606 HW 6

Nj:(f}&)//c_@//q &:‘.;L;:-q__ 772:30 = Tf—‘/? & inod AN =2

Need hep with this Q.

Y(t) = t³e-t => Ys) =? A: 3 Y(s) (s + 1)+ B: 6 Y(s) (s + 1)3 C: 6 Y(s) (s + 1)+ D: 3 Y(s) (s + 1)2

M-(Izy z-ly.y) + My(1z.z – lzy -y) Iz.ly - Izy Pr My Formüller; a-- Pr Og + dy oå - da0p + o < oỷ , Jort = Tmaks 2t 0z + Oy + Ty , E = aAT, T-. Tc d'y M(x) Omaks.min 2 I dx? El + Ty tc/D MalanicoXc, @pỊc El Malanipc EI Tmaks = aM Mp dx, Par = VQ %3D It Find the critical buckling load if the length of the 10 cm * 12 cm sectioned bar with both ends is 4 m? E = 1.106 N/cm2 92.45 kN 75.64 kN 88,82 kN 61,68 kN 53,52 kN

M2(Izy.Z– ly-y) + M,(1z.z – lzy-y) 1z.ly - Izy? Pr Мy Formüller; o =- • Oy = Oz + Oy o - ạ0p + o < oỷ , Jort = , Tmaks 2 Pr •02 = 2 2t 2 Çelik Og + Oy Te d²y_M(x) Omaks.min + τ , ε αΔΤ, τ,. EI MalanıcoXc , @pjc EI 2 Malanıpc 2000 mm ) + ry tejp = Tmaks = EI Bakır ƏM dx. Pgr VQ M It If a copper ring with an outer diameter of 2000 mm and a thickness of 20 mm and a steel ring with an inner diameter of 2000 mm and a thickness of 10 mm are intertwined and heated up to 100 °C; a) Calculate the maximum stress in the steel ring. b) Calculate the pressure exerted by the copper ring on the steel ring. Copper = Ebakır= 100 GPa, abakıF 16.10-6/°C Steel = Eçelik= 200 GPa açelik= 12.10-6/ºC

please solve ture and clear

Need only handwritten solution only (not typed one).

Solve the following differential equation: y'"-2y' +y= e*Inx Select one: a. YG.s=C;Xe¯*+Czx²e*+e* Jinx+ xe-* [Inx = C, sinx+ c>cosx+ sinx Inx+cosx /Inx b. YG.S c. None O d. YG.s=C,xe*+czx²e*-e* ] xInx+e* ]x?inx YG.s=Ce*+c2xe* - e* | xlnx+ xe* | Inx е.

V:09)

Q1: Find force M. [2 Marks] M 70N 50 60 A) M-(50-70)N B) M-(70.1-80)N C) M-(80.1-1400)N D) M= does not include previous choices

Flow Speed in a Channel The speed of water flowing in achannel, such as a canal or river bed, is governed by theManning Equation,

Given: N1 = 10, N2 = 20, N3 = 30, N4 = 40 J1 = 1, J2 = 2, J3 = 3, J4 = 4, J5 = 5, D1 = 1, and D2 = 2 Determine: 01(s)/Tl(s) T₁(1) 0₁ (1) CC N₂ D2, J2 N₁ J₁. Di N3 J3 N4 N₂0 JS J4

6...

I need Answer For Both Problems Within 30Min. (I will Report if you Submit Only one problem) Problem gain formulae. Masino by eeing RCS) Feind CCs) レャ G3 CCs) RCS) L3 Le - HI -HL. - H3 Pobkme Det the T-F g the SF9 Phaon in G3 G4 Gz -HL. - H4. Lq, ーや。

For the beam and loading shown, determine the deflection midway between the supports. Assume that El is constant for the beam. A Wox3 w(x) = L3 L Wo B x

Apply the required method to arrive at the displayed expression. Method used and Four assumptions. T(x) =0-Ih(T - T,) + ɛo(Tky – Tt)] + T, 8. Q k Tred T

please check my solution thank you

1) From 0 to 10 sec, find alphaA1, alphaC1 in rad/s^2, omegaA1(t), omegaC1(t) in rad/s, thetaA1(t), thetaB1(t) and thetaC1(t) in rad, and the distance made by the load s1 in inches and in feet made by the load during this time.

I need a clear answer by hand, not by keyboard | dybala Suppose that a certain fraction of the power produced by a 350 MW coal plant is offset by wind power. Assume that when the coal plant runs at its constant rated power it has an efficiency of 37%, but that when it needs to be ramped up and down to compensate for the wind power variations its efficiency is reduced by according to e=0.37 -0.00001p², at what p the efficiency is maximum? Signature Head of Department

A 令 Wed 17 Mar 12: moodle1.du.edu.om DU - Moodle English (en) - Mohammed Ahmed Al Sarj Al Marhoon tion 6 et ered K ed out of 000 ag cion M (t) fv Mä + f,* + kx + f(1) = 0 Mä + f,x+ kx = f (t) c. fyä+ Mx + kx = 0 d. fä+ Mx + kx = f(t) а. b. %3D The differential equation of the system is Select one: а. с O b. b O C. d d. a étv W acBook Air DII DD F7 F8 F9 F10 F11 F12 V 9. P ]{ 3 * CO

Hw/ y= lux f Y=e? Find Df R. Hw/ solve: O log (x)+Log (x-1) = log (8x-12)-1a9L2) %3D An s/x=3 %3D

is it correct?? if it is correct,please tell me why r=0,z=H?? Thanks very much!!!!!

I have attemped to start the question by first using the equation: log_{10}W_{TO} = A+Blog_{10}(CW_{TO} - D) After working out some stuff I got to: log_{10}W_{TO} = 0.833+1.0383log_{10}(CW_{TO} - 53000) Using the info give, C = M_ff I tried calculating the M_ff but needed the weight ratios for both cruises, loiter, and flight to another airport. I used the range and endurance equations for loiter and flight to another airport but cannot do cruise as I do not have the Mach number. I don't know how to continue.

Q1 / Reduce the block diagram to the simple form R(s) S 13 S 0. S 1 S C(s)

Command: PLOTTERMANAGER (from the autocad file m TO CONFIGURE A LOCAL, NONSYSTEM PLOTTER 10. PROFILES-Controls the use of profiles. A profile is a configuration you define. 367N 367N R=1.0m 426N 426N B. 426N C. The two identical sphemes having oqual weights of 367N is placed on top of the three identic al sphere's w/ 426 N as their reight . Compute the reaction A,B and C