preview

Battery Light Lab Report

Decent Essays

Think about the situation you have two lights that have different is this resistance is and both are connected via wires in series with an electrical sore switch in our case is a battery. One of the lights close very brightly, all the other light is very dim, and if it even is blowing, there's a chance that is not. With our knows that we know as of now and physics, we know that the current will flow through both of the bulbs, and it will not matter which the voltage flows through first, that it will all add to the total voltage in the battery in the end. But why is it that one of the batteries glows so much better than the other? The first thing that we must at determine, is what it was the thing that chooses the brightness of the bulb, and is it due to …show more content…

Obviously it is not due to the current because both have the same electrical current flowing through them. When we look at the equation P= IV, P being the power output I being current Envy being voltage drop, the current through both bulbs must've been the same if they were wired in series, therefore the voltage drop must have been much higher for the glowing bulb, and it resulted in the larger power output on like the other bulb which probably had a lower power output. Homes law states that the voltage drop is equal to the current flowing through times resistance. The resistance of the battery had a direct effect on the power output because again the current stay the same throughout the circuit. Power is still giving off by both, but because one of the resistance is is higher and one of the bulbs it burns much brighter, Andrews results in more light being output. The next thing that we must ask ourselves is where is the rest of the energy going? And the answer to this is that is going into

Get Access