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Blue Eye Genotics

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1: For eye color in humans, assume that the allele (version of the gene) B (brown) is completely dominant to b (blue). Suppose Alex has brown eyes, but his mother had blues eyes. Suppose Betty has blue eyes. Give the expected and phenotype (what you see), percentages (or ratios) for Alex and Betty’s children.
Brown = B (dominate gene)
Blue = b (recessive gene)
Using the laws of Mendelian of inheritance using complete blending, If Brown is dominate but Betty has Blue eyes then it is assumed that her phenotype is bb added that her parents eye color was not mentioned. Note: that Alex’s mother was. If Alex has Brown eyes and his mother had Blue eyes then it is indicated that Alex will be Heterozygous Allele paired or Bb. The chart (Punnett square), or figure 1 below shows the possible offspring Phenotypes of their …show more content…

Give all possible combinations of her Father’s and Mother’s genotypes.
Brown = B
Blue = b
Using complete blending and If Brown is dominate but and the child was born with Brown colored eyes. Giving the idea off question 1, again using the laws of Mendelian inheritance; The Brown eye dominance play truth to the chart or figure 2. The parents would be more Homozygous Brown dominate or BB. The Father would have a dominate Bb and the mother would have Bb dominates, which would explain the reason the girl has brown eyes over the secular Blue eye color as seen in figure 2 regardless of which gene or allele is first: example Bb, bB or BB. QUESTION 2 - Figure 2 BETTY Phenotypes: Brown (B) 3 75% ALEX B b 4 B BB Bb Blue (b) 1 25% b Bb bb 4

3: (a) Suppose skin color in a frog is determined by two alleles: B (blue) and Y (yellow). B and Y show incomplete dominance, where BY heterozygotes are

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