Assignment 9 Fa 2023
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University of Houston *
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Course
3316
Subject
Political Science
Date
Dec 6, 2023
Type
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4
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POLS 3316. Statistics for Political Science
Dr. Scott Basinger
Homework Assignment #9
Distributed Thursday, November 9, 2023
Due Thursday, November 16, 2023
Name
A survey conducted in 2006 asked 1,000 adult Americans to name
one
justice who is currently serving on the
United States Supreme Court. 430 respondents could name at least one justice.
1. The proportion of people
in the sample
who could name at least one Supreme Court justice equals _____ =
𝑝𝑝̂
.
2. Fill in the table below:
Standard error of
𝑝𝑝̂
Margin of error = 1.96 x standard error…
3. The 95% confidence interval for the proportion
of the population
who can name at least one Supreme Court
justice is between ______ and ______.
A recent survey asked parents whether they agreed with a series of controversial statements. One such
statement was, “Homework should be banned.” Out of 1,545 respondents, 250 parents answered yes.
4. The proportion of respondents
in the sample
who believe homework should be banned equals _____ =
𝑝𝑝̂
.
5. Fill in the table below:
Standard error of
𝑝𝑝̂
Margin of error = 1.96 x standard error…
6. The 95% confidence interval for the proportion of parents
in the population
who believe homework should be
banned is between ______ and ______.
The Public Religion Research Institute conducted a survey of 1,013 U.S. adults between January 18 – 22, 2017.
Respondents were asked to agree or disagree with the statement, “God rewards athletes who have faith with
good health and success.” 38 respondents refused to answer the question or said “don’t know.” Of the 975 who
responded,
⋅
499 respondents agreed (179
completely
agreed
; 320
mostly agreed
)
⋅
476 respondents disagreed (192
mostly disagreed
; 284
completely disagreed
)
7. The proportion of respondents in the sample who agreed
(
completely agree
+
mostly agree
) is _____ =
𝑝𝑝̂
.
8. Fill in the table below:
Standard error of
𝑝𝑝̂
Margin of error = 1.96 x standard error…
9. The 95% confidence interval for the proportion of the population who
agree
that God rewards athletes who
have faith with good health and success is between ______ and ______.
The 2014 General Social Survey asked respondents to agree or disagree with the following statement, “It is
much better for everyone involved if the man is the achiever outside the home and the woman takes care of the
home and the family.” Out of 1,655 respondents, 515 agreed and 1,140 disagreed.
10. The proportion of respondents in the sample who agreed with the statement equals _____ =
𝑝𝑝̂
.
11. Fill in this table:
Standard error of
𝑝𝑝̂
Margin of error = 1.96 x standard error…
12. The 95% confidence interval for the proportion of the population who believe that only men should be the
achievers outside the home is between ______ and ______.
Is there a gender divide? The sample consisted of 745 men and 910 women.
13. Of the 745 men, 247 agreed with the statement and 498 disagreed. The proportion of men
in the sample
who believe that only men should be the achievers outside the home is _____ =
𝑝𝑝̂
M
14. Fill in this table:
Standard error of men
sample proportion (
𝑝𝑝̂
M
)
Margin of error = 1.96 x standard error…
15. The 95% confidence interval for the proportion of men
in the population
who believe only men should be the
achievers outside the home is between _______ and _______.
16. Of the 910 women, 268 agreed with the statement and 642 disagreed. The proportion of women
in the
sample
who believe that only men should be the achievers outside the home is _____ =
𝑝𝑝̂
W
17. Fill in this table:
Standard error of women sample proportion (
𝑝𝑝̂
W
)
Margin of error =
z
* x standard error…
18. The 95% confidence interval for the proportion of women
in the population
who only men should be the
achievers outside the home is between _______ and _______.
19. Fill in this table to show every step necessary to perform a difference-of-proportions test of the null
hypothesis that equal proportions of men and women agree with the statement (i.e.,
π
M
–
π
W
= 0).
Difference of proportions
𝑝𝑝̂
M
–
𝑝𝑝̂
W
=
Standard error of
difference
of proportions
z
statistic
20. Performing a
z
test would lead you to re _ _ _ _ _ the null hypothesis of no difference.
Is there an education divide on this question? The sample consisted of 1,032 people without a college degree
and 623 people with a college degree.
21. Of the 1,032 people without a college degree, 383 agreed with the statement and 649 disagreed. The
proportion of less-educated respondents
in the sample
who believe that only men should be the achievers
outside the home is _____ =
𝑝𝑝̂
LE
22. Fill in this table:
Standard error of less-educated
sample proportion (
𝑝𝑝̂
LE
)
Margin of error = 1.96 x standard error…
23. The 95% confidence interval for the proportion of less educated people in the population who agree that
only men should be the achievers outside the home is between _______ and _______.
24. Of the 623 people with a college degree, 132 agreed with the statement and 491 disagreed. The proportion
of college educated respondents
in the sample
who believe that only men should be the achievers outside the
home is ____ =
𝑝𝑝̂
CE
25. Fill in this table:
Standard error of more-educated sample proportion (
𝑝𝑝̂
CE
)
Margin of error =
z
* x standard error…
26. The 95% confidence interval for the proportion of college educated people in the population who agree that
only men should be the achievers outside the home is between _______ and _______.
27. Fill in this table to show every step necessary to perform a difference-of-proportions test of the null
hypothesis that equal proportions of less-educated and college-educated people agree with the statement
(i.e.,
π
LE
–
π
CE
= 0).
Difference of proportions
𝑝𝑝̂
LE
–
𝑝𝑝̂
CE
=
Standard error of
difference
of proportions
z
statistic
28. Performing a
z
test would lead you to re _ _ _ _ _ the null hypothesis of no difference.
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Some useful equations:
Sample proportion (
𝑥𝑥
satisfy some condition among
𝑛𝑛
respondents or cases)
𝑝𝑝̂
=
𝑥𝑥
𝑛𝑛
Standard error of a sample proportion
𝑆𝑆
𝑝𝑝�
=
�
𝑝𝑝̂
(1
− 𝑝𝑝̂
)
𝑛𝑛
Margin of error for a sample proportion
𝑚𝑚
=
𝑧𝑧
∗
𝑆𝑆
𝑝𝑝�
=
𝑧𝑧
∗
�
𝑝𝑝̂
(1
− 𝑝𝑝̂
)
𝑛𝑛
Confidence interval for a sample proportion
𝑝𝑝̂
±
𝑚𝑚
=
𝑝𝑝̂
±
𝑧𝑧
∗
�
𝑝𝑝̂
(1
− 𝑝𝑝̂
)
𝑛𝑛
One-sample
z
statistic for a proportion against a null
hypothesis about the population proportion (
𝜋𝜋
0
)
𝑧𝑧
=
𝑝𝑝̂ − 𝜋𝜋
0
�
𝑝𝑝̂
(1
− 𝑝𝑝̂
)
𝑛𝑛
Difference of proportions (between samples)
𝐷𝐷
�
=
𝑝𝑝
2
� − 𝑝𝑝
1
�
Standard error of difference of proportions for
confidence interval for the difference between
population proportions (
𝜋𝜋
2
− 𝜋𝜋
1
)
𝑆𝑆
𝐷𝐷
�
≡ 𝑆𝑆
𝑝𝑝
2
�−𝑝𝑝
1
�
=
�
𝑝𝑝
1
�
(1
− 𝑝𝑝
1
�
)
𝑛𝑛
1
+
𝑝𝑝
2
�
(1
− 𝑝𝑝
2
�
)
𝑛𝑛
2
Confidence interval for the difference of population
proportions
𝐷𝐷
�
±
𝑧𝑧
∗
𝑆𝑆
𝐷𝐷
�
Standard error of difference of proportions for
difference-of-proportions test
𝑆𝑆
𝐷𝐷
�
𝑝𝑝
≡ 𝑆𝑆
𝑝𝑝
2
�−𝑝𝑝
1
�
=
�
𝑝𝑝̂
(1
− 𝑝𝑝̂
)
𝑛𝑛
1
+
𝑝𝑝̂
(1
− 𝑝𝑝̂
)
𝑛𝑛
2
Two-sample
z
statistic for a difference of
proportions test (against a null hypothesis of no
difference, i.e.,
𝜋𝜋
1
=
𝜋𝜋
2
)
𝑧𝑧
=
𝐷𝐷
�
𝑆𝑆
𝐷𝐷
�
𝑝𝑝