4.0 Student Essay

618 Words3 Pages
Simplifying Expressions While working on this problem I learned a lot about basic properties of addition and multiplication, such as distributive property, inverse property, commutative properties, etc. What’s common about these problems is the order in which we are going to do the steps. The first step will always be to remove the parenthesis, which uses the distributive property. Second will always be combining like terms and adding related coefficients what we have been working on this week which is dealing with real numbers. Here is the solution to the first problem: 2a(a-5)+ 4(a-5) =2aa+2a(-5)+4a-4⋅5 =2a^2-10a+4a-20 =2a^2-6a-20 The steps used to simplify this equation are as follows: First I remove all of the…show more content…
Although I still have parentheses in the equation, they are only there to emphasize the negative numbers. 20.05(0.3m+35n)-0.8(-0.09n-22m) =0.05⋅0.3m+0.05⋅35n-0.8⋅(-0.09n)-0.8⋅(-22m) The second step is to figure out the correct coefficients: 0.05⋅0.3m+0.05⋅35n-0.8⋅(-0.09n)-0.8⋅(-22m)=0.015m+1.75n+0.072n+17.6m The final step is to find the like terms and then combine them to obtain the simplified form: 0.015m+1.75n+0.072n+17.6m=17.615m+1.822n The expression is now fully simplified to 17.615m+1.822n In all three problems in this problem set, I learned how to simplify algebraic expressions using distributive property and commutative property. In the second problem I used the inverse property of addition. I noticed that the third problem was different from the first and second problems, in that in the third problem there were no integer numbers. This whole section is about real numbers so this problem set teaches us how to operate using both integer and non-integer real
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