Final FV1 Kress

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The right half of the square loop of wire shown in (Figure 1) is in a 0.45 T magnetic field directed into the page. The current in the loop is 1.5 A in a clockwise direction Part A What is the magnitude of the force on the loop? Express your answer with the appropriate units. µA ? F = Value Units Submit Request Answer Part B In which direction does this force act? O to the left O to the right upward downward Figure < 1 of 1 Submit Request Answer Provide Feedback 5.0 cm X X X

The right half of the square loop of wire shown in (Figure 1) is in a 0.85 T magnetic field directed into the page. The current in the loop is 1.1 A in a clockwise direction. 1. What is the magnitude of the force on the loop?  Express your answer with the appropriate units. 2. In which direction does this force act? A. to the left B. upward C. downward D. to the right

The figure at right shows two current carrying wires, which are oriented perpendicular to the page. The currents are the same magnitudes but • A opposite directions as indicated by the usual convention. wire 1 wire 2 What is the direction of the the net magnetic field vector at point A. A. С. D. E. F. into the out of the page page B.

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°8. A circular loop is conducting current in a counter-clockwise direction as shown. wire carn A number of changes to this initial situation are described in 1-6 below. Select from choices a-e how each change will affect the magnetic field at the center of the loop.

From the experiment on tracing the magnetic field lines of the bar magnet, we understand the following: 1. The magnetic field lines of the earth is directed from to which was shown by the compass at the start of the experiment. 2. The field lines of the bar magnet was traced using following the north + of the compass needle. 3. The magnetic field of the bar magnet (outside) starts at + land ends at but we know that by nature the magnetic field lines are 4. are points where the field lines of the bar magnetic and earth's field are equal and opposite.

In the figure below we have a wire loop with resistance R. in the gray area, magnetic field is constant and equal to B Figure1 We assumed that wire loop in the figure below has a resistance R so the current generated is : I=vBh/R But what if R=0 (perfectly conductive material) What happens when we move the loop with speed v?

For each of the following diagrams, you will be shown the directions for two variables (v B or F) tor a positive charge moving in a uniform magnetic field and asked for the missing one using the right-hand rule. Remember that dots represent a vector pointed out of the screen and x's represent a vector pointed into the screen. a. What is the direction of the Force on this diagram? O A. right OB. left OD. down toward the bottom of the screen OC. up toward the top of the screen OE. out of the screen OF into the screen b. What is the direction of the Force for this diagram? O A. right O B. left OD. down toward the bottom of the screen OC up toward the top of the screen OE. out of the screen OF into the screen What is the direction of the motion for this diagram? C.

A 1.85 m long metal bar having a weight of 3.50 N and a resistance of 10.0 S2, rests horizontally on conducting wires connecting it to the circuit shown in (Figure 1). The bar is in a uniform, horizontal, 1.65 T magnetic field and is not attached to the wires in the circuit. Figure a = Submit Request Answer Part B What is the magnitude of the acceleration of the bar just after the switch is closed? Express your answer in meters per second squared to three significant figures. 15. ΑΣΦ to the left to the right 120.0 V downward upward Submit T 25.0 Ω www Request Answer 10.0 Ω What is the direction of the acceleration of the bar just after the switch is closed? S ? 1 of 1 m/s²

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Assume that I = 4.0 A andd = 2.5 cm Part A What is the strength of the magnetic field at the center of the loop in the figure? (Figure 1) Express your answer to two significant figures and include the appropriate units. ? B = 0.000064 You have already submitted this answer. Enter a new answer. No credit lost Try again. Submit Previous Answers Request Answer Part B What is the direction of the magnetic field at the center of the loop? Figure out of the screen 1 of 1 into the screen Previous Answers V Correct Provide Feedback d

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Two current-carrying loops are arranged so that they form concentric circles as shown in the figure below. The bigger loop (radius = 0.80 m) has a 5.00 A-current passing through it. The smaller loop has a radius of 0.40 m. 1. Draw the magnetic field (use 2 different colors) produced by each current carrying loop. 2. Determine the magnitude of the current in the inner loop so that the resulting net magnetic field at the center of the concentric loops will be zero. (Hint: This will only happen when the directions of the magnetic field produced by each loop are opposite in direction)

​Then the ions enter to velocity selector region. In this region both electric and magnetic fields are applied. Next theyenter into the mass spectrometer region. In this region there is magnetic field different than the previous region. Depending of the charge of the ions, they travel in a circular path with a well-defined radius either to the left or to the right. 1.The mass difference between two isotopes is sometimes just a neutron mass. The spectrometer should separate them very well. For such an isotope combination, the difference in radius should be around 1 cm. That is . In order to achieve this, choose a magnetic field with a magnitude in Tesla (maximum magnetic field you can obtain from a conventional magnet is around 2.5 T so be far away from this value) and choose the direction also. Then determine the velocity of isotope you need. Last calculate radius r of a smallest isotope. 2.In order to produce this magnetic field, determine the current and number of turns, radius and…

Multiple choice (briefly explain)

A wire that is 25 meters long carries a current of 15 A to the west. If the magnetic force on the wire due to Earth's magnetic field is 5.5 x 10-3 N downward (toward the ground), fınd the magnitude and direction of the magnetic field strength. Which formula will you use. Show your work. What is the field strength? * What is its direction?

The loop in (Figure 1) is being pushed into the 0.10 T magnetic field at 25 m/s . The resistance of the loop is 0.10 N. Part A What is the magnitude of the current in the loop? Express your answer with the appropriate units. HẢ ? Value Units Submit Request Answer Part B Figure 1 of 1 What is the direction of the current in the loop? V clockwise В counterclockwise Submit Previous Answers Correct Here we learn how to use Lenz's law to determine the direction of the cun 5.0 cm

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An electron moves at right angles to a magnetic field of 0.23 T. Part A What is its speed if the force exerted on it is 9.1x10-15 N? Express your answer using two significant figures. IVO ADC ? v = m/s