Results of Catalase Reactions
Background:
An enzyme is a protein that acts as a catalyst to start a reaction. Enzymes are able to break down large molecules into smaller molecules in order for it to be easily absorbed by the body. Not only can enzymes break molecules, but they can link two molecules together to create a whole, new molecule. A catalyst enzyme’s main function is to speed up the rate at which a reaction is going. It does this by creating a new reaction with a lower activation energy. The substrate that this enzyme works on is hydrogen peroxide (H2O2). The balanced chemical equation for the breakdown of hydrogen peroxide is 2 H2O2 ----> 2 H2O+O2 (g). This balanced equation represents the decomposition of the hydrogen peroxide
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The factor that was tested in this lab was the type of catalyst. The catalysts tested were beef liver, chicken liver, and potato. The amount of oxygen gas produced differed among the different catalase. The purpose of this experiment was to determine whether the type of catalyst affects the amount of oxygen produced in the reaction.
Hypothesis:
If we change the type of catalyse from beef liver to chicken liver then the chicken liver will have higher levels of 02 produced because of the amount of catalase present. The independent variable in this experiment is type of catalyst and the dependent variable is the amount of oxygen produced.
Method:
Get materials such as 12 small disks, bucket, graduated cylinder, Hydrogen Peroxide (H2O2), and water.
Fill bucket ¾ full of
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To ensure accurate results, measurements were recorded precisely at each 30 second mark. The group was very focused on getting the information needed to create a successful table and graph. (add more)
Discussion:
This lab proved our hypothesis wrong because the beef created the biggest reaction by producing the most oxygen. The hypothesis stated that the chicken would likely produce the most O2. Some possible errors that could have affected the data is different amounts of the catalase distributed onto the disks as well as wrong measurements taken during the 30 second intervals. Some improvements that could’ve prevented possible errors is a longer time to collect data and determine the amount of oxygen produced. It is important for an organism to maintain homeostasis because it if homeostasis does not occur, the catalysts and substrates may not react efficiently and cause other problems in the
Five different temperatures of enzyme (spinach extract) (5°C, 20°C, 35°C, 45°C and 65°C) were added to individual measuring cylinders -each filled with 7ml of Hydrogen Peroxide (H202). The height of foam (oxygen + water) produced by the reaction was recorded for each temperature of the catalase after 30 seconds, to find at which degrees the enzyme activity had the fastest reaction rate. The data collected from this experiment suggested that the enzyme extract had the greatest efficiency at 20 °C, and the temperatures greater displayed a decline in rate of reaction.
The lab leaders and the Punk Rock Warlord prepared three different concentrations of catechol oxidase by extracting potato juice (because it contains lots of catechol oxidase). Pure catechol, a 5mL test tube, 1mL/5mL
Objective: Measure the rate of decomposition of hydrogen peroxide with and without the addition of an enzyme catalase at different time intervals.
This experiment looked at how substrate concentration can affect enzyme activity. In this case the substrate was hydrogen peroxide and the enzyme was catalase. Pieces of meat providing the catalase were added to increasing concentrations of hydrogen peroxide in order to measure the effect of hydrogen peroxide concentrations on the enzyme’s activity. The variable measured was oxygen produced, as water would be too difficult to measure with basic equipment.
The topic of this lab is on biochemistry.This experiment was conducted to show how cells prevent the build of hydrogen peroxide in tissues. My group consisted of Lekha, Ruth, and Jason. There were used two different concentrations of hydrogen peroxide through this experiment , 1.5% and 3%. By testing two different types it is easier to understand how the H2O2 and catalase react with one another. To do this both the yeast, which was our catalase, and H2O2 were mixed together in a beaker. Each concentration was tested out twice for more accurate results . 1.5% concentrated H2O2 had an average reaction rate of 10.5 seconds while 3% concentrated H2O2 had an average reaction rate of 7.5 seconds. From this experiment we learned that by increasing the concentration of H2O2 and chemically combining it with a catalase it will speed up the reaction. Enzymes speed up chemical reactions . The independent variable in this experiment was the concentration of the H2O2. Some key vocabulary words are Catalase, enzyme, hydrogen peroxide ( H2O2), and concentration.
peroxide there is in 5.0mL of the reacted solution; to figuring out exactly how much
As seen on table 1, the hypothesis in the introduction of this lab has been supported by the procedures. As the temperature varied from catalases optimal of 37° C, the reaction rate of catalase decreased. 37°C had the highest reaction rate of the three, at 3, while 4°C had the middle rate of reaction at 2.5, and 100° C had the lowest reaction rate of 0.5.
The purpose of this investigation is to discover the effect of pH on the activity of catalase, an enzyme which plays the integral role of converting hydrogen peroxide into water and oxygen, and discover which pH level it will work at the most efficient rate (the optimum). The original hypothesis states that that the optimum would be at a pH is 7, due to the liver, where catalase usually resides, being neutral. The experiment consists of introducing the catalase to hydrogen peroxide, after exposure to certain solutions; hydrogen peroxide, water and hydrochloric acids, all containing the adjusted pH, and measuring the height of froth formed, an observable representation of the activity of the enzyme. The final data indicated that
generally act as a catalase that initially bring about a chemical reaction.” Enzymes play an
Extension: Comparing the trends shown in enzyme activity increase in catalase activity when no inhibitors are added to when a set amount of competitive inhibitors are added and a set amount of non-competitive inhibitors are added could extend this lab. Another possible extension is comparing the efficiency of catalase to other peroxidases by conducting the same experiment and seeing which enzyme will have the highest rate of reaction overall. Furthermore, one could compare the amount of catalase in an organism/part of an organism by finding the rate of reaction of different origins of catalase under the exact same conditions with an excess of hydrogen peroxide
This experiment is designed to analyze how the enzyme catalase activity is affected by the pH levels. The experiment has also been designed to outline all of the directions and the ways by which the observation can be made clearly and accurately. Yeast, will be used as the enzyme and hydrogen peroxide will be used as a substrate. This experiment will be used to determine the effects of the concentration of the hydrogen peroxide versus the rate of reaction of the enzyme catalase.
This investigation will be carried out to investigate the rate of reaction of the enzyme catalase on the substrate hydrogen peroxide.
The null hypothesis for the first experiment was that substrate concentration would have no effect on the reaction rate. It was hypothesized that the reaction rate would increase with rising substrate concentrations, until all active sites were bound. The null hypothesis for the second experiment was that temperature would not have an effect on reaction rates. It was hypothesized that until the enzyme is denatured, as temperature increased, so would the reaction rate.
The chemical hydrogen peroxide(H₂O₂) is broken down by the enzyme catalase. Hydrogen peroxide is a byproduct formed in cellular reactions that, if not broken down, could inflict severe damage to the cell. Catalase is an enzyme that breaks down hydrogen peroxide in to water and oxygen. How efficient and strong the enzymes reaction to break down H₂O₂ determines largely on temperature and pH level. An enzyme only functions within a set pH and temperature range. Beyond that it becomes denatured, rendering it useless. The purpose of this lab is to determine at which temperature and pH level the enzyme catalase reacts best. Catalase in chicken and beef livers will be used to do the lab because enzymes still function after death as long as they are kept refrigerated at a low temperature.
The purpose of this lab report is to investigate the effect of substrate concentration on enzyme activity as tested with the enzyme catalase and the substrate hydrogen peroxide at several concentrations to produce oxygen. It was assumed that an increase in hydrogen peroxide concentration would decrease the amount of time the paper circle with the enzyme catalase present on it, sowing an increase in enzyme activity. Therefore it can be hypothesised that there would be an effect on catalase activity from the increase in hydrogen peroxide concentration measured in time for the paper circle to ride to the top of the solution.