#include #include #include #include #include #include int PID[100], CPU_time[100], IO_time[100], arrival_time[100], flags[100],ID_ready[100]; int rQ[100], bQ[100]; int f_CPU = 0, r_CPU = 0, f_IO = 0, r_IO = 0; // a function that dequeue an element from a queue int deque(int state, int N, int ID) { int temp, var, i, index; if (state == 0) { //deque from ready_queue var = rQ[f_CPU]; rQ[f_CPU] = -1; f_CPU++; if (f_CPU == N) f_CPU = 0; } if (state == 1) { //deque from blocked_queue for (i = 0; i < N; i++) { //search for ID in the blocked queue if (bQ[i] == ID) { index = i; break; } } if (bQ[f_IO] != ID) { //sort the elements of the blocked_queue to deque from the place pointed by f_IO temp = bQ[f_IO]; bQ[f_IO] = ID; bQ[index] = temp; } var = bQ[f_IO]; bQ[f_IO] = -1; f_IO++; if (f_IO == N) //check if end of queue reached f_IO = 0; flags[ID] = 0; } return var; } // a function that enqueue an element in a queue void enque(int _id, int state, int N) { if (state == 0) { //enque in ready_queue rQ[r_CPU] = _id; r_CPU++; if (r_CPU == N) r_CPU = 0; } else { //enque in blocked_queue bQ[r_IO] = _id; r_IO++; if (r_IO == N) r_IO = 0; flags[_id] = 1; } } // a function for first come first served algorithm void FCFS(int N) { int n, m, k, p, j, ID, time = 0, temp, counter = -1, run_flag = 0, finish_counter = 0; int turnaround_time[N], data[N]; float run_count = 0; FILE *output = fopen("FCFS.out",
2, 2, 0, 5,1, 4,1, 3, 0, 0, 1, 4, 4, 0,1, 4, 3, 4, 2, 1
2, 2, 0, 5,1, 4,1, 3, 0, 0, 1, 4, 4, 0,1, 4, 3, 4, 2, 1
The main thing is to basically say nope to whatever the enemy tries to do whether it is playing a big scary creature or putting the brakes on the mill engine. Two of the main stall cards for blue is “Negate” and “Cancel”. “Negate” allows the player to negate an opposing player’s spell which is normally aimed at the enchantments, while “Cancel” puts a stop from a creature from being played on the board. On the other hand summoning creatures that are also known as defenders helps to stall since they have a high toughness rating so most creature attacks won’t deal any permanent damage to your life total since it is highly unlikely that the opponent will not have any creatures at any point in the game.
for (int j=i+1; j < n; j++)// defines j as one larger than i, compares j to n, increments j each iteration
2, 2, 0, 5,1, 4,1, 3, 0, 0, 1, 4, 4, 0,1, 4, 3, 4, 2, 1
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During adverse weather conditions which of the fundamental assumptions of queueing theory discussed in class is violated? Discuss how, in reality, does the system function in spite of this violation?
If the time exceeds four minutes, then stop the timer and move onto the next beaker. Repeat this process for Beakers 2, 3 and 4. Record the data in seconds. Repeat this experiment at least three times for a total of three
Let’s say there is a line of customers during the lunch rush at your average fast food restaurant. The line is taking extraordinarily long because there is only one person running the register and one person
The current iteration is denotes by $t$, The position of selected $j-th$ antlion at $t-th$ iteration and $i-th$
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The theme of a message is what the author or the speaker wants his audience to pay attention to, hence it is placed in the forefront of the clause. The theme has to be at the beginning of the sentence to be identified as a theme while the subject can be predicated. For example in the clause: My family and I visited the orphanage, ‘my family’ is the theme because it is the starting point of the message and ‘I’ is the subject because it is predicated and it is
HORDER in FMDump table. if the status of the order is Disconnected or Void then we delete the record from radius.radCheck and radius.radReply table.
For the application of cross-gradient function, the coupled parameter models are assumed to have similar structures. Therefore, the structures of true models are designed in the similar way in the following examples, and the physicochemical relationship between the medium elastic and electromagnetic properties are not strictly defined. In this situation, the elastic and electromagnetic properties are negatively associated in example 1 and positively associated in examples 2 and 3. The initial models are critical for the solution of FWI problem. In practice, the initial P-wave velocity and permittivity model could be recovered by velocity analysis, and the initial conductivity model could be provided by electrical resistivity tomography. In
t = 0; Q = 9 * (1 - e^(-t / 4)); % Condition-Controlled loop used do time = sprintf("%1.1f", t); % the display statement below comprises of concatenation disp(cstrcat("Time: ", num2str(time), " ; ", "Charge : ", num2str(Q))) ; t = t + 0.1; Q = 9 * (1 - e^(-t / 4)); until Q>=8 The output of the program is: Time: 0.0 ; Charge : 0 Time: 0.1 ; Charge : 0.22221 Time: 0.2 ; Charge : 0.43894 Time: 0.3 ; Charge : 0.65031 Time: 0.4 ; Charge : 0.85646 Time: 0.5 ; Charge : 1.0575 Time: 0.6 ; Charge : 1.2536 Time: 0.7 ; Charge : 1.4449 Time: 0.8 ; Charge : 1.6314 Time: 0.9 ; Charge : 1.8134 Time: 1.0 ; Charge : 1.9908 Time: 1.1 ; Charge : 2.1639 Time: 1.2 ; Charge : 2.3326 Time: 1.3 ; Charge : 2.4973 Time: 1.4 ; Charge : 2.6578 Time: 1.5 ; Charge : 2.8144 Time: 1.6 ; Charge : 2.9671 Time: 1.7 ; Charge : 3.1161 Time: 1.8 ; Charge : 3.2613 Time: 1.9 ; Charge : 3.403 Time: 2.0 ; Charge : 3.5412 Time: 2.1 ; Charge : 3.676 Time: 2.2 ; Charge : 3.8075 Time: 2.3 ; Charge : 3.9357 17 Time: 2.4 ; Charge : 4.0607 Time: 2.5 ; Charge : 4.1826 Time: 2.6 ; Charge : 4.3016 Time: 2.7 ; Charge : 4.4176