Hw chapter 10
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Industrial Engineering
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Apr 3, 2024
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10-21
. Using the average end area method, determine the required volume of the cuts and fills for a new road. The cuts and fills for each station are shown in Table 10.1. Express your answer
in cubic
yards. (5pts)
Cut
= ((0sf x 0’) + (257sf x 50’) + (50sf x 50’) + (20sf x 50’) + (0sf x 50’) + (0sf x 20’)) / 6
= 3,766.67cf x (1cy/27cf)
= 139.51cy
Fill
= ((0sf x 0’) + (0sf x 50’) + (50sf x 50’) + (285sf x 50’) + (233sf x 50’) + ( 0sf x 20’)) / 6
= 4,733.33cf x (1cy/27cf)
= 175.3cy 10-27. Six inches of topsoil is to be removed and stockpiled for the building in Figure 10.48. The
topsoil is to be removed 8 feet back from the perimeter of the building to allow for working around the building and sloping the sides of the excavation. How many bank cubic yards (bcy) of topsoil need to be removed and stockpiled? (3pts)
A1= (L1 x W1) - (L2 x W2)
= (42 x 53) - (12 x 27) A1= 1902 sf^2
A2= [(L1 + 16) x (W1 + 16)] - (L2 - W2) = [(42 + 16) x (53 + 16)] - (12 x 27) = 4002 - 324
A2= 3678 ft^2 A3= A2 - A1
= 3678 - 1902
A3= 1776 ft^2
V= (A1 + A3) x D
= (1902 + 1776) x [(6in x (1ft/12in)]
= 1839 ft^3
= 1838 ft^2 x (1cy/27ft^2)
V= 68.11cy
10-35. Determine the amount of excavation needed for the continuous footings in Figures 10.54 and 10.55. A one-foot working distance is required and the excavation will be sloped 1:1 (one vertical foot for every horizontal foot). (3pts)
Average width of cut = 2’ + 1’+ 1’+ 1’+ 1’
= 6’
Perimeter= 25’ + 21’ + 5’+ 20’ + 36’
= 122’ General excavation = 6’ x 122’ x 2’
= 1464 bcf x (1bcy/ 27bcf) = 54.22 bcy
10-43. Determine the quantity of asphalt and granular material required for the parking lot shown in
Figure 10.60. The asphalt is 4 inches thick and the granular material is 8 inches thick. (3pts)
Rectangle 99’ x 200’
Area= length x breadth
= 99’ x 200’
= 19800sf
Rectangle 23’ x 24’
Area=
length x breadth
= 23’ x 24’
= 552 sf
Total area Area = 19800 + 552 = 20352 sf
4 inches thick Asphalt = 20352 sf x (26tons/ 1000sf)
= 529.15 tons
8 inches thich
Asphalt = 20352 sf x ( 42tons/ 1000sf)
= 854.78 tons
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