Biology Heat Loss Practical Write Up

To make the results of the experiment valid four variables to take into account are if the freezer is the same temperature for both tests, the water is the same water just different temperatures, the ice cube trays are the same size, and finally both trays are in the freezer for the same amount of time.

What is a ratio?  What are the different ways of expressing the relationship of two amounts?  What information does a ratio provide?

2. How did concentration and/or volume differences affect the heat change (q) for each trial?

My calculated volume values were found by using the Charles’ Law formula: V1/T1=V2/T2. My Trial A values (20 mL and 293.15 K) were the V1 and T1 values. The temperatures measured in Trials B, C, D, and E were the T2 values. The quantitative relationship between the volume and the absolute temperature of a gas is summarized in Charles’ Law. This law states that at constant pressure, the volume of a particular sample of gas is directly proportional to the absolute temperature. In other words, there is a direct relationship between temperature and the volume of gas. In an actual laboratory, it must be ensured that the hot water is below 50ºC. If it is not, the sealed syringe will soften and it could explode.

Abstract: This experiment introduced the student to lab techniques and measurements. It started with measuring length. An example of this would be the length of a nickel, which is 2cm. The next part of the experiment was measuring temperature. I found that water boils around 95ºC at 6600ft. Ice also has a significant effect on the temperature of water from the tap. Ice dropped the temperature about 15ºC. Volumetric measurements were the basis of the 3rd part of the experiment. It was displayed during this experiment that a pipet holds about 4mL and that there are approximately 27 drops/mL from a short stem pipet. Part 4 introduced the student to measuring

We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL.

(0.623) x (square feet of surface area) x (% from lab demo*) = gallons of water

The Effect of Different Temperature Water on Alka-Seltzer Dissolving Time The Effect of Different Temperature Water on Alka-Seltzer Dissolving Time Trial 1 Trial 2 Trial 3 Trial 4 Trial 5 Average 30 °C 90.00 sec 97.74 sec 73.63 sec 101.94 sec 70.13 sec 86.72 sec 50°C 50.01 sec 80.59 sec 90.16 sec 87.15 sec 70.81 sec 75.74 sec 70°C 56.65 sec 56.57 sec 56.60 sec 56.80 sec 57.16 sec 56.76 sec 90°C 20.85 sec 27.78 sec 28.78 sec 27.35 sec 29.91 sec 26.95 sec 110°C 25.41 sec 24.03 sec 21.73 sec 22.14 sec 26.17 sec 23.90 sec Figure 1 The data table is showing the relationship between temperature of water and dissolving time of Alka-Seltzers. Alka-Seltzers were placed in 30°, 50°, 70°, 90° and 110° water.

The value determined in question 4 is the enthalpy change value you will need for Conclusion question 1 below.

The amount of deionised water that is placed in the conical flask must be the exact same

The next step in this lab is to rinse the Erlenmeyer flask with distilled water down the drain and then repeat the experiment, this time adding 10 ml of 0.10M KI and 10 ml of distilled water to the flask instead. The flask should again be swirling to allow the solution to succumb to the same temperature as the water bath and once it has reached the same temperature, 10 ml of 3% H2O2 must then be added and a stopper must be immediately placed on the flask and recording should then begin for experiment two. After recording the times, the Erlenmeyer flask must then be rinsed again with distilled water down the drain. After rinsing the flask, the last part of the lab can now be performed. Experiment three is performed the same way, but instead, 20 ml of 0.10 ml M KI and 5 ml of distilled water will be added and after the swirling of the flask, 5 ml of 3% H2O2 will be added. After the times have been recorded, data collection should now be complete.

Surface area is a two-dimensional measurement, and is proportional to the square of its length.

In order to obtain the true volume of volumetric glassware holds, this formula will be used.

Heat transfer processes are prominent in engineering due to several applications in industry and environment. Heat transfer is central to the performance of propulsion systems, design of conventional space and water heating systems, cooling of electronic equipment, and many manufacturing processes (Campos 3).

4. Remelt the contents of the tube and add the counterpart component based on the given schedule. Ask the demonstrator to adjust the cooling water between mixtures. During the experiment, record and plot the data obtained for all mixtures listed. The experiments are stopped as follows: