Advantages And Disadvantages Of Round Robin Schedulinging In The Operating System

It will increase or decrease each division to the choosing time which will change the

6.10) I/O-bound projects have the property of performing just a little measure of computation before performing I/O. Such projects regularly don't use up their whole CPU quantum. Whereas, in case of CPU-bound projects, they utilize their whole quantum without performing any blocking I/O operations. Subsequently, one could greatly improve the situation utilization of the computer’s assets by giving higher priority to I/O-bound projects and permit them to execute in front of the CPU-bound

Dhrystone is especially designed to estimate integer performance of a processor based systems. A particular dhrystone score mentions number of times a fundamental function of a dhrystone source code is executed per second. Better this score is, the better is the performance of a processor. To calculate time taken by a dhrystone fundamental function, dhrystone uses standard “times(2)” function by default. However, “times(2)” provides time values in terms of processor clocks consumed. To have this value in seconds dhrystone also requires specification of clock rate used by a processor. Therefore, it is a convention to provide dhrystone score with a clock rate. However, there is no need of specifying clock rate, if the time calculations are performed using standard “time(NULL)” function. For emulators, time calculations are done using standard “time(NULL)” function. Hence, in this report no clock rates are specified with dhrystone scores associated with

Ans: As thread is a shared one and it doesn’t store the data instead it shares the data. so Thread uses smaller resources than the process. A context should be created, that includes a register set storage location for Storage at the time of context switching, and a local stack for recording all the procedure call arguments, return values, return addresses, and thread-local storage. Creating a process results in the memory that is being allocated for instructions of program and data, as well as thread-like storage. Code may also be loaded into the allocated memory.

This will allow the values of the CPU registers and memory allocation to be saved. Context switches are able to flush data and have instruction caches.

In Symmetric Multiprocessor systems performance is high since each processor will have its own CPU, registers and cache. The processes will be allocated to each processor separately and each process runs on its own. So, if there are 3 processes then there will be 3 CPU’s which runs simultaneously and hence all the 3 processes will be completed at the same time. But in Asymmetric Multiprocessor systems performance is not high as symmetric because the operating system can process only one request at a time. Only after the process allocated

for the next time slot of a core can consume a lot of time in

b) It also consumes the least amount of time in all the cases (approx.) since its best and worst case performance are O(n log n)

Suppose that the last SampleRTT in a TCP connection is equal to 1 sec. The current value of TimeoutInterval for the connection will neces- sarily be  1 sec.

here we have to find time required to send first packet from source to first packet switch.

is as good as the unitary nanosecond, and thus the delays in arrival time produced by the

Now as per algorithm if there is valid triple matching then this is the set of jobs where intervals are completely disjoint, hence we can accept this set of jobs to run on the processor as there is no overlapping. The size of the multiple interval scheduling is polynomial n.

Throughput can only go as fast as the bottleneck, therefore non-bottleneck resources should only be producing at the bottleneck rates even if that means that there is idle time.

Using Little’s Formula we have done Lead Time Analysis (Exhibit 4) which shows that on an average Lead Time is approximately 2 days (2.10). As we have seen, throughput on the other hand is approximately 6 days which is much higher than the average Lead Time. This suggests that the longer throughput time is because of allocation problems described

Once we began our changes, we had to make more assumptions since we realized that we had to be able to divide the first operation into two parts, as the operation time was 100 seconds, greater than the maximum cycle time needed (90seconds) to achieve our goal of 300 computers in a shift.  We also assumed that with an upgrade, we could change the hardware testing software activity time to 50% of the original time. We also assumed we could change the screwing operations to decrease the needed time by changing the action to