1485 Words6 Pages

Applied mechanics laboratory report
“Measurement of bending moment and shear forces for structural analysis”
Azamat Omarov
ID201102658
1.Theory and background
1.1 Summary
That performed laboratory session on bending moments and shear forces requires good understanding and sufficient knowledge of axial forces. Bending is defined as a behavior of any structural element that undergoes the external load, which is applied perpendicularly to longitudinal axis. That experiment helps us to find the maximum load that can be applied to the beam with rectangular cross section. Moments are calculated by using statics theory, or multiplying perpendicularly directed load by the respective distance to the pivot point.
1.2 Objective
The main objective*…show more content…*

Thar resulted in the maximum bending moment occurred. Moment was calculated in the same manner as in the previous example with only the difference in direction for positive moment. ∑MR1(left)= ∑MR1(right) ; R1*0.2 - P2*0.34=(R2-P3)*0.24; The resultant bending moment was found to be maximum at the point where shear forces are minimal and thus equals to approximately +0.3856 N.m Regarding the moment about the cut, here our group was able to find the minimum difference between the measured and calculated values applying the same formulas and assumptions.The resultant moment was calculated to be 0.225N.m , which is approximately 3% difference and thus can be neglected. It is clear from the bending moment diagram that there is a point except ends where bending moment equals to zero. Such a point have a different of bending moment on its two sides (left and right) is known as a point of contra-flexture. It can be easily found by using moment equation about that point and equate it to zero. Taking that reference point as “X”, we obtain: ∑MX(left)= ∑MX(right); 5.26*(X-0.14) = 1.962*X Thus the point of contra flexture for those specific loads equals 0.223m or 223mm from P1 Figure 7. Bending moment graph 4. Discussion and

Thar resulted in the maximum bending moment occurred. Moment was calculated in the same manner as in the previous example with only the difference in direction for positive moment. ∑MR1(left)= ∑MR1(right) ; R1*0.2 - P2*0.34=(R2-P3)*0.24; The resultant bending moment was found to be maximum at the point where shear forces are minimal and thus equals to approximately +0.3856 N.m Regarding the moment about the cut, here our group was able to find the minimum difference between the measured and calculated values applying the same formulas and assumptions.The resultant moment was calculated to be 0.225N.m , which is approximately 3% difference and thus can be neglected. It is clear from the bending moment diagram that there is a point except ends where bending moment equals to zero. Such a point have a different of bending moment on its two sides (left and right) is known as a point of contra-flexture. It can be easily found by using moment equation about that point and equate it to zero. Taking that reference point as “X”, we obtain: ∑MX(left)= ∑MX(right); 5.26*(X-0.14) = 1.962*X Thus the point of contra flexture for those specific loads equals 0.223m or 223mm from P1 Figure 7. Bending moment graph 4. Discussion and

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