Section 3
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School
Harvard University *
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Course
245
Subject
Mathematics
Date
Jan 9, 2024
Type
docx
Pages
2
Uploaded by MateFangScorpion33
1.
Solve for �
x
: 3
�
+7=223
x
+7=22
.
Answer
: �
=5
x
=5
.
2.
Find the value of �
y
if 2
�
−5=112
y
−5=11
.
Answer
: �
=8
y
=8
.
3.
Calculate the perimeter of a rectangle with length 1010
units and width
66
units.
Answer
: Perimeter = 2×(10+6)=322×(10+6)=32
units.
4.
Determine the value of �
z
in the equation 4
�
−9=234
z
−9=23
.
Answer
: �
=8
z
=8
.
5.
Solve the equation 2(
�
−3)=102(
x
−3)=10
.
Answer
: �
=8
x
=8
.
6.
Evaluate the expression: 53−2×45
3
−2×4
.
Answer
: 53−2×4=125−8=1175
3
−2×4=125−8=117
.
7.
Compute the area of a circle with a radius of 66
units (use �
=3.14
π
=3.14
).
Answer
: Area = �
×
�
2=3.14×62=113.04
π
×
r
2
=3.14×6
2
=113.04
square units.
8.
Solve the inequality: 2
�
+5>152
x
+5>15
.
Answer
: �
>5
x
>5
.
9.
Find the slope of the line passing through points (−2,4)(−2,4)
and (3,−1)(3,−1)
.
Answer
: Slope = −1−43−(−2)=−55=−1
3−(−2)−1−4
=
5−5
=−1
.
10.
Solve for �
y
in the equation 3
�
−7=83
y
−7=8
.
Answer
: �
=5
y
=5
.
11.
Calculate the volume of a cube with side length 44
units.
Answer
: Volume = 43=644
3
=64
cubic units.
12.
Factorize the quadratic expression: �
2+6
�
+9
x
2
+6
x
+9
.
Answer
: �
2+6
�
+9=(
�
+3)2
x
2
+6
x
+9=(
x
+3)
2
.
13.
Solve the system of equations: {2
�
+3
�
=124
�
−
�
=7
{
2
x
+3
y
=124
x
−
y
=7
Answer
: �
=2,
�
=2
x
=2,
y
=2
.
14.
Determine the midpoint between points (−3,4)(−3,4)
and (5,−2)
(5,−2)
.
Answer
: Midpoint = (−3+52,4+(−2)2)=(1,1)
(
2−3+5
,
24+(−2)
)
=(1,1)
.
15.
Find the value of �
z
in the equation 5(
�
+3)=405(
z
+3)=40
.
Answer
: �
=5
z
=5
.
16.
Calculate the surface area of a sphere with a radius of 1010
units
(use �
=3.14
π
=3.14
).
Answer
: Surface Area = 4×
�
×
�
2=4×3.14×102=12564×
π
×
r
2
=4×3.14×10
2
=1256
square units.
17.
Solve the inequality: 3(2
�
−5)≤213(2
x
−5)≤21
.
Answer
: �
≤8
x
≤8
.
18.
Find the domain of the function �
(
�
)=4
�
−9
f
(
x
)=4
x
−9
.
Answer
: �
≥94
x
≥
49
(to ensure the square root is non-negative).
19.
Simplify: 3
�
2−2
�
+1
�
−1
x
−13
x
2
−2
x
+1
.
Answer
: 3
�
2−2
�
+1
�
−1=3
�
+1
x
−13
x
2
−2
x
+1
=3
x
+1
.
20.
Solve for �
y
in the equation 2
�
+4=102
y
+4=10
.
Answer
: �
=3
y
=3
.
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