Ccna

In the Network Design Paper I will explain how the University has recently leased a building in Adelphi, Maryland. The measurements of the University is 240 feet long, 95 feet wide and 30 feet tall and broken down to two different floors. This University will be used for education purposes of course, the facility will be made of six instructional labs, seven offices, library, five classrooms, a student lobby and a computer lab. There will be a server room on each floor. The purpose of this paper is to explain the design of the networks in this building. The student accessed computers will be set up on a separate network than the network that they staff will be using.

4) In IP subnet planning, you need to have at least 130 subnets. How large should your subnet part be?

5 bits need to be borrowed with a total of 32 subnets. There will be a total of 2046 hosts per subnet. 211=2048 2048-2=2046

Nurse Anesthetists are also known as CRNA, which means Certified Registered Nurse Anesthetists. Being a CRNA, one has big shoes to fill when it comes to their job. CRNA’s work with anesthesiologist surgeons and other physicians and medical professionals to give anesthesia to patients undergoing medical and surgical procedures. CRNA’s care for patients before, during and after a medical or surgery by doing a patient assessment , preparing the patient for anesthesia, they must maintain the anesthesia throughout the whole procedure to secure the proper sedation, and pain management, and as a CRNA they must make sure the patient recovers from the anesthesia properly. CRNA’s usually overshadow anesthesiologists. They perform much of the work

2. Enterprise networks typically use LAN _____ at each site to connect devices using some type of media.

IP stands for ‘Internet Protocol’ and is made of numbers and periods. It is the

135.46.52.2. In binary this is 10000111.00101110.00110100.00000010. Again, we are looking at one of the Interfaces, so we take the 22 MSB’s, which

For the second half of this assignment I will set up a network LAN for 145 host with an allowance for 50% growth over the next two years. When I do the math the number that I came up with is 281 address spaces needed for this company. To get 218, multiply the original 145 hosts by .50, which is equal to 72.5. Then add the 72.5 to the original 145 and the result is 217.5 and I rounded up to 218. So I will need at least 218 host addresses on my LAN. I now know that from the number of addresses needed I will be in the C Class of Classful networks, because there are 218 network addresses needed and Class C networks will allow up to 256 addresses per network. From the start I would break this down into at least five or more networks depending on how the company is divided. A company with this many host computers will have at least four or more divisions (IT, Administrations, Accounting, and Human Resources), and each division will need its own network. In order to get my five networks I will have to make room for eight networks, because the next lowest number for networks is 4. Remembering that I must use the n-2 notation for networks the number 8-2 = 6 which covers my 4 networks needed. The subnet mask for this will be 255.255.255.224 because 128 + 64 +32 = 224. The CIDR notation is /27 because of the bit value. Now that I have this information I know that my subnet mask is 255.255.255.224/27. The range of my four networks are as follows:

If we take the 172.16.0.0 range, that is /12. So that means that the network mask is 255.240.0.0. If we take 256-240 = 16 we get the block size which is 16. So that means that the range is from 172.16.0.0 to 172.31.255.255 because 172.32.0.0 is the next block and would be a public IP.

It creates a VPC with a /16 IPv4 CIDR block. It is a network with 65,536 private

Each school has four labs that require 31 connections. There needs to be 3 runs of cabling to the 30 computers on the Curriculum network and 1 run of cable to terminate at the instructor’s computer on the Administrator network.

5. Administration departments spread over another 10 buildings. LAN IP’s: Building 1 (128.100.17.x), Building 2 (128.100.18.x), Building 3 (128.100.19.x), Building 4 (128.100.20.x), Building 5 (128.100.21.x), Building 6 (128.100.22.x), Building 7 (128.100.23.x), Building 8 (128.100.24.x), Building 9 (128.100.25.x), and Building 10 (128.100.26.x). Router IP’s will be respectively as follows: (128.100.254.11), (128.100.254.12), (128.100.254.13), (128.100.254.14), (128.100.254.15), (128.100.254.16), (128.100.254.17), (128.100.254.18),

1. Drawings showing a map of cable runs and placement of wiring rooms for networking devices

What is IPv4? IPv4 is a 32-bit address used for communication between nodes using the TCP/IP protocol. The IPv4 address is broken into 4 octets each 8 bits long in binary and are broken into 5 different classes. Class A addresses start out where the first octet of the IP address ranged from 1-127 where 10 is reserved from private IP addresses. Class B addresses start out with 128 - 191 and has the 172.16.x.x to 172.31.x.x reserved from private IP addresses. Next is class C addresses that range from 192 - 223 in the first octet where 192.168.x.x is reserved from private IP addresses. Class D addresses range from 224 -239 in the first octet and are reserved from multicasting network traffic. Finally we have class E that range from 240 - 255 in the first octet and is reserved for experimental purposes ("IPv4," 2016).

For our network design we propose using 200 LAN segments each supporting up to 100 hosts. While 7 host bits or a /25 subnet mask would meet this requirement, it is probably neater in terms of administration