2. Indicate on your pedigree chart the individuals who are carriers by shading half of each circle or square.
2. Sort the data by Gen or Gen 1 (into males and females) and find the mean and standard deviation for each gender for the following variables: Use the descriptive stats function for one gender and the Fx functions (average and stdev) for the other.
Apply your understanding of how alleles assort and combine during reproduction to evaluate a scenario involving a monohybrid cross.
14. In a flower garden, the gardener has purple and white pansies. He notices that a new pansy has sprouted. When it finally flowers, the pansy is lavender. Explain how this happened. (5 points) This would happen in a case incomplete dominance. The white pansies nor the purple ones genes dominated making a 50/50 offspring.
Using the Hardy-Weinberg equation, calculate the predicted genotype frequencies for each population scenario below. Place your calculations and data in the space provided below. Once you have calculated the frequencies, answer the conclusion questions for each one. Please remember that all calculations must be shown for full credit.
1. A black guinea pig is crossed with an albino guinea pig, producing 12 black offspring. When
Over five trials the average allele frequency with this change in the migration rate is 0.366.
Read the background information in the Question Column under “How can Punnett Squares help predict the traits of offspring?”
This data can be further used by analyzing and providing additional information about the influences of certain characteristics on population genetics.
You are also provided with a heterozygous female, and a homozygous recessive male for a genetic cross. In this particular female, all the dominant alleles are on one chromosome, and the recessive counterparts are on the other homologous chromosome. Due to a chromosomal condition, in the female no recombination occurs between the M and N loci. Normal recombination occurs between the L and M loci. Diagram this cross, and show the genotypes and frequencies of all offspring expected from this cross.
Based on your results for the female offspring, predict whether color blindness is a dominant or recessive trait. Explain your reasoning.
Lindsey used 2 cups of red crystal light and 2 cups of water to illustrate homozygous. Students identified which two pairs were the same. Lindsey mixed the two cups of water and two cups of red crystal light. The two pairs stayed the same when mixing to illustrate
This equation is used to calculate the genotype frequency, so 1 = 100% of the population.
If there are three alleles, they extra attention needs to be paid. Three alleles does not mean multiply the frequency three times. Still two alleles will define a certain phenotype. For example, if we want a pq phenotype when there are three alleles: p,q,r. Then we use the frequency of p(p/n), multiply with the frequency of q(q/n). However, the sequence in this case does not matter, whether we draw a q first or a p first still can make a pq. Thus we need to multiply it with 2 as well. And the final possibility of us getting a pq is
This table helps show all the possible genotypes from one set of parents. The table shows that the genotypes purple and starchy are dominant, and the genotypes yellow and sweet are recessive.(stallsmith)