.81 V Loop 2 (R3, R4, and voltage sources): V(R3) = 4.35 V (measured) V(R4) = 7.64 V (measured) KVL around Loop 2: V(R3) + V(R4) - V(R3,4) = 4.35 V + 7.64 V - 4.74 V = 6.25 V Loop 3 (R1, R3, and voltage sources): V(R1) = 3.32 V (measured) V(R3) = 4.35 V (measured) KVL around Loop 3: V(R1) - V(R3) - V(R1,2) = 3.32 V - 4.35 V - 4.70 V = -5.73 V Ali A. Hussein, Ph.D., P. Eng. EMNG 1001, Circuit Analysis Lab Page 10