Angle of Shooting in Soccer

1434 WordsJul 11, 20186 Pages
It was about 3 minutes before the time was called. The red light from the score billboard showing “2-1” represented our team’s frustration to win that one more point in order to break even. The cheering sound of the crowd reverberated through the ground; chased by the other two players from the opposing side, I ran as fast as I could toward the opponent’s goal; it was our last chance of scoring. My heart started pounding rapidly, I ran closer to the goal, and took the shot. I missed. My dad started teaching me to play soccer since I was very young. He used to be a soccer team’s captain when he was in university, so he was very good at soccer. Every weekend, he would bring my brother and me to a soccer field in our neighborhood, and we…show more content…
Therefore, I tried using tan. Assuming that the position that gives the widest angle is located x meters from the corner. To make it easier to see, I constructed two triangles in green and red. Then I let the smaller angle be α (green), and the bigger angle be β (red). The angle I wanted to maximize is the difference between the two angles (as shown by θ°). Therefore, I tried to find α and β. As tan = opposite/adjacent , tan β = 35.66/x and so in order to find the angle “β” I used arctan β = arctan (35.66/x) Similarly, tan α = 28.34/d ,and so the angle “α” would be α = arctan (28.34/x) Then, I found the equation that determine the shooting angle: f(x)= β - α = arctan (35.66/x) - arctan (28.34/x), when x is the length from the corner to the soccer player. Optimization Once I got the function to find an angle subtended by the two goalposts using the distance from a corner to a player’s position, I tried graphing the equation (Figure 3 [Right] ) in my calculator to take a closer look at the
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