IMF: Evaporative Cooling and Molecular Modeling
ChemInquiry 5
Experiment Completed on Tuesday, October 21, 2014
Report turned in on Tuesday, November 3, 2014
Author: Katyna Omidfar-Tran
Partner: Jesus Palomo
Data Analysis Questions
1. Molecular Series I, II, and III all have London Dispersion forces, Dipole-Dipole moment forces, and Hydrogen Bonding forces.
2. Molecular Series IV all have London Dispersion forces only
3. In Molecular Series I (Straight-Chain Alcohols): As you go through the group from methanol ethanol 1-propanol 1-butanol:
A. The IMFs that are changing in Molecular Series I are London Dispersion forces.
B. Claim: As we go from methanol ethanol 1-propanol 1-butanol the dispersion forces increase.
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The more molecules that are able to escape into the vapor, the greater the decrease in temperature due to evaporative cooling. Thus, a larger negative ΔT corresponds to a substance in which the IMFs are weak.
A greater number of electrons correspond to a great polarizability of a molecule. Greater polarizability leads to greater dispersion forces. Thus, as molar mass increases, the number of electrons increase, which increases the polarizability of the molecule and hence the strength of the dispersion forces of the substance.
4. In Molecular Series II (Branched-Chain Alcohols): As you go through the group from 1-butanol sec-butanol 1-ter-butanol:
A. The dipole moments, surface area (shape), steric hindrances, and change in temperature (degree of evaporative cooling) affect IMF strength and are changing from one molecule to the next.
B. Claim: As we go from 1-butanol sec-butanol 1-ter-butanol the dipole moments and the surface areas decrease. As we go from 1-butanol sec-butanol 1-ter-butanol the steric hindrance increases. As we go from 1-butanol sec-butanol 1-ter-butanol the ΔT (degree of evaporative cooling) decreases. As we go from 1-butanol sec-butanol 1-ter-butanol the strength of the IMFs decrease.
C. Evidence: As can be seen in Table 2 on page 2A of the attached Appendix, the Spartan molecular modeling data shows surface area decreases in the
To make useful and effective cocktails, each individual fragment should have least structural similarity. As a result, the fragment fits substrate structure can be distinguished without confusing by structure analogues. Fragment 1/4, 2/6 and 3/5 are structural analogue pairs hence need to be separated. Therefore, grouping fragment 1/2/3 together and 4/5/6 together could be a choice for making cocktails with three fragments.
6. Challenge yourself: Other than space, what might be another density-dependent limiting factor? Explain. A contagious disease would be a density-dependent limiting factor.
3. Test the effect of a magnet on each substance by passing the magnet under
As a result of the water molecule bond, each (hydrogen; oxygen) has a slightly negative charge and each (hydrogen; oxygen) has a slightly positive charge.
There are four main types of intermolecular forces, the strongest force, first place, is ionic bonds, second place hydrogen bond interactions, third place dipole interactions, last place London dispersion/ Van der Waals interactions. Ionic forces occur when a complete transfer of electrons takes place when one interacting atom is much more electronegative than the other, causing atoms and molecules to take on charges. Hydrogen bonding occurs when a hydrogen atom is bonded to a very electro negative atom, specifically a nitrogen, oxygen or, fluorine atom.
8-4: Name the three-dimensional shape of this molecule. _double strand coiled into a double helix__
Methanol, ethanol, 1-propanol, and 1-butanol are alcohols that contain both London-dispersion forces and hydrogen bonds. Hydrogen
Note: Your prelab/lab report is to be done in your carbon copy lab notebook (sold in FIU bookstore)
These results can be attributed to the intermolecular forces holding
The main objective of this experiment is to differentiate between a physical change and a chemical change.
alcohol, making it either primary (1° ), secondary (2° ), or tertiary (3° ). If the OH is bonded to only one other carbon, it is a primary alcohol (eg. 1-butanol); if bonded to two other carbons, it is a secondary alcohol (eg. 2-butanol); if bonded to three other carbons, it is a tertiary alcohol (eg. 2-methyl-2-propanol). Due to the placement of the hydroxyl functional group in each of the degrees of alcohol, the reactivity of each should be impacted. This means that all three
The rate that a substance crosses the plasma membrane depends of the its surface area.
Conclusion: The result supports the hypothesis, that as the mass increases so will the force as there is a general trend that shows when mass is increased so is the force.
This scientific paper investigates my hypothesis that "Higher molecular weight produce faster diffusion". Diffusion is a process of equalization which involves movement of molecules from an area of high concentration to an area of low concentration (Biology 101.1). As Thomas Graham (1831-1833) found out on his study that gases of different nature diffuse with each other, it is a challenge as to how true it
over the volume of the structure, an increase in the temperature which lead to the atoms having higher